Is there some meaningful statistical data to justify keeping signed integer arithmetic overflow undefined?Detecting signed overflow in C/C++Why does integer overflow on x86 with GCC cause an infinite loop?Do C99 signed integer types defined in stdint.h exhibit well-defined behaviour in case of an overflow?Efficient unsigned-to-signed cast avoiding implementation-defined behaviorWhy is unsigned integer overflow defined behavior but signed integer overflow isn't?Signed integers' undefined behavior and Apple Secure Coding GuideDoes Visual C++ consider signed integer overflow undefined?Does integer overflow cause undefined behavior because of memory corruption?I'm having some difficulty understanding these comments about detecting integer overflowsSigned Integer value overflow in C++?
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Is there some meaningful statistical data to justify keeping signed integer arithmetic overflow undefined?
Detecting signed overflow in C/C++Why does integer overflow on x86 with GCC cause an infinite loop?Do C99 signed integer types defined in stdint.h exhibit well-defined behaviour in case of an overflow?Efficient unsigned-to-signed cast avoiding implementation-defined behaviorWhy is unsigned integer overflow defined behavior but signed integer overflow isn't?Signed integers' undefined behavior and Apple Secure Coding GuideDoes Visual C++ consider signed integer overflow undefined?Does integer overflow cause undefined behavior because of memory corruption?I'm having some difficulty understanding these comments about detecting integer overflowsSigned Integer value overflow in C++?
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The C Standard explicitly specifies signed integer overflow as having undefined behavior. Yet most CPUs implement signed arithmetics with defined semantics for overflow (except maybe for division overflow: x / 0
and INT_MIN / -1
).
Compilers writers have been taking advantage of the undefinedness of such overflows to add more aggressive optimisations that tend to break legacy code in very subtle ways. For example this code may have worked on older compilers but does not anymore on current versions of gcc
and clang
:
/* Tncrement a by a value in 0..255, clamp a to positive integers.
The code relies on 32-bit wrap-around, but the C Standard makes
signed integer overflow undefined behavior, so sum_max can now
return values less than a. There are Standard compliant ways to
implement this, but legacy code is what it is... */
int sum_max(int a, unsigned char b)
int res = a + b;
return (res >= a) ? res : INT_MAX;
Is there hard evidence that these optimisations are worthwhile? Are there comparative studies documenting the actual improvements on real life examples or even on classical benchmarks?
I came up with this question as I was watching this: C++Now 2018: John Regehr “Closing Keynote: Undefined Behavior and Compiler Optimizations”
I am tagging c and c++ as the problem is similar in both languages but the answers might be different.
c++ c language-lawyer signed integer-overflow
add a comment |
The C Standard explicitly specifies signed integer overflow as having undefined behavior. Yet most CPUs implement signed arithmetics with defined semantics for overflow (except maybe for division overflow: x / 0
and INT_MIN / -1
).
Compilers writers have been taking advantage of the undefinedness of such overflows to add more aggressive optimisations that tend to break legacy code in very subtle ways. For example this code may have worked on older compilers but does not anymore on current versions of gcc
and clang
:
/* Tncrement a by a value in 0..255, clamp a to positive integers.
The code relies on 32-bit wrap-around, but the C Standard makes
signed integer overflow undefined behavior, so sum_max can now
return values less than a. There are Standard compliant ways to
implement this, but legacy code is what it is... */
int sum_max(int a, unsigned char b)
int res = a + b;
return (res >= a) ? res : INT_MAX;
Is there hard evidence that these optimisations are worthwhile? Are there comparative studies documenting the actual improvements on real life examples or even on classical benchmarks?
I came up with this question as I was watching this: C++Now 2018: John Regehr “Closing Keynote: Undefined Behavior and Compiler Optimizations”
I am tagging c and c++ as the problem is similar in both languages but the answers might be different.
c++ c language-lawyer signed integer-overflow
Comments are not for extended discussion; this conversation has been moved to chat.
– Samuel Liew♦
3 hours ago
1
The reason C says signed integer overflow is undefined is that some CPUs use "2's complement", some use "1's compliment", some use "sign and magnitude"; and for all the cases overflow could cause anything (e.g. CPUs like MIPS have "trap on overflow"). In other words it's about portability and not optimisation.
– Brendan
2 hours ago
Exactly. The only 'meaningful statistic' anybody needs is that ones-complement and sign-magnitude computers exist.
– user207421
1 hour ago
add a comment |
The C Standard explicitly specifies signed integer overflow as having undefined behavior. Yet most CPUs implement signed arithmetics with defined semantics for overflow (except maybe for division overflow: x / 0
and INT_MIN / -1
).
Compilers writers have been taking advantage of the undefinedness of such overflows to add more aggressive optimisations that tend to break legacy code in very subtle ways. For example this code may have worked on older compilers but does not anymore on current versions of gcc
and clang
:
/* Tncrement a by a value in 0..255, clamp a to positive integers.
The code relies on 32-bit wrap-around, but the C Standard makes
signed integer overflow undefined behavior, so sum_max can now
return values less than a. There are Standard compliant ways to
implement this, but legacy code is what it is... */
int sum_max(int a, unsigned char b)
int res = a + b;
return (res >= a) ? res : INT_MAX;
Is there hard evidence that these optimisations are worthwhile? Are there comparative studies documenting the actual improvements on real life examples or even on classical benchmarks?
I came up with this question as I was watching this: C++Now 2018: John Regehr “Closing Keynote: Undefined Behavior and Compiler Optimizations”
I am tagging c and c++ as the problem is similar in both languages but the answers might be different.
c++ c language-lawyer signed integer-overflow
The C Standard explicitly specifies signed integer overflow as having undefined behavior. Yet most CPUs implement signed arithmetics with defined semantics for overflow (except maybe for division overflow: x / 0
and INT_MIN / -1
).
