Applying a function to a nested listNested List ProductExtract function argumentsCreating a simple function to compute the average of the difference between pairs of elements in an arraySorting non-numerical listsExtract part of list by reading it in a cyclic mannerApplying a function along the desired dimensions of a n-dimensional arrayManipulating Elements in a Triple-Nested ListApplying function to all elements of the list of listApplying a function to a list of symbolic ratiosApplying a function to a list (compounding)

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Applying a function to a nested list

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Applying a function to a nested list


Nested List ProductExtract function argumentsCreating a simple function to compute the average of the difference between pairs of elements in an arraySorting non-numerical listsExtract part of list by reading it in a cyclic mannerApplying a function along the desired dimensions of a n-dimensional arrayManipulating Elements in a Triple-Nested ListApplying function to all elements of the list of listApplying a function to a list of symbolic ratiosApplying a function to a list (compounding)













1












$begingroup$


Say I have a list:



l = a, b, c, d 


I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.



F[F[F[a,b], c] , d]


Is there a function in Mathematica which does exactly that?










share|improve this question











$endgroup$







  • 4




    $begingroup$
    Why does the order for d and c change, and not for a and b?
    $endgroup$
    – Carl Woll
    2 hours ago










  • $begingroup$
    My mistake, thank you for spotting that. I edited it.
    $endgroup$
    – amator2357
    1 hour ago















1












$begingroup$


Say I have a list:



l = a, b, c, d 


I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.



F[F[F[a,b], c] , d]


Is there a function in Mathematica which does exactly that?










share|improve this question











$endgroup$







  • 4




    $begingroup$
    Why does the order for d and c change, and not for a and b?
    $endgroup$
    – Carl Woll
    2 hours ago










  • $begingroup$
    My mistake, thank you for spotting that. I edited it.
    $endgroup$
    – amator2357
    1 hour ago













1












1








1





$begingroup$


Say I have a list:



l = a, b, c, d 


I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.



F[F[F[a,b], c] , d]


Is there a function in Mathematica which does exactly that?










share|improve this question











$endgroup$




Say I have a list:



l = a, b, c, d 


I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.



F[F[F[a,b], c] , d]


Is there a function in Mathematica which does exactly that?







list-manipulation functions






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 1 hour ago







amator2357

















asked 2 hours ago









amator2357amator2357

4538




4538







  • 4




    $begingroup$
    Why does the order for d and c change, and not for a and b?
    $endgroup$
    – Carl Woll
    2 hours ago










  • $begingroup$
    My mistake, thank you for spotting that. I edited it.
    $endgroup$
    – amator2357
    1 hour ago












  • 4




    $begingroup$
    Why does the order for d and c change, and not for a and b?
    $endgroup$
    – Carl Woll
    2 hours ago










  • $begingroup$
    My mistake, thank you for spotting that. I edited it.
    $endgroup$
    – amator2357
    1 hour ago







4




4




$begingroup$
Why does the order for d and c change, and not for a and b?
$endgroup$
– Carl Woll
2 hours ago




$begingroup$
Why does the order for d and c change, and not for a and b?
$endgroup$
– Carl Woll
2 hours ago












$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
1 hour ago




$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
1 hour ago










4 Answers
4






active

oldest

votes


















2












$begingroup$

Replace[l, x_List :> F[x], All]



F[F[F[a, b], c], d]




Also



ClearAll[f]
f[Except[_List, x_]] := x;
MapAll[f, l]



f[f[f[a, b], c], d]







share|improve this answer









$endgroup$




















    1












    $begingroup$

    F@*Reverse@Map[F@*Reverse, l, -2]



    F[d, F[c, F[b, a]]]




    Fold[F[#2, #1] &, Flatten[l]]



    F[d, F[c, F[b, a]]]







    share|improve this answer









    $endgroup$












    • $begingroup$
      I think that Flatten works in this trivial case but it will not "find" the levels in a more complex situation
      $endgroup$
      – J42161217
      2 hours ago


















    0












    $begingroup$

    This works:



    a, b, c, d //. s_?ListQ, t_?(Not@*ListQ) :> f[s], t // f


    It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.






    share|improve this answer









    $endgroup$




















      0












      $begingroup$

      Another possibility, if you want just lists to acquire the F wrapper:



      l /. List -> F@*List



      F[F[F[a, b], c], d]







      share|improve this answer









      $endgroup$













        Your Answer








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        4 Answers
        4






        active

        oldest

        votes








        4 Answers
        4






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2












        $begingroup$

        Replace[l, x_List :> F[x], All]



        F[F[F[a, b], c], d]




        Also



        ClearAll[f]
        f[Except[_List, x_]] := x;
        MapAll[f, l]



        f[f[f[a, b], c], d]







        share|improve this answer









        $endgroup$

















          2












          $begingroup$

          Replace[l, x_List :> F[x], All]



          F[F[F[a, b], c], d]




