draw a pulley system Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: placing a line (transformed into a sinusoidal shape) parallel to an edge connecting nodesAbsolutely position arrow headHow to define the default vertical distance between nodes?Computing the rectangle encompassing a node and a pointUse of overlay command in a graphTikZ: Drawing an arc from an intersection to an intersectionGetting the proper shading within a circle - a bit of litographyAdjusting edge alignment and positioning of fitted nodeRelative transparency in TikZ?Line up nested tikz enviroments or how to get rid of them
Noise in Eigenvalues plot
How do I find my Spellcasting Ability for my D&D character?
Why does BitLocker not use RSA?
Does the universe have a fixed centre of mass?
Why is there so little support for joining EFTA in the British parliament?
Flight departed from the gate 5 min before scheduled departure time. Refund options
Do i imagine the linear (straight line) homotopy in a correct way?
Found this skink in my tomato plant bucket. Is he trapped? Or could he leave if he wanted?
Is there a verb for listening stealthily?
How do you write "wild blueberries flavored"?
One-one communication
Inverse square law not accurate for non-point masses?
Besides transaction validation, are there any other uses of the Script language in Bitcoin
French equivalents of おしゃれは足元から (Every good outfit starts with the shoes)
Why do the Z-fighters hide their power?
What does 丫 mean? 丫是什么意思？
Was the pager message from Nick Fury to Captain Marvel unnecessary?
Can gravitational waves pass through a black hole?
How do you cope with tons of web fonts when copying and pasting from web pages?
Why not use the yoke to control yaw, as well as pitch and roll?
Where and when has Thucydides been studied?
3D Masyu - A Die
Where did Ptolemy compare the Earth to the distance of fixed stars?
Why are two-digit numbers in Jonathan Swift's "Gulliver's Travels" (1726) written in "German style"?
draw a pulley system
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: placing a line (transformed into a sinusoidal shape) parallel to an edge connecting nodesAbsolutely position arrow headHow to define the default vertical distance between nodes?Computing the rectangle encompassing a node and a pointUse of overlay command in a graphTikZ: Drawing an arc from an intersection to an intersectionGetting the proper shading within a circle - a bit of litographyAdjusting edge alignment and positioning of fitted nodeRelative transparency in TikZ?Line up nested tikz enviroments or how to get rid of them
1
I need to draw a pulley system as in the figure. Can you help?
begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
draw(-3,0)--(3,0);
draw(-2.5,0)--(-2.5,-2.4);
draw(2.5,0)--(2.5,-1);
draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);
draw[fill=white] (0,-3) circle (.153);
draw
(2.5,-1) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (0,-2.75) coordinate (c) node[above right]
pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
angle=a--b--c;
draw
(0,-2.75) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (-2.5,-2.4) coordinate (c) node[above right]
pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
angle=a--b--c;
draw[dashed] (0,-3)--(0,-1);
draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);
draw[fill=white] (0,-3) circle (.153);
endtikzpicture
tikz-pgf
asked 2 hours ago
ThumboltThumbolt
1,516822
add a comment |
1
I need to draw a pulley system as in the figure. Can you help?
begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
draw(-3,0)--(3,0);
draw(-2.5,0)--(-2.5,-2.4);
draw(2.5,0)--(2.5,-1);
draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);
draw[fill=white] (0,-3) circle (.153);
draw
(2.5,-1) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (0,-2.75) coordinate (c) node[above right]
pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
angle=a--b--c;
draw
(0,-2.75) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (-2.5,-2.4) coordinate (c) node[above right]
pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
angle=a--b--c;
draw[dashed] (0,-3)--(0,-1);
draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);
draw[fill=white] (0,-3) circle (.153);
endtikzpicture
tikz-pgf
asked 2 hours ago
ThumboltThumbolt
1,516822
add a comment |
1
1
1
0
I need to draw a pulley system as in the figure. Can you help?
begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
draw(-3,0)--(3,0);
draw(-2.5,0)--(-2.5,-2.4);
draw(2.5,0)--(2.5,-1);
draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);
draw[fill=white] (0,-3) circle (.153);
draw
(2.5,-1) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (0,-2.75) coordinate (c) node[above right]
pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
angle=a--b--c;
draw
(0,-2.75) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (-2.5,-2.4) coordinate (c) node[above right]
pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
angle=a--b--c;
draw[dashed] (0,-3)--(0,-1);
draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);
draw[fill=white] (0,-3) circle (.153);
endtikzpicture
tikz-pgf
asked 2 hours ago
ThumboltThumbolt
1,516822
I need to draw a pulley system as in the figure. Can you help?
begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
draw(-3,0)--(3,0);
draw(-2.5,0)--(-2.5,-2.4);
draw(2.5,0)--(2.5,-1);
draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);
draw[fill=white] (0,-3) circle (.153);
draw
(2.5,-1) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (0,-2.75) coordinate (c) node[above right]
pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
angle=a--b--c;
draw
(0,-2.75) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (-2.5,-2.4) coordinate (c) node[above right]
pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
angle=a--b--c;
draw[dashed] (0,-3)--(0,-1);
draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);
draw[fill=white] (0,-3) circle (.153);
endtikzpicture
tikz-pgf
tikz-pgf
asked 2 hours ago
ThumboltThumbolt
1,516822
asked 2 hours ago
ThumboltThumbolt
1,516822
edited 2 hours ago
Thumbolt
asked 2 hours ago
ThumboltThumbolt
1,516822
asked 2 hours ago
ThumboltThumbolt
1,516822
asked 2 hours ago
ThumboltThumbolt
1,516822
1,516822
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
3
In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypatterns,calc,angles,quotes
begindocument
begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
beginscope[thick]
draw(-3,0)--(3,0);
path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
(2.5,-1) node[circle,draw,inner sep=.3cm] (R)
(0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
draw[dashed] (M) -- (0,-1)coordinate (M1);
draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
endscope
path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
endtikzpicture
enddocument
answered 2 hours ago
marmotmarmot
120k6156292
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "85"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f485982%2fdraw-a-pulley-system%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypatterns,calc,angles,quotes
begindocument
begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
beginscope[thick]
draw(-3,0)--(3,0);
path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
(2.5,-1) node[circle,draw,inner sep=.3cm] (R)
(0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
draw[dashed] (M) -- (0,-1)coordinate (M1);
draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
endscope
path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
endtikzpicture
enddocument
answered 2 hours ago
marmotmarmot
120k6156292
add a comment |
3
In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypatterns,calc,angles,quotes
begindocument
begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
beginscope[thick]
draw(-3,0)--(3,0);
path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
(2.5,-1) node[circle,draw,inner sep=.3cm] (R)
(0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
draw[dashed] (M) -- (0,-1)coordinate (M1);
draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
endscope
path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
endtikzpicture
enddocument
answered 2 hours ago
marmotmarmot
120k6156292
add a comment |
3
3
3
In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypatterns,calc,angles,quotes
begindocument
begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
beginscope[thick]
draw(-3,0)--(3,0);
path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
(2.5,-1) node[circle,draw,inner sep=.3cm] (R)
(0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
draw[dashed] (M) -- (0,-1)coordinate (M1);
draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
endscope
path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
endtikzpicture
enddocument
answered 2 hours ago
marmotmarmot
120k6156292
In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypatterns,calc,angles,quotes
begindocument
begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
beginscope[thick]
draw(-3,0)--(3,0);
path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
(2.5,-1) node[circle,draw,inner sep=.3cm] (R)
(0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
draw[dashed] (M) -- (0,-1)coordinate (M1);
draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
endscope
path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
endtikzpicture
enddocument
answered 2 hours ago
marmotmarmot
120k6156292
edited 2 hours ago
answered 2 hours ago
marmotmarmot
120k6156292
answered 2 hours ago
marmotmarmot
120k6156292
answered 2 hours ago
marmotmarmot
120k6156292
120k6156292
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to TeX - LaTeX Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f485982%2fdraw-a-pulley-system%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