Compilers writers have been taking advantage of the undefinedness of such overflows to add more aggressive optimisations that tend to break legacy code in very subtle ways. For example this code may have worked on older compilers but does not anymore on current versions of gcc
and clang
:
/* Tncrement a by a value in 0..255, clamp a to positive integers.
The code relies on 32-bit wrap-around, but the C Standard makes
signed integer overflow undefined behavior, so sum_max can now
return values less than a. There are Standard compliant ways to
implement this, but legacy code is what it is... */
int sum_max(int a, unsigned char b)
int res = a + b;
return (res >= a) ? res : INT_MAX;
Is there hard evidence that these optimisations are worthwhile? Are there comparative studies documenting the actual improvements on real life examples or even on classical benchmarks?
I came up with this question as I was watching this: C++Now 2018: John Regehr “Closing Keynote: Undefined Behavior and Compiler Optimizations”
I am tagging c and c++ as the problem is similar in both languages but the answers might be different.
c++ c language-lawyer signed integer-overflow
c++ c language-lawyer signed integer-overflow
edited 7 hours ago
chqrlie
asked 7 hours ago
chqrliechqrlie
65.7k853111
65.7k853111
Comments are not for extended discussion; this conversation has been moved to chat.
– Samuel Liew♦
3 hours ago
1
The reason C says signed integer overflow is undefined is that some CPUs use "2's complement", some use "1's compliment", some use "sign and magnitude"; and for all the cases overflow could cause anything (e.g. CPUs like MIPS have "trap on overflow"). In other words it's about portability and not optimisation.
– Brendan
2 hours ago
Exactly. The only 'meaningful statistic' anybody needs is that ones-complement and sign-magnitude computers exist.
– user207421
1 hour ago
add a comment |
Comments are not for extended discussion; this conversation has been moved to chat.
– Samuel Liew♦
3 hours ago
1
The reason C says signed integer overflow is undefined is that some CPUs use "2's complement", some use "1's compliment", some use "sign and magnitude"; and for all the cases overflow could cause anything (e.g. CPUs like MIPS have "trap on overflow"). In other words it's about portability and not optimisation.
– Brendan
2 hours ago
Exactly. The only 'meaningful statistic' anybody needs is that ones-complement and sign-magnitude computers exist.
– user207421
1 hour ago
Comments are not for extended discussion; this conversation has been moved to chat.
– Samuel Liew♦
3 hours ago
Comments are not for extended discussion; this conversation has been moved to chat.
– Samuel Liew♦
3 hours ago
1
1
The reason C says signed integer overflow is undefined is that some CPUs use "2's complement", some use "1's compliment", some use "sign and magnitude"; and for all the cases overflow could cause anything (e.g. CPUs like MIPS have "trap on overflow"). In other words it's about portability and not optimisation.
– Brendan
2 hours ago
The reason C says signed integer overflow is undefined is that some CPUs use "2's complement", some use "1's compliment", some use "sign and magnitude"; and for all the cases overflow could cause anything (e.g. CPUs like MIPS have "trap on overflow"). In other words it's about portability and not optimisation.
– Brendan
2 hours ago
Exactly. The only 'meaningful statistic' anybody needs is that ones-complement and sign-magnitude computers exist.
– user207421
1 hour ago
Exactly. The only 'meaningful statistic' anybody needs is that ones-complement and sign-magnitude computers exist.
– user207421
1 hour ago
add a comment |
3 Answers
3
active
oldest
votes
Not quite an example of optimization, but one useful consequence of undefined behaviour is -ftrapv
command line switch of GCC/clang. It inserts code which crashes your program on integer overflow.
It won't work on unsigned integers, in accordance with the idea that unsigned overflow is intentional.
The Standard's wording on signed integer overflow ensures that people won't write overflowing code on purpose, so ftrapv
is a useful tool to discover unintentional overflow.
add a comment |
The answer is actually in your question:
Yet most CPUs implement signed arithmetics with defined semantics
I can't think of a CPU that you can buy today that does not use twos-compliment arithmetic for signed integers, but that wasn't always the case.
The C language was invented in 1972. Back then, IBM 7090 mainframes still existed. Not all computers were twos-compliment.
To have defined the language (and overflow behaviour) around 2s-compliment would have been prejudicial to code generation on machines that weren't.
Furthermore, as it has already been said, specifying that signed overflow is to be UB allows the compiler to produce better code, because it can discount code paths that result from signed overflow, assuming that this will never happen.
If I understand correctly that it's intended to clamp the sum of a and b to 0....INT_MAX without wraparound, I can think of two ways to write this function in a compliant way.
First, the inefficient general case that will work on all cpus:
int sum_max(int a, unsigned char b)
if (a > std::numeric_limits<int>::max() - b)
return std::numeric_limits<int>::max();
else
return a + b;
Second, the surprisingly efficient 2s-compliment specific way:
int sum_max2(int a, unsigned char b)
unsigned int buffer;
std::memcpy(&buffer, &a, sizeof(a));
buffer += b;
if (buffer > std::numeric_limits<int>::max())
buffer = std::numeric_limits<int>::max();
std::memcpy(&a, &buffer, sizeof(a));
return a;
Resulting assembler can be seen here: https://godbolt.org/z/F42IXV
add a comment |
I don't know about studies and statistics, but yes, there are definitely optimizations taking this into account that compilers actually do. And yes, they are very important (tldr loop vectorization for example).
Besides the compiler optimizations, there is another aspect to be taken into account. With UB you get C/C++ signed integers to behave arithmetically as you would expect mathematically. For instance x + 10 > x
holds true now, but would not on a wrap-around behavior.
I've found an excellent article How undefined signed overflow enables optimizations in GCC from Krister Walfridsson’s blog listing some optimizations that take signed overflow UB into account. The following examples are from it. I am adding c++ and assembly examples to them.
If the optimizations look too simple, uninteresting or unimpactful, remember that these optimization are just steps in a much much larger chain of optimizations. And the butterfly effect does happen as a seemingly unimportant optimization at an earlier step can trigger a much more impactful optimization at a later step.