          Also



          ClearAll[f]
          f[Except[_List, x_]] := x;
          MapAll[f, l]



          f[f[f[a, b], c], d]







          share|improve this answer









          $endgroup$















            2












            2








            2





            $begingroup$

            Replace[l, x_List :> F[x], All]



            F[F[F[a, b], c], d]




            Also



            ClearAll[f]
            f[Except[_List, x_]] := x;
            MapAll[f, l]



            f[f[f[a, b], c], d]







            share|improve this answer









            $endgroup$



            Replace[l, x_List :> F[x], All]



            F[F[F[a, b], c], d]




            Also



            ClearAll[f]
            f[Except[_List, x_]] := x;
            MapAll[f, l]



            f[f[f[a, b], c], d]








            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 1 hour ago









            kglrkglr

            190k10209427




            190k10209427





















                1












                $begingroup$

                F@*Reverse@Map[F@*Reverse, l, -2]



                F[d, F[c, F[b, a]]]




                Fold[F[#2, #1] &, Flatten[l]]



                F[d, F[c, F[b, a]]]







                share|improve this answer









                $endgroup$












                • $begingroup$
                  I think that Flatten works in this trivial case but it will not "find" the levels in a more complex situation
                  $endgroup$
                  – J42161217
                  2 hours ago















                1












                $begingroup$

                F@*Reverse@Map[F@*Reverse, l, -2]



                F[d, F[c, F[b, a]]]




                Fold[F[#2, #1] &, Flatten[l]]



                F[d, F[c, F[b, a]]]







                share|improve this answer









                $endgroup$












                • $begingroup$
                  I think that Flatten works in this trivial case but it will not "find" the levels in a more complex situation
                  $endgroup$
                  – J42161217
                  2 hours ago













                1












                1








                1





                $begingroup$

                F@*Reverse@Map[F@*Reverse, l, -2]



                F[d, F[c, F[b, a]]]




                Fold[F[#2, #1] &, Flatten[l]]



                F[d, F[c, F[b, a]]]







                share|improve this answer









                $endgroup$



                F@*Reverse@Map[F@*Reverse, l, -2]



                F[d, F[c, F[b, a]]]




                Fold[F[#2, #1] &, Flatten[l]]



                F[d, F[c, F[b, a]]]








                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 2 hours ago









                Henrik SchumacherHenrik Schumacher

                61.3k585171




                61.3k585171











                • $begingroup$
                  I think that Flatten works in this trivial case but it will not "find" the levels in a more complex situation
                  $endgroup$
                  – J42161217
                  2 hours ago
















                • $begingroup$
                  I think that Flatten works in this trivial case but it will not "find" the levels in a more complex situation
                  $endgroup$
                  – J42161217
                  2 hours ago















                $begingroup$
                I think that Flatten works in this trivial case but it will not "find" the levels in a more complex situation
                $endgroup$
                – J42161217
                2 hours ago




                $begingroup$
                I think that Flatten works in this trivial case but it will not "find" the levels in a more complex situation
                $endgroup$
                – J42161217
                2 hours ago











                0












                $begingroup$

                This works:



                a, b, c, d //. s_?ListQ, t_?(Not@*ListQ) :> f[s], t // f


                It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.






                share|improve this answer









                $endgroup$

















                  0












                  $begingroup$

                  This works:



                  a, b, c, d //. s_?ListQ, t_?(Not@*ListQ) :> f[s], t // f


                  It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.






                  share|improve this answer









                  $endgroup$















                    0












                    0








                    0





                    $begingroup$

                    This works:



                    a, b, c, d //. s_?ListQ, t_?(Not@*ListQ) :> f[s], t // f


                    It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.






                    share|improve this answer









                    $endgroup$



                    This works:



                    a, b, c, d //. s_?ListQ, t_?(Not@*ListQ) :> f[s], t // f


                    It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 1 hour ago









                    ShredderroyShredderroy

                    1,6101117




                    1,6101117





















                        0












                        $begingroup$

                        Another possibility, if you want just lists to acquire the F wrapper:



                        l /. List -> F@*List



                        F[F[F[a, b], c], d]







                        share|improve this answer









                        $endgroup$

















                          0












                          $begingroup$

                          Another possibility, if you want just lists to acquire the F wrapper:



                          l /. List -> F@*List



                          F[F[F[a, b], c], d]







                          share|improve this answer









                          $endgroup$















                            0












                            0








                            0





                            $begingroup$

                            Another possibility, if you want just lists to acquire the F wrapper:



                            l /. List -> F@*List



                            F[F[F[a, b], c], d]







                            share|improve this answer









                            $endgroup$



                            Another possibility, if you want just lists to acquire the F wrapper:



                            l /. List -> F@*List



                            F[F[F[a, b], c], d]








                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 34 mins ago









                            Carl WollCarl Woll

                            76.4k3100200




                            76.4k3100200



























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