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Power LED from 3.3V Power Pin without Resistor


LED resistor questionWiring RGB LED'sbattery power for RPI and IR LED bank?PWM-based controlling an LED-strip using transistors, circuitry problemsTurn TouchScreen Backlight Off after ShutdownUsing jumper cables to turn on LEDsRaspberry PI + DS1820 + Led. Resistor confusion (series or parallel?)Control 5m of WS2812 LED Strip: Wire it uphelp reconstructing blinking LED circuit that required GPIO #17 pin low rather than highProblem with LED blink program on PiPowering a sensor using an external power supply board






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2















I tried wiring one white LED to the 3.3V pin on a Pi Zero W with a 330 Ohm resistor but it's not as bright as I would like. If I wire it up without a resister I get a good amount of brightness. Is that a viable solution? Or should I try a smaller resistor?



If it matters, the power supply is a standard 5V 2.5A supply like this one. The LED is this one.










share|improve this question

















  • 1





    I'd recommend 10Ohm resistor

    – Jaromanda X
    1 hour ago

















2















I tried wiring one white LED to the 3.3V pin on a Pi Zero W with a 330 Ohm resistor but it's not as bright as I would like. If I wire it up without a resister I get a good amount of brightness. Is that a viable solution? Or should I try a smaller resistor?



If it matters, the power supply is a standard 5V 2.5A supply like this one. The LED is this one.










share|improve this question

















  • 1





    I'd recommend 10Ohm resistor

    – Jaromanda X
    1 hour ago













2












2








2








I tried wiring one white LED to the 3.3V pin on a Pi Zero W with a 330 Ohm resistor but it's not as bright as I would like. If I wire it up without a resister I get a good amount of brightness. Is that a viable solution? Or should I try a smaller resistor?



If it matters, the power supply is a standard 5V 2.5A supply like this one. The LED is this one.










share|improve this question














I tried wiring one white LED to the 3.3V pin on a Pi Zero W with a 330 Ohm resistor but it's not as bright as I would like. If I wire it up without a resister I get a good amount of brightness. Is that a viable solution? Or should I try a smaller resistor?



If it matters, the power supply is a standard 5V 2.5A supply like this one. The LED is this one.







power led






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 1 hour ago









MichaelMichael

1504




1504







  • 1





    I'd recommend 10Ohm resistor

    – Jaromanda X
    1 hour ago












  • 1





    I'd recommend 10Ohm resistor

    – Jaromanda X
    1 hour ago







1




1





I'd recommend 10Ohm resistor

– Jaromanda X
1 hour ago





I'd recommend 10Ohm resistor

– Jaromanda X
1 hour ago










1 Answer
1






active

oldest

votes


















3














You need to consider that the forward voltage of a white LED is likely in the range of 3.0 V to 3.2 V (according to the linked article). Assuming the best case of 3.0 V and a resistor of 330 Ohms and using Ohm's law R = U / I we find that the current is about 1 mA and thus the brightness of the LED is rather low. Decreasing the resistor will help to some degree but be aware that this is borderline in any case. Say 33 Ohms will get you about 10 mA which might be ok. Best bet is to use the 5 V instead and design the resistor in such a fashion that the current suits the safe operational range of the LED.



Connecting a LED to a voltage source without a current limiting resistor is not a safe way of operating a LED. It is therefore not advisable to do so.



Find a more elaborate description of the calculations here; even though it is aiming at GPIO pins the physics still apply.






share|improve this answer























  • Great input - thanks so much!

    – Michael
    1 hour ago











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














You need to consider that the forward voltage of a white LED is likely in the range of 3.0 V to 3.2 V (according to the linked article). Assuming the best case of 3.0 V and a resistor of 330 Ohms and using Ohm's law R = U / I we find that the current is about 1 mA and thus the brightness of the LED is rather low. Decreasing the resistor will help to some degree but be aware that this is borderline in any case. Say 33 Ohms will get you about 10 mA which might be ok. Best bet is to use the 5 V instead and design the resistor in such a fashion that the current suits the safe operational range of the LED.



Connecting a LED to a voltage source without a current limiting resistor is not a safe way of operating a LED. It is therefore not advisable to do so.



Find a more elaborate description of the calculations here; even though it is aiming at GPIO pins the physics still apply.






share|improve this answer























  • Great input - thanks so much!

    – Michael
    1 hour ago















3














You need to consider that the forward voltage of a white LED is likely in the range of 3.0 V to 3.2 V (according to the linked article). Assuming the best case of 3.0 V and a resistor of 330 Ohms and using Ohm's law R = U / I we find that the current is about 1 mA and thus the brightness of the LED is rather low. Decreasing the resistor will help to some degree but be aware that this is borderline in any case. Say 33 Ohms will get you about 10 mA which might be ok. Best bet is to use the 5 V instead and design the resistor in such a fashion that the current suits the safe operational range of the LED.



Connecting a LED to a voltage source without a current limiting resistor is not a safe way of operating a LED. It is therefore not advisable to do so.



Find a more elaborate description of the calculations here; even though it is aiming at GPIO pins the physics still apply.






share|improve this answer























  • Great input - thanks so much!

    – Michael
    1 hour ago













3












3








3







You need to consider that the forward voltage of a white LED is likely in the range of 3.0 V to 3.2 V (according to the linked article). Assuming the best case of 3.0 V and a resistor of 330 Ohms and using Ohm's law R = U / I we find that the current is about 1 mA and thus the brightness of the LED is rather low. Decreasing the resistor will help to some degree but be aware that this is borderline in any case. Say 33 Ohms will get you about 10 mA which might be ok. Best bet is to use the 5 V instead and design the resistor in such a fashion that the current suits the safe operational range of the LED.



Connecting a LED to a voltage source without a current limiting resistor is not a safe way of operating a LED. It is therefore not advisable to do so.



Find a more elaborate description of the calculations here; even though it is aiming at GPIO pins the physics still apply.






share|improve this answer













You need to consider that the forward voltage of a white LED is likely in the range of 3.0 V to 3.2 V (according to the linked article). Assuming the best case of 3.0 V and a resistor of 330 Ohms and using Ohm's law R = U / I we find that the current is about 1 mA and thus the brightness of the LED is rather low. Decreasing the resistor will help to some degree but be aware that this is borderline in any case. Say 33 Ohms will get you about 10 mA which might be ok. Best bet is to use the 5 V instead and design the resistor in such a fashion that the current suits the safe operational range of the LED.



Connecting a LED to a voltage source without a current limiting resistor is not a safe way of operating a LED. It is therefore not advisable to do so.



Find a more elaborate description of the calculations here; even though it is aiming at GPIO pins the physics still apply.







share|improve this answer












share|improve this answer



share|improve this answer










answered 1 hour ago









GhanimaGhanima

12.6k114080




12.6k114080












  • Great input - thanks so much!

    – Michael
    1 hour ago

















  • Great input - thanks so much!

    – Michael
    1 hour ago
















Great input - thanks so much!

– Michael
1 hour ago





Great input - thanks so much!

– Michael
1 hour ago

















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