If the examples look nonsensical (who would write x * 10 > 0
) keep in mind that you can very easily get to this kind of examples in C and C++ with constants, macros, templates. Besides the compiler can get to this kind of examples when applying transformations and optimizations in its IR.
Signed integer expression simplification
Eliminate multiplication in comparison with 0
(x * c) cmp 0 -> x cmp 0
bool foo(int x) return x * 10 > 0
foo(int):
test edi, edi
setg al
retEliminate division after multiplication
(x * c1) / c2 -> x * (c1 / c2) if c1 is divisible by c2
int foo(int x) return (x * 20) / 10;
foo(int):
lea eax, [rdi+rdi]
retEliminate negation
(-x) / (-y) -> x / y
int foo(int x, int y) return (-x) / (-y);
foo(int, int):
mov eax, edi
cdq
idiv esi
retSimplify comparisons that are always true or false
x + c < x -> false
x + c <= x -> false
x + c > x -> true
x + c >= x -> truebool foo(int x) return x + 10 >= x;
foo(int):
mov eax, 1
retEliminate negation in comparisons
(-x) cmp (-y) -> y cmp x
bool foo(int x, int y) return -x < -y;
foo(int, int):
cmp edi, esi
setg al
retReduce magnitude of constants
x + c > y -> x + (c - 1) >= y
x + c <= y -> x + (c - 1) < ybool foo(int x, int y) return x + 10 <= y;
foo(int, int):
add edi, 9
cmp edi, esi
setl al
retEliminate constants in comparisons
(x + c1) cmp c2 -> x cmp (c2 - c1)
(x + c1) cmp (y + c2) -> x cmp (y + (c2 - c1)) if c1 <= c2
The second transformation is only valid if c1 <= c2, as it would
otherwise introduce an overflow when y has the value INT_MIN.bool foo(int x) return x + 42 <= 11;
foo(int):
cmp edi, -30
setl al
ret
Pointer arithmetic and type promotion
If an operation does not overflow, then we will get the same result if
we do the operation in a wider type. This is often useful when doing
things like array indexing on 64-bit architectures — the index
calculations are typically done using 32-bit int, but the pointers are
64-bit, and the compiler may generate more efficient code when signed
overflow is undefined by promoting the 32-bit integers to 64-bit
operations instead of generating type extensions.
One other aspect of this is that undefined overflow ensures that a[i]
and a[i+1] are adjacent. This improves analysis of memory accesses for
vectorization etc.
This is a very important optimization as loop vectorization one of the most efficient and effective optimization algorithms.
It is trickier to demonstrate. But I remember actually encountering a situation when changing an index from unsigned
to signed
drastically improved the generated assembly. Unfortunately I cannot remember or replicate it now. Will come back later if I figure it out.
Value range calculations
The compiler keeps track of the variables' range of possible values at
each point in the program, i.e. for code such asint x = foo();
if (x > 0) {
int y = x + 5;
int z = y / 4;
it determines that x has the range
[1, INT_MAX]
after the
if-statement, and can thus determine that y has the range[6,
as overflow is not allowed. And the next line can be
INT_MAX]
optimized toint z = y >> 2;
as the compiler knows that y is
non-negative.
auto foo(int x)
if (x <= 0)
__builtin_unreachable();
return (x + 5) / 4;
foo(int):
lea eax, [rdi+5]
sar eax, 2
ret
The undefined overflow helps optimizations that need to compare two
values (as the wrapping case would give possible values of the form
[INT_MIN, (INT_MIN+4)]
or[6, INT_MAX]
that prevents all useful
comparisons with<
or>
), such as
- Changing comparisons
x<y
to true or false if the ranges forx
andy
does not overlap
- Changing
min(x,y)
ormax(x,y)
tox
ory
if the ranges do not overlap
- Changing
abs(x)
tox
or-x
if the range does not cross0
- Changing
x/c
tox>>log2(c)
ifx>0
and the constantc
is a power of2
- Changing
x%c
tox&(c-1)
ifx>0
and the constantc
is a power of2
Loop analysis and optimization
The canonical example of why undefined signed overflow helps loop
optimizations is that loops likefor (int i = 0; i <= m; i++)
are guaranteed to terminate for undefined overflow. This helps
architectures that have specific loop instructions, as they do in
general not handle infinite loops.
But undefined signed overflow helps many more loop optimizations. All
analysis such as determining number of iteration, transforming
induction variables, and keeping track of memory accesses are using
everything in the previous sections in order to do its work. In
particular, the set of loops that can be vectorized are severely
reduced when signed overflow is allowed.
"x + 10 > x holds true now" - no it doesn't. It could format your hard disk if x happens to equal INT_MAX-5.
– immibis
18 mins ago
add a comment |
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3 Answers
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active
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votes
3 Answers
3
active
oldest
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active
oldest
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active
oldest
votes
Not quite an example of optimization, but one useful consequence of undefined behaviour is -ftrapv
command line switch of GCC/clang. It inserts code which crashes your program on integer overflow.
It won't work on unsigned integers, in accordance with the idea that unsigned overflow is intentional.
The Standard's wording on signed integer overflow ensures that people won't write overflowing code on purpose, so ftrapv
is a useful tool to discover unintentional overflow.
add a comment |
Not quite an example of optimization, but one useful consequence of undefined behaviour is -ftrapv
command line switch of GCC/clang. It inserts code which crashes your program on integer overflow.
It won't work on unsigned integers, in accordance with the idea that unsigned overflow is intentional.
The Standard's wording on signed integer overflow ensures that people won't write overflowing code on purpose, so ftrapv
is a useful tool to discover unintentional overflow.
add a comment |
Not quite an example of optimization, but one useful consequence of undefined behaviour is -ftrapv
command line switch of GCC/clang. It inserts code which crashes your program on integer overflow.
