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How to define command with 2 optional params such that it calls another command (accepting 1 optional param) to which it passes one of those 2 params?

Conditionals in newcommandPass key option inside a macro to a TikZ drawing commandWrite a command that dynamically calls the argument of another commandHow do you define one macro with arguments inside anothercustom hatching pattern : arbitrary direction of hatchingHow to define such a command with an optional argument in my class?How to define a command that defines another command?How to define a newcommand that expands into another newcommandDefine latex command in which argument is part of another commandHow to define a command with two optional arguments?

1

documentclassstandalone

usepackagetikz

newcountermyC

newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
 thenumexpr(valuemyC-0)

% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
 % I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
 path[draw=red](myN.#1 west)--(myN.#1 east);
 

begindocument
 begintikzpicture
 path node[draw,/utils/exec=stepcountermyC](1)one;
 myL
 path node[draw,/utils/exec=stepcountermyC](2)two;
 myL
 endtikzpicture
enddocument

---

EDIT (for @Red-Cloud):

I can do

newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);

but as soon as myN is rewritten to allow for an optional argument, it doesn't work

newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);

Why is that? I need myN to accept an optional arg.

macros

share|improve this question

edited 26 mins ago

bp2017

asked 4 hours ago

bp2017bp2017

879114

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'm not quite understanding. I see how myL has one optional parameter, and can be called by myL or myL[south]. How does the other optional parameter fit in? How do you intend to call myL?
  
  – Teepeemm
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  path[draw=red](myN.#1 west)--(myN.#1 east); makes no sense here because it doesn't use the second optional parameter #2 (default north)
  
  – Red-Cloud
  1 hour ago
  

  
  
  
  

add a comment | 

1

documentclassstandalone

usepackagetikz

newcountermyC

newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
 thenumexpr(valuemyC-0)

% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
 % I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
 path[draw=red](myN.#1 west)--(myN.#1 east);
 

begindocument
 begintikzpicture
 path node[draw,/utils/exec=stepcountermyC](1)one;
 myL
 path node[draw,/utils/exec=stepcountermyC](2)two;
 myL
 endtikzpicture
enddocument

---

EDIT (for @Red-Cloud):

I can do

newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);

but as soon as myN is rewritten to allow for an optional argument, it doesn't work

newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);

Why is that? I need myN to accept an optional arg.

macros

share|improve this question

edited 26 mins ago

bp2017

asked 4 hours ago

bp2017bp2017

879114

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'm not quite understanding. I see how myL has one optional parameter, and can be called by myL or myL[south]. How does the other optional parameter fit in? How do you intend to call myL?
  
  – Teepeemm
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  path[draw=red](myN.#1 west)--(myN.#1 east); makes no sense here because it doesn't use the second optional parameter #2 (default north)
  
  – Red-Cloud
  1 hour ago
  

  
  
  
  

add a comment | 

documentclassstandalone

usepackagetikz

newcountermyC

newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
 thenumexpr(valuemyC-0)

% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
 % I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
 path[draw=red](myN.#1 west)--(myN.#1 east);
 

begindocument
 begintikzpicture
 path node[draw,/utils/exec=stepcountermyC](1)one;
 myL
 path node[draw,/utils/exec=stepcountermyC](2)two;
 myL
 endtikzpicture
enddocument

---

EDIT (for @Red-Cloud):

I can do

newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);

but as soon as myN is rewritten to allow for an optional argument, it doesn't work

newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);

Why is that? I need myN to accept an optional arg.

macros

share|improve this question

edited 26 mins ago

bp2017

asked 4 hours ago

bp2017bp2017

879114

documentclassstandalone

usepackagetikz

newcountermyC

newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
 thenumexpr(valuemyC-0)

% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
 % I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
 path[draw=red](myN.#1 west)--(myN.#1 east);
 

begindocument
 begintikzpicture
 path node[draw,/utils/exec=stepcountermyC](1)one;
 myL
 path node[draw,/utils/exec=stepcountermyC](2)two;
 myL
 endtikzpicture
enddocument

newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);

newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);

share|improve this question

edited 26 mins ago

bp2017

asked 4 hours ago

bp2017bp2017

879114

share|improve this question

edited 26 mins ago

bp2017

asked 4 hours ago

bp2017bp2017

879114

asked 4 hours ago

bp2017bp2017

879114

asked 4 hours ago

bp2017bp2017

879114

2 Answers
2

active

oldest

votes

1

newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax

usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
 path[draw=red](myN.#1 west)--(myN.#1 east);%

But makes no real sense in your example

share|improve this answer

answered 1 hour ago

Red-CloudRed-Cloud

1,61911

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please check EDIT part (on the bottom) in my question.
  
  – bp2017
  26 mins ago
  

  
  
  
  

add a comment | 

1

It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:

 documentclass[tikz, border=5mm]standalone
 usepackagexparse

 newcountermyC
 NewDocumentCommandmyLOnorth O0%
 defmyCthenumexpr(themyC-#2)
 path[draw=red](myC.#1 west)--(myC.#1 east);
 

 begindocument
 begintikzpicture[mystep/.code=stepcountermyC]
 path node[draw,mystep](1)at (themyC,0)one;
 myL
 path node[draw,mystep](2)at (themyC,0)two;
 myL
 endtikzpicture
 enddocument

Here is the output:

Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.

share|improve this answer

answered 1 hour ago

AndrewAndrew

32.5k34684

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I need newcommand which you removed. I also use it for other means.
  
