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Inversion Puzzle
The 2019 Stack Overflow Developer Survey Results Are InWhat is the cipher behind this circular cyphertext?A well balanced puzzle: Logic puzzle(s) in visual disguiseLepidopterology needed!Capture The StonesFind the number code in the pictureHow should the hexagon be coloured?The Alien grid of picturesA-maze-ing Navigation4x4 Sliding Puzzle with a twistASCII art troubles
$begingroup$
You can describe your inversions however you like. I think an ordered grid from the center (n,m) is easy to understand (doesn't matter where to start due to radial symmetry), or an image
visual
asked 1 hour ago
Artem LuginArtem Lugin
736
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
You can describe your inversions however you like. I think an ordered grid from the center (n,m) is easy to understand (doesn't matter where to start due to radial symmetry), or an image
visual
asked 1 hour ago
Artem LuginArtem Lugin
736
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
$endgroup$
– noedne
40 mins ago
$begingroup$
Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
$endgroup$
– Artem Lugin
37 mins ago
add a comment |
$begingroup$
You can describe your inversions however you like. I think an ordered grid from the center (n,m) is easy to understand (doesn't matter where to start due to radial symmetry), or an image
visual
asked 1 hour ago
Artem LuginArtem Lugin
736
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
You can describe your inversions however you like. I think an ordered grid from the center (n,m) is easy to understand (doesn't matter where to start due to radial symmetry), or an image
visual
visual
asked 1 hour ago
Artem LuginArtem Lugin
736
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
Artem LuginArtem Lugin
736
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
Artem LuginArtem Lugin
736
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
Artem LuginArtem Lugin
736
asked 1 hour ago
Artem LuginArtem Lugin
736
736
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
$endgroup$
– noedne
40 mins ago
$begingroup$
Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
$endgroup$
– Artem Lugin
37 mins ago
add a comment |
$begingroup$
Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
$endgroup$
– noedne
40 mins ago
$begingroup$
Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
$endgroup$
– Artem Lugin
37 mins ago
$begingroup$
Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
$endgroup$
– noedne
40 mins ago
$begingroup$
Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
$endgroup$
– noedne
40 mins ago
$begingroup$
Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
$endgroup$
– Artem Lugin
37 mins ago
$begingroup$
Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
$endgroup$
– Artem Lugin
37 mins ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
My solution is
2 moves to make the inversions - was very slow to make this horrible graphic!
answered 26 mins ago
Weather VaneWeather Vane
2,137112
$endgroup$
add a comment |
$begingroup$
EDIT: I found an even better
2 inversion solution:
And of course, this is the optimal solution because you obviously can’t get to the end with only one inversion
Original answer: I can do it in
6 inversions
by
inverting a set of 4 non-adjacent big triangles (the ones that go BWBW or WBWB), then inverting the 2 black rings that result from that. (Will update with a visual later)
edited 34 secs ago
Adam
333120
answered 50 mins ago
PiIsNot3PiIsNot3
2,135329
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
My solution is
2 moves to make the inversions - was very slow to make this horrible graphic!
answered 26 mins ago
Weather VaneWeather Vane
2,137112
$endgroup$
add a comment |
$begingroup$
My solution is
2 moves to make the inversions - was very slow to make this horrible graphic!
answered 26 mins ago
Weather VaneWeather Vane
2,137112
$endgroup$
add a comment |
$begingroup$
My solution is
2 moves to make the inversions - was very slow to make this horrible graphic!
answered 26 mins ago
Weather VaneWeather Vane
2,137112
$endgroup$
My solution is
2 moves to make the inversions - was very slow to make this horrible graphic!
answered 26 mins ago
Weather VaneWeather Vane
2,137112
edited 8 mins ago
answered 26 mins ago
Weather VaneWeather Vane
2,137112
answered 26 mins ago
Weather VaneWeather Vane
2,137112
answered 26 mins ago
Weather VaneWeather Vane
2,137112
2,137112
add a comment |
add a comment |
$begingroup$
EDIT: I found an even better
2 inversion solution:
And of course, this is the optimal solution because you obviously can’t get to the end with only one inversion
Original answer: I can do it in
6 inversions
by
inverting a set of 4 non-adjacent big triangles (the ones that go BWBW or WBWB), then inverting the 2 black rings that result from that. (Will update with a visual later)
edited 34 secs ago
Adam
333120
answered 50 mins ago
PiIsNot3PiIsNot3
2,135329
$endgroup$
add a comment |
$begingroup$
EDIT: I found an even better
2 inversion solution:
And of course, this is the optimal solution because you obviously can’t get to the end with only one inversion
Original answer: I can do it in
6 inversions
by
inverting a set of 4 non-adjacent big triangles (the ones that go BWBW or WBWB), then inverting the 2 black rings that result from that. (Will update with a visual later)
edited 34 secs ago
Adam
333120
answered 50 mins ago
PiIsNot3PiIsNot3
2,135329
$endgroup$
add a comment |
$begingroup$
EDIT: I found an even better
2 inversion solution:
And of course, this is the optimal solution because you obviously can’t get to the end with only one inversion
Original answer: I can do it in
6 inversions
by
inverting a set of 4 non-adjacent big triangles (the ones that go BWBW or WBWB), then inverting the 2 black rings that result from that. (Will update with a visual later)
edited 34 secs ago
Adam
333120
answered 50 mins ago
PiIsNot3PiIsNot3
2,135329
$endgroup$
EDIT: I found an even better
2 inversion solution:
And of course, this is the optimal solution because you obviously can’t get to the end with only one inversion
Original answer: I can do it in
6 inversions
by
inverting a set of 4 non-adjacent big triangles (the ones that go BWBW or WBWB), then inverting the 2 black rings that result from that. (Will update with a visual later)
edited 34 secs ago
Adam
333120
answered 50 mins ago
PiIsNot3PiIsNot3
2,135329
edited 34 secs ago
Adam
333120
edited 34 secs ago
Adam
333120
edited 34 secs ago
Adam
333120
333120
answered 50 mins ago
PiIsNot3PiIsNot3
2,135329
answered 50 mins ago
PiIsNot3PiIsNot3
2,135329
answered 50 mins ago
PiIsNot3PiIsNot3
2,135329
2,135329
add a comment |
add a comment |
Artem Lugin is a new contributor. Be nice, and check out our Code of Conduct.
Artem Lugin is a new contributor. Be nice, and check out our Code of Conduct.
Artem Lugin is a new contributor. Be nice, and check out our Code of Conduct.
Artem Lugin is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
$endgroup$
– noedne
40 mins ago
$begingroup$
Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
$endgroup$
– Artem Lugin
37 mins ago