It won't work on unsigned integers, in accordance with the idea that unsigned overflow is intentional.
The Standard's wording on signed integer overflow ensures that people won't write overflowing code on purpose, so ftrapv
is a useful tool to discover unintentional overflow.
Not quite an example of optimization, but one useful consequence of undefined behaviour is -ftrapv
command line switch of GCC/clang. It inserts code which crashes your program on integer overflow.
It won't work on unsigned integers, in accordance with the idea that unsigned overflow is intentional.
The Standard's wording on signed integer overflow ensures that people won't write overflowing code on purpose, so ftrapv
is a useful tool to discover unintentional overflow.
answered 6 hours ago
anatolyganatolyg
17.4k44794
17.4k44794
add a comment |
add a comment |
The answer is actually in your question:
Yet most CPUs implement signed arithmetics with defined semantics
I can't think of a CPU that you can buy today that does not use twos-compliment arithmetic for signed integers, but that wasn't always the case.
The C language was invented in 1972. Back then, IBM 7090 mainframes still existed. Not all computers were twos-compliment.
To have defined the language (and overflow behaviour) around 2s-compliment would have been prejudicial to code generation on machines that weren't.
Furthermore, as it has already been said, specifying that signed overflow is to be UB allows the compiler to produce better code, because it can discount code paths that result from signed overflow, assuming that this will never happen.
If I understand correctly that it's intended to clamp the sum of a and b to 0....INT_MAX without wraparound, I can think of two ways to write this function in a compliant way.
First, the inefficient general case that will work on all cpus:
int sum_max(int a, unsigned char b)
if (a > std::numeric_limits<int>::max() - b)
return std::numeric_limits<int>::max();
else
return a + b;
Second, the surprisingly efficient 2s-compliment specific way:
int sum_max2(int a, unsigned char b)
unsigned int buffer;
std::memcpy(&buffer, &a, sizeof(a));
buffer += b;
if (buffer > std::numeric_limits<int>::max())
buffer = std::numeric_limits<int>::max();
std::memcpy(&a, &buffer, sizeof(a));
return a;
Resulting assembler can be seen here: https://godbolt.org/z/F42IXV
add a comment |
The answer is actually in your question:
Yet most CPUs implement signed arithmetics with defined semantics
I can't think of a CPU that you can buy today that does not use twos-compliment arithmetic for signed integers, but that wasn't always the case.
The C language was invented in 1972. Back then, IBM 7090 mainframes still existed. Not all computers were twos-compliment.
To have defined the language (and overflow behaviour) around 2s-compliment would have been prejudicial to code generation on machines that weren't.
Furthermore, as it has already been said, specifying that signed overflow is to be UB allows the compiler to produce better code, because it can discount code paths that result from signed overflow, assuming that this will never happen.
If I understand correctly that it's intended to clamp the sum of a and b to 0....INT_MAX without wraparound, I can think of two ways to write this function in a compliant way.
First, the inefficient general case that will work on all cpus:
int sum_max(int a, unsigned char b)
if (a > std::numeric_limits<int>::max() - b)
return std::numeric_limits<int>::max();
else
return a + b;
Second, the surprisingly efficient 2s-compliment specific way:
int sum_max2(int a, unsigned char b)
unsigned int buffer;
std::memcpy(&buffer, &a, sizeof(a));
buffer += b;
if (buffer > std::numeric_limits<int>::max())
buffer = std::numeric_limits<int>::max();
std::memcpy(&a, &buffer, sizeof(a));
return a;
Resulting assembler can be seen here: https://godbolt.org/z/F42IXV
add a comment |
The answer is actually in your question:
Yet most CPUs implement signed arithmetics with defined semantics
I can't think of a CPU that you can buy today that does not use twos-compliment arithmetic for signed integers, but that wasn't always the case.
The C language was invented in 1972. Back then, IBM 7090 mainframes still existed. Not all computers were twos-compliment.
To have defined the language (and overflow behaviour) around 2s-compliment would have been prejudicial to code generation on machines that weren't.
Furthermore, as it has already been said, specifying that signed overflow is to be UB allows the compiler to produce better code, because it can discount code paths that result from signed overflow, assuming that this will never happen.
If I understand correctly that it's intended to clamp the sum of a and b to 0....INT_MAX without wraparound, I can think of two ways to write this function in a compliant way.
First, the inefficient general case that will work on all cpus:
int sum_max(int a, unsigned char b)
if (a > std::numeric_limits<int>::max() - b)
return std::numeric_limits<int>::max();
else
return a + b;
Second, the surprisingly efficient 2s-compliment specific way:
int sum_max2(int a, unsigned char b)
unsigned int buffer;
std::memcpy(&buffer, &a, sizeof(a));
buffer += b;
if (buffer > std::numeric_limits<int>::max())
buffer = std::numeric_limits<int>::max();
std::memcpy(&a, &buffer, sizeof(a));
return a;
Resulting assembler can be seen here: https://godbolt.org/z/F42IXV
The answer is actually in your question:
Yet most CPUs implement signed arithmetics with defined semantics
I can't think of a CPU that you can buy today that does not use twos-compliment arithmetic for signed integers, but that wasn't always the case.
The C language was invented in 1972. Back then, IBM 7090 mainframes still existed. Not all computers were twos-compliment.
To have defined the language (and overflow behaviour) around 2s-compliment would have been prejudicial to code generation on machines that weren't.
Furthermore, as it has already been said, specifying that signed overflow is to be UB allows the compiler to produce better code, because it can discount code paths that result from signed overflow, assuming that this will never happen.
If I understand correctly that it's intended to clamp the sum of a and b to 0....INT_MAX without wraparound, I can think of two ways to write this function in a compliant way.