  – bp2017
  19 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @bp2017 Just use newcommandmyN[1][0]thenumexpr(valuemyC-#1). I think that if you try to use myN inside your myL command then you will have expansion issues, which is part of why I did this the way that I did.
  
  – Andrew
  5 mins ago
  
  

  
  
  
  

add a comment | 

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1

newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax

usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
 path[draw=red](myN.#1 west)--(myN.#1 east);%

But makes no real sense in your example

share|improve this answer

answered 1 hour ago

Red-CloudRed-Cloud

1,61911

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please check EDIT part (on the bottom) in my question.
  
  – bp2017
  26 mins ago
  

  
  
  
  

add a comment | 

1

newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax

usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
 path[draw=red](myN.#1 west)--(myN.#1 east);%

But makes no real sense in your example

share|improve this answer

answered 1 hour ago

Red-CloudRed-Cloud

1,61911

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please check EDIT part (on the bottom) in my question.
  
  – bp2017
  26 mins ago
  

  
  
  
  

add a comment | 

newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax

usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
 path[draw=red](myN.#1 west)--(myN.#1 east);%

But makes no real sense in your example

share|improve this answer

answered 1 hour ago

Red-CloudRed-Cloud

1,61911

newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax

usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
 path[draw=red](myN.#1 west)--(myN.#1 east);%

share|improve this answer

answered 1 hour ago

Red-CloudRed-Cloud

1,61911

answered 1 hour ago

Red-CloudRed-Cloud

1,61911

answered 1 hour ago

Red-CloudRed-Cloud

1,61911

1

It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:

 documentclass[tikz, border=5mm]standalone
 usepackagexparse

 newcountermyC
 NewDocumentCommandmyLOnorth O0%
 defmyCthenumexpr(themyC-#2)
 path[draw=red](myC.#1 west)--(myC.#1 east);
 

 begindocument
 begintikzpicture[mystep/.code=stepcountermyC]
 path node[draw,mystep](1)at (themyC,0)one;
 myL
 path node[draw,mystep](2)at (themyC,0)two;
 myL
 endtikzpicture
 enddocument

Here is the output:

Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.

share|improve this answer

answered 1 hour ago

AndrewAndrew

32.5k34684

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I need newcommand which you removed. I also use it for other means.
  
  – bp2017
  19 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @bp2017 Just use newcommandmyN[1][0]thenumexpr(valuemyC-#1). I think that if you try to use myN inside your myL command then you will have expansion issues, which is part of why I did this the way that I did.
  
  – Andrew
  5 mins ago
  
  

  
  
  
  

add a comment | 

1

It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:

 documentclass[tikz, border=5mm]standalone
 usepackagexparse

 newcountermyC
 NewDocumentCommandmyLOnorth O0%
 defmyCthenumexpr(themyC-#2)
 path[draw=red](myC.#1 west)--(myC.#1 east);
 

 begindocument
 begintikzpicture[mystep/.code=stepcountermyC]
 path node[draw,mystep](1)at (themyC,0)one;
 myL
 path node[draw,mystep](2)at (themyC,0)two;
 myL
 endtikzpicture
 enddocument

Here is the output:

Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.

share|improve this answer

answered 1 hour ago

AndrewAndrew

32.5k34684

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I need newcommand which you removed. I also use it for other means.
  
  – bp2017
  19 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @bp2017 Just use newcommandmyN[1][0]thenumexpr(valuemyC-#1). I think that if you try to use myN inside your myL command then you will have expansion issues, which is part of why I did this the way that I did.
  
  – Andrew
  5 mins ago
  
  

  
  
  
  

add a comment | 

It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:

 documentclass[tikz, border=5mm]standalone
 usepackagexparse

 newcountermyC
 NewDocumentCommandmyLOnorth O0%
 defmyCthenumexpr(themyC-#2)
 path[draw=red](myC.#1 west)--(myC.#1 east);
 

 begindocument
 begintikzpicture[mystep/.code=stepcountermyC]
 path node[draw,mystep](1)at (themyC,0)one;
 myL
 path node[draw,mystep](2)at (themyC,0)two;
 myL
 endtikzpicture
 enddocument

Here is the output:

Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.

share|improve this answer

answered 1 hour ago

AndrewAndrew

32.5k34684

 documentclass[tikz, border=5mm]standalone
 usepackagexparse

 newcountermyC
 NewDocumentCommandmyLOnorth O0%
 defmyCthenumexpr(themyC-#2)
 path[draw=red](myC.#1 west)--(myC.#1 east);
 

 begindocument
 begintikzpicture[mystep/.code=stepcountermyC]
 path node[draw,mystep](1)at (themyC,0)one;
 myL
 path node[draw,mystep](2)at (themyC,0)two;
 myL
 endtikzpicture
 enddocument

share|improve this answer

answered 1 hour ago

AndrewAndrew

32.5k34684

answered 1 hour ago

AndrewAndrew

32.5k34684

answered 1 hour ago

AndrewAndrew

32.5k34684