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Im stuck and having trouble with ¬P ∨ Q Prove: P → Q



Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Help with simple deductive proofInvalid arguments with true premises and true conclusionWhat are the important effects of studying logic?If F is a sufficient condition for G, is lacking G a sufficient condition for lacking F?How to prove (P ∧ ¬Q) ↔ ¬(P → Q)Prove (¬P ∨ Q) ↔ (P → Q)How to prove the tautology ¬(P↔¬P) using Fitch?How do you prove B v A |- A v B?I have trouble understanding this fallacy: “If A, then B. Therefore if not-B, then not-A.”trouble with rules of inference practice problems










2















I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ¬P ∨ Q?










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Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • 2





    Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

    – Frank Hubeny
    4 hours ago















2















I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ¬P ∨ Q?










share|improve this question







New contributor




Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.















  • 2





    Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

    – Frank Hubeny
    4 hours ago













2












2








2








I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ¬P ∨ Q?










share|improve this question







New contributor




Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ¬P ∨ Q?







logic






share|improve this question







New contributor




Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






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Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 5 hours ago









Hamish DochertyHamish Docherty

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111




New contributor




Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor





Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 2





    Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

    – Frank Hubeny
    4 hours ago












  • 2





    Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

    – Frank Hubeny
    4 hours ago







2




2





Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

– Frank Hubeny
4 hours ago





Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

– Frank Hubeny
4 hours ago










1 Answer
1






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3














In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.



This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ¬P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).



Now to prove Q from an assumption of P and the premise of ¬P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.






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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3














    In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
    Proof.



    This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ¬P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).



    Now to prove Q from an assumption of P and the premise of ¬P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.






    share|improve this answer



























      3














      In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
      Proof.



      This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ¬P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).



      Now to prove Q from an assumption of P and the premise of ¬P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.






      share|improve this answer

























        3












        3








        3







        In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
        Proof.



        This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ¬P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).



        Now to prove Q from an assumption of P and the premise of ¬P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.






        share|improve this answer













        In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
        Proof.



        This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ¬P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).



        Now to prove Q from an assumption of P and the premise of ¬P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 1 hour ago









        Graham KempGraham Kemp

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