First, the inefficient general case that will work on all cpus:
int sum_max(int a, unsigned char b)
if (a > std::numeric_limits<int>::max() - b)
return std::numeric_limits<int>::max();
else
return a + b;
Second, the surprisingly efficient 2s-compliment specific way:
int sum_max2(int a, unsigned char b)
unsigned int buffer;
std::memcpy(&buffer, &a, sizeof(a));
buffer += b;
if (buffer > std::numeric_limits<int>::max())
buffer = std::numeric_limits<int>::max();
std::memcpy(&a, &buffer, sizeof(a));
return a;
Resulting assembler can be seen here: https://godbolt.org/z/F42IXV
answered 2 hours ago
Richard HodgesRichard Hodges
57.4k658105
57.4k658105
add a comment |
add a comment |
I don't know about studies and statistics, but yes, there are definitely optimizations taking this into account that compilers actually do. And yes, they are very important (tldr loop vectorization for example).
Besides the compiler optimizations, there is another aspect to be taken into account. With UB you get C/C++ signed integers to behave arithmetically as you would expect mathematically. For instance x + 10 > x
holds true now, but would not on a wrap-around behavior.
I've found an excellent article How undefined signed overflow enables optimizations in GCC from Krister Walfridsson’s blog listing some optimizations that take signed overflow UB into account. The following examples are from it. I am adding c++ and assembly examples to them.
If the optimizations look too simple, uninteresting or unimpactful, remember that these optimization are just steps in a much much larger chain of optimizations. And the butterfly effect does happen as a seemingly unimportant optimization at an earlier step can trigger a much more impactful optimization at a later step.
If the examples look nonsensical (who would write x * 10 > 0
) keep in mind that you can very easily get to this kind of examples in C and C++ with constants, macros, templates. Besides the compiler can get to this kind of examples when applying transformations and optimizations in its IR.
Signed integer expression simplification
Eliminate multiplication in comparison with 0
(x * c) cmp 0 -> x cmp 0
bool foo(int x) return x * 10 > 0
foo(int):
test edi, edi
setg al
retEliminate division after multiplication
(x * c1) / c2 -> x * (c1 / c2) if c1 is divisible by c2
int foo(int x) return (x * 20) / 10;
foo(int):
lea eax, [rdi+rdi]
retEliminate negation
(-x) / (-y) -> x / y
int foo(int x, int y) return (-x) / (-y);
foo(int, int):
mov eax, edi
cdq
idiv esi
retSimplify comparisons that are always true or false
x + c < x -> false
x + c <= x -> false
x + c > x -> true
x + c >= x -> truebool foo(int x) return x + 10 >= x;
foo(int):
mov eax, 1
retEliminate negation in comparisons
(-x) cmp (-y) -> y cmp x
bool foo(int x, int y) return -x < -y;
foo(int, int):
cmp edi, esi
setg al
retReduce magnitude of constants
x + c > y -> x + (c - 1) >= y
x + c <= y -> x + (c - 1) < ybool foo(int x, int y) return x + 10 <= y;
foo(int, int):
add edi, 9
cmp edi, esi
setl al
retEliminate constants in comparisons
(x + c1) cmp c2 -> x cmp (c2 - c1)
(x + c1) cmp (y + c2) -> x cmp (y + (c2 - c1)) if c1 <= c2
The second transformation is only valid if c1 <= c2, as it would
otherwise introduce an overflow when y has the value INT_MIN.bool foo(int x) return x + 42 <= 11;
foo(int):
cmp edi, -30
setl al
ret
Pointer arithmetic and type promotion
If an operation does not overflow, then we will get the same result if
we do the operation in a wider type. This is often useful when doing
things like array indexing on 64-bit architectures — the index
calculations are typically done using 32-bit int, but the pointers are
64-bit, and the compiler may generate more efficient code when signed
overflow is undefined by promoting the 32-bit integers to 64-bit
operations instead of generating type extensions.
One other aspect of this is that undefined overflow ensures that a[i]
and a[i+1] are adjacent. This improves analysis of memory accesses for
vectorization etc.
This is a very important optimization as loop vectorization one of the most efficient and effective optimization algorithms.
It is trickier to demonstrate. But I remember actually encountering a situation when changing an index from unsigned
to signed
drastically improved the generated assembly. Unfortunately I cannot remember or replicate it now. Will come back later if I figure it out.
Value range calculations
The compiler keeps track of the variables' range of possible values at
each point in the program, i.e. for code such asint x = foo();
if (x > 0) {
int y = x + 5;
int z = y / 4;
it determines that x has the range
[1, INT_MAX]
after the
if-statement, and can thus determine that y has the range[6,
as overflow is not allowed. And the next line can be
INT_MAX]
optimized toint z = y >> 2;
as the compiler knows that y is
non-negative.
auto foo(int x)
if (x <= 0)
__builtin_unreachable();
return (x + 5) / 4;
foo(int):
lea eax, [rdi+5]
sar eax, 2
ret
The undefined overflow helps optimizations that need to compare two
values (as the wrapping case would give possible values of the form
[INT_MIN, (INT_MIN+4)]
or[6, INT_MAX]
that prevents all useful
comparisons with<
or>
), such as
- Changing comparisons
x<y
to true or false if the ranges forx
andy
does not overlap
- Changing
min(x,y)
ormax(x,y)
tox
ory
if the ranges do not overlap
- Changing
abs(x)
tox
or-x
if the range does not cross0
- Changing
x/c
tox>>log2(c)
ifx>0
and the constantc
is a power of2
- Changing
x%c
tox&(c-1)
ifx>0
and the constantc
is a power of2
Loop analysis and optimization
The canonical example of why undefined signed overflow helps loop
optimizations is that loops likefor (int i = 0; i <= m; i++)
are guaranteed to terminate for undefined overflow. This helps
architectures that have specific loop instructions, as they do in
general not handle infinite loops.
But undefined signed overflow helps many more loop optimizations. All
analysis such as determining number of iteration, transforming
induction variables, and keeping track of memory accesses are using
everything in the previous sections in order to do its work. In
particular, the set of loops that can be vectorized are severely
reduced when signed overflow is allowed.
"x + 10 > x holds true now" - no it doesn't. It could format your hard disk if x happens to equal INT_MAX-5.
– immibis
18 mins ago
add a comment |
I don't know about studies and statistics, but yes, there are definitely optimizations taking this into account that compilers actually do. And yes, they are very important (tldr loop vectorization for example).
Besides the compiler optimizations, there is another aspect to be taken into account. With UB you get C/C++ signed integers to behave arithmetically as you would expect mathematically. For instance x + 10 > x
holds true now, but would not on a wrap-around behavior.
I've found an excellent article How undefined signed overflow enables optimizations in GCC from Krister Walfridsson’s blog listing some optimizations that take signed overflow UB into account. The following examples are from it. I am adding c++ and assembly examples to them.
If the optimizations look too simple, uninteresting or unimpactful, remember that these optimization are just steps in a much much larger chain of optimizations. And the butterfly effect does happen as a seemingly unimportant optimization at an earlier step can trigger a much more impactful optimization at a later step.
If the examples look nonsensical (who would write x * 10 > 0
) keep in mind that you can very easily get to this kind of examples in C and C++ with constants, macros, templates. Besides the compiler can get to this kind of examples when applying transformations and optimizations in its IR.
Signed integer expression simplification
Eliminate multiplication in comparison with 0
(x * c) cmp 0 -> x cmp 0
bool foo(int x) return x * 10 > 0
foo(int):
test edi, edi
setg al
retEliminate division after multiplication
(x * c1) / c2 -> x * (c1 / c2) if c1 is divisible by c2
int foo(int x) return (x * 20) / 10;
foo(int):
lea eax, [rdi+rdi]
retEliminate negation
(-x) / (-y) -> x / y
int foo(int x, int y) return (-x) / (-y);
foo(int, int):
mov eax, edi
cdq
idiv esi
retSimplify comparisons that are always true or false
x + c < x -> false
x + c <= x -> false
x + c > x -> true
x + c >= x -> truebool foo(int x) return x + 10 >= x;
foo(int):
mov eax, 1
retEliminate negation in comparisons
(-x) cmp (-y) -> y cmp x
bool foo(int x, int y) return -x < -y;
foo(int, int):
cmp edi, esi
setg al
retReduce magnitude of constants
x + c > y -> x + (c - 1) >= y
x + c <= y -> x + (c - 1) < ybool foo(int x, int y) return x + 10 <= y;
foo(int, int):
add edi, 9
cmp edi, esi
setl al
retEliminate constants in comparisons
(x + c1) cmp c2 -> x cmp (c2 - c1)
(x + c1) cmp (y + c2) -> x cmp (y + (c2 - c1)) if c1 <= c2
The second transformation is only valid if c1 <= c2, as it would
otherwise introduce an overflow when y has the value INT_MIN.bool foo(int x) return x + 42 <= 11;
foo(int):
cmp edi, -30
setl al
ret
Pointer arithmetic and type promotion
If an operation does not overflow, then we will get the same result if
we do the operation in a wider type. This is often useful when doing
things like array indexing on 64-bit architectures — the index
calculations are typically done using 32-bit int, but the pointers are
64-bit, and the compiler may generate more efficient code when signed
overflow is undefined by promoting the 32-bit integers to 64-bit
operations instead of generating type extensions.
One other aspect of this is that undefined overflow ensures that a[i]
and a[i+1] are adjacent. This improves analysis of memory accesses for
vectorization etc.
This is a very important optimization as loop vectorization one of the most efficient and effective optimization algorithms.
It is trickier to demonstrate. But I remember actually encountering a situation when changing an index from unsigned
to signed
drastically improved the generated assembly. Unfortunately I cannot remember or replicate it now. Will come back later if I figure it out.
Value range calculations
The compiler keeps track of the variables' range of possible values at
each point in the program, i.e. for code such asint x = foo();
if (x > 0) {
int y = x + 5;
int z = y / 4;
it determines that x has the range
[1, INT_MAX]
after the
if-statement, and can thus determine that y has the range[6,
as overflow is not allowed. And the next line can be
INT_MAX]
optimized toint z = y >> 2;
as the compiler knows that y is
non-negative.
auto foo(int x)
if (x <= 0)
__builtin_unreachable();
return (x + 5) / 4;
foo(int):
lea eax, [rdi+5]
sar eax, 2
ret
The undefined overflow helps optimizations that need to compare two
values (as the wrapping case would give possible values of the form
[INT_MIN, (INT_MIN+4)]
or[6, INT_MAX]
that prevents all useful
comparisons with<
or>
), such as
- Changing comparisons
x<y
to true or false if the ranges forx
andy
does not overlap
- Changing
min(x,y)
ormax(x,y)
tox
ory
if the ranges do not overlap
- Changing
abs(x)
tox
or-x
if the range does not cross0
- Changing
x/c
tox>>log2(c)
ifx>0
and the constantc
is a power of2
- Changing
x%c
tox&(c-1)
ifx>0
and the constantc
is a power of2
Loop analysis and optimization
The canonical example of why undefined signed overflow helps loop
optimizations is that loops likefor (int i = 0; i <= m; i++)
are guaranteed to terminate for undefined overflow. This helps
architectures that have specific loop instructions, as they do in
general not handle infinite loops.
But undefined signed overflow helps many more loop optimizations. All
analysis such as determining number of iteration, transforming
induction variables, and keeping track of memory accesses are using
everything in the previous sections in order to do its work. In
particular, the set of loops that can be vectorized are severely
reduced when signed overflow is allowed.
"x + 10 > x holds true now" - no it doesn't. It could format your hard disk if x happens to equal INT_MAX-5.
– immibis
18 mins ago
add a comment |
I don't know about studies and statistics, but yes, there are definitely optimizations taking this into account that compilers actually do. And yes, they are very important (tldr loop vectorization for example).
Besides the compiler optimizations, there is another aspect to be taken into account. With UB you get C/C++ signed integers to behave arithmetically as you would expect mathematically. For instance x + 10 > x
holds true now, but would not on a wrap-around behavior.
I've found an excellent article How undefined signed overflow enables optimizations in GCC from Krister Walfridsson’s blog listing some optimizations that take signed overflow UB into account. The following examples are from it. I am adding c++ and assembly examples to them.
If the optimizations look too simple, uninteresting or unimpactful, remember that these optimization are just steps in a much much larger chain of optimizations. And the butterfly effect does happen as a seemingly unimportant optimization at an earlier step can trigger a much more impactful optimization at a later step.
If the examples look nonsensical (who would write x * 10 > 0
) keep in mind that you can very easily get to this kind of examples in C and C++ with constants, macros, templates. Besides the compiler can get to this kind of examples when applying transformations and optimizations in its IR.
Signed integer expression simplification
Eliminate multiplication in comparison with 0
(x * c) cmp 0 -> x cmp 0
bool foo(int x) return x * 10 > 0
foo(int):
test edi, edi
setg al
retEliminate division after multiplication
(x * c1) / c2 -> x * (c1 / c2) if c1 is divisible by c2
int foo(int x) return (x * 20) / 10;
foo(int):
lea eax, [rdi+rdi]
retEliminate negation
(-x) / (-y) -> x / y
int foo(int x, int y) return (-x) / (-y);
foo(int, int):
mov eax, edi
cdq
idiv esi
retSimplify comparisons that are always true or false
x + c < x -> false
x + c <= x -> false
x + c > x -> true
x + c >= x -> truebool foo(int x) return x + 10 >= x;
foo(int):
mov eax, 1
retEliminate negation in comparisons
(-x) cmp (-y) -> y cmp x
bool foo(int x, int y) return -x < -y;
foo(int, int):
cmp edi, esi
setg al
retReduce magnitude of constants
x + c > y -> x + (c - 1) >= y
x + c <= y -> x + (c - 1) < ybool foo(int x, int y) return x + 10 <= y;
foo(int, int):
add edi, 9
cmp edi, esi
setl al
retEliminate constants in comparisons
(x + c1) cmp c2 -> x cmp (c2 - c1)
(x + c1) cmp (y + c2) -> x cmp (y + (c2 - c1)) if c1 <= c2
The second transformation is only valid if c1 <= c2, as it would
otherwise introduce an overflow when y has the value INT_MIN.bool foo(int x) return x + 42 <= 11;
foo(int):
cmp edi, -30
setl al
ret
Pointer arithmetic and type promotion
If an operation does not overflow, then we will get the same result if
we do the operation in a wider type. This is often useful when doing
things like array indexing on 64-bit architectures — the index
calculations are typically done using 32-bit int, but the pointers are
64-bit, and the compiler may generate more efficient code when signed
overflow is undefined by promoting the 32-bit integers to 64-bit
operations instead of generating type extensions.
One other aspect of this is that undefined overflow ensures that a[i]
and a[i+1] are adjacent. This improves analysis of memory accesses for
vectorization etc.
This is a very important optimization as loop vectorization one of the most efficient and effective optimization algorithms.
It is trickier to demonstrate. But I remember actually encountering a situation when changing an index from unsigned
to signed
drastically improved the generated assembly. Unfortunately I cannot remember or replicate it now. Will come back later if I figure it out.
Value range calculations
The compiler keeps track of the variables' range of possible values at
each point in the program, i.e. for code such asint x = foo();
if (x > 0) {
int y = x + 5;
int z = y / 4;
it determines that x has the range
[1, INT_MAX]
after the
if-statement, and can thus determine that y has the range[6,
as overflow is not allowed. And the next line can be
INT_MAX]
optimized toint z = y >> 2;
as the compiler knows that y is
non-negative.
auto foo(int x)
if (x <= 0)
__builtin_unreachable();
return (x + 5) / 4;
foo(int):
lea eax, [rdi+5]
sar eax, 2
ret
The undefined overflow helps optimizations that need to compare two
values (as the wrapping case would give possible values of the form
[INT_MIN, (INT_MIN+4)]
or[6, INT_MAX]
that prevents all useful
comparisons with<
or>
), such as
- Changing comparisons
x<y
to true or false if the ranges forx
andy
does not overlap
- Changing
min(x,y)
ormax(x,y)
tox
ory
if the ranges do not overlap
- Changing
abs(x)
tox
or-x
if the range does not cross0
- Changing
x/c
tox>>log2(c)
ifx>0
and the constantc
is a power of2
- Changing
x%c
tox&(c-1)
ifx>0
and the constantc
is a power of2
Loop analysis and optimization
The canonical example of why undefined signed overflow helps loop
optimizations is that loops likefor (int i = 0; i <= m; i++)
are guaranteed to terminate for undefined overflow. This helps
architectures that have specific loop instructions, as they do in
general not handle infinite loops.
But undefined signed overflow helps many more loop optimizations. All
analysis such as determining number of iteration, transforming
induction variables, and keeping track of memory accesses are using
everything in the previous sections in order to do its work. In
particular, the set of loops that can be vectorized are severely
reduced when signed overflow is allowed.
I don't know about studies and statistics, but yes, there are definitely optimizations taking this into account that compilers actually do. And yes, they are very important (tldr loop vectorization for example).
Besides the compiler optimizations, there is another aspect to be taken into account. With UB you get C/C++ signed integers to behave arithmetically as you would expect mathematically. For instance x + 10 > x
holds true now, but would not on a wrap-around behavior.
I've found an excellent article How undefined signed overflow enables optimizations in GCC from Krister Walfridsson’s blog listing some optimizations that take signed overflow UB into account. The following examples are from it. I am adding c++ and assembly examples to them.
If the optimizations look too simple, uninteresting or unimpactful, remember that these optimization are just steps in a much much larger chain of optimizations. And the butterfly effect does happen as a seemingly unimportant optimization at an earlier step can trigger a much more impactful optimization at a later step.
If the examples look nonsensical (who would write x * 10 > 0
) keep in mind that you can very easily get to this kind of examples in C and C++ with constants, macros, templates. Besides the compiler can get to this kind of examples when applying transformations and optimizations in its IR.
Signed integer expression simplification
Eliminate multiplication in comparison with 0
(x * c) cmp 0 -> x cmp 0
bool foo(int x) return x * 10 > 0
foo(int):
test edi, edi
setg al
retEliminate division after multiplication
(x * c1) / c2 -> x * (c1 / c2) if c1 is divisible by c2
int foo(int x) return (x * 20) / 10;
foo(int):
lea eax, [rdi+rdi]
retEliminate negation
(-x) / (-y) -> x / y
int foo(int x, int y) return (-x) / (-y);
foo(int, int):
mov eax, edi
cdq
idiv esi
retSimplify comparisons that are always true or false
x + c < x -> false
x + c <= x -> false
x + c > x -> true
x + c >= x -> truebool foo(int x) return x + 10 >= x;
foo(int):
mov eax, 1
retEliminate negation in comparisons
(-x) cmp (-y) -> y cmp x
bool foo(int x, int y) return -x < -y;
foo(int, int):
cmp edi, esi
setg al
retReduce magnitude of constants
x + c > y -> x + (c - 1) >= y
x + c <= y -> x + (c - 1) < ybool foo(int x, int y) return x + 10 <= y;
foo(int, int):
add edi, 9
cmp edi, esi
setl al
retEliminate constants in comparisons
(x + c1) cmp c2 -> x cmp (c2 - c1)
(x + c1) cmp (y + c2) -> x cmp (y + (c2 - c1)) if c1 <= c2
The second transformation is only valid if c1 <= c2, as it would
otherwise introduce an overflow when y has the value INT_MIN.bool foo(int x) return x + 42 <= 11;
foo(int):
cmp edi, -30
setl al
ret
Pointer arithmetic and type promotion
If an operation does not overflow, then we will get the same result if
we do the operation in a wider type. This is often useful when doing
things like array indexing on 64-bit architectures — the index
calculations are typically done using 32-bit int, but the pointers are
64-bit, and the compiler may generate more efficient code when signed
overflow is undefined by promoting the 32-bit integers to 64-bit
operations instead of generating type extensions.
One other aspect of this is that undefined overflow ensures that a[i]
and a[i+1] are adjacent. This improves analysis of memory accesses for
vectorization etc.
This is a very important optimization as loop vectorization one of the most efficient and effective optimization algorithms.
It is trickier to demonstrate. But I remember actually encountering a situation when changing an index from unsigned
to signed
drastically improved the generated assembly. Unfortunately I cannot remember or replicate it now. Will come back later if I figure it out.
Value range calculations
The compiler keeps track of the variables' range of possible values at
each point in the program, i.e. for code such asint x = foo();
if (x > 0) {
int y = x + 5;
int z = y / 4;
it determines that x has the range
[1, INT_MAX]
after the
if-statement, and can thus determine that y has the range[6,
as overflow is not allowed. And the next line can be
INT_MAX]
optimized toint z = y >> 2;
as the compiler knows that y is
non-negative.
auto foo(int x)
if (x <= 0)
__builtin_unreachable();
return (x + 5) / 4;
foo(int):
lea eax, [rdi+5]
sar eax, 2
ret
The undefined overflow helps optimizations that need to compare two
values (as the wrapping case would give possible values of the form
[INT_MIN, (INT_MIN+4)]
or[6, INT_MAX]
that prevents all useful
comparisons with<
or>
), such as
- Changing comparisons
x<y
to true or false if the ranges forx
andy
does not overlap
- Changing
min(x,y)
ormax(x,y)
tox
ory
if the ranges do not overlap
- Changing
abs(x)
tox
or-x
if the range does not cross0
- Changing
x/c
tox>>log2(c)
ifx>0
and the constantc
is a power of2
- Changing
x%c
tox&(c-1)
ifx>0
and the constantc
is a power of2
Loop analysis and optimization
The canonical example of why undefined signed overflow helps loop
optimizations is that loops likefor (int i = 0; i <= m; i++)
are guaranteed to terminate for undefined overflow. This helps
architectures that have specific loop instructions, as they do in
general not handle infinite loops.
But undefined signed overflow helps many more loop optimizations. All
analysis such as determining number of iteration, transforming
induction variables, and keeping track of memory accesses are using
everything in the previous sections in order to do its work. In
particular, the set of loops that can be vectorized are severely
reduced when signed overflow is allowed.
edited 59 mins ago
answered 1 hour ago
bolovbolov
34.4k878142
34.4k878142
"x + 10 > x holds true now" - no it doesn't. It could format your hard disk if x happens to equal INT_MAX-5.
– immibis
18 mins ago
add a comment |
"x + 10 > x holds true now" - no it doesn't. It could format your hard disk if x happens to equal INT_MAX-5.
– immibis
18 mins ago
"x + 10 > x holds true now" - no it doesn't. It could format your hard disk if x happens to equal INT_MAX-5.
– immibis
18 mins ago
"x + 10 > x holds true now" - no it doesn't. It could format your hard disk if x happens to equal INT_MAX-5.
– immibis
18 mins ago
add a comment |
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– Samuel Liew♦
3 hours ago
1
The reason C says signed integer overflow is undefined is that some CPUs use "2's complement", some use "1's compliment", some use "sign and magnitude"; and for all the cases overflow could cause anything (e.g. CPUs like MIPS have "trap on overflow"). In other words it's about portability and not optimisation.
– Brendan
2 hours ago
Exactly. The only 'meaningful statistic' anybody needs is that ones-complement and sign-magnitude computers exist.
– user207421
1 hour ago