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How do you center multiple equations that have multiple steps?
How do you center equations?How do you align equations parts vertically?How to add explanatory text labels to a list of equations / solving stepsHow do you center everythingEquations aligned centerHow can I center equations?Horizontal center vertically aligned equationsHow center align two equations separated by a lineCenter all equations inside alignHow to align multiple separate equations by equal sign to center of page
I am writing a paper that deals with Gaussian integers and I have a section where I am talking about the norm of the units in the Gaussian integers. Since there are only four units in the Gaussian integers, I'd like to have the calculations of their norms appear neatly in four columns that are centered. Basically so that you can easily look down each of the four columns and see the calculations for each unit. What I have right now sort of does that but its very sloppy and I'm sure there is a much cleaner way to do it. I'm still new to Latex so I realize this code is probably painfully inefficient but I would appreciate any suggestions of how to fix it and what packages I'd need to use to implement those changes.
begincenter
$N(1)=N(1+0i)$
hspace.025cm
$N(-1)=N(-1+0i)$
hspace.025cm
$N(i)=N(0+1i)$
hspace.025cm
$N(-i)=N(0-1i)$
endcenter
begincenter
$N(1)=1^2+0$
hspace.1cm
$N(-1)=(-1)^2+0^2$
hspace.1cm
$N(i)=0^2+1^2$
hspace.1cm
$N(-i)=0^2+(-1)^2$
endcenter
begincenter
$N(1)=1$
hspace.5cm
$N(-1)=1$
hspace.5cm
$N(i)=1$
hspace.5cm
$N(-i)=1$
endcenter
horizontal-alignment equations vertical-alignment
add a comment |
I am writing a paper that deals with Gaussian integers and I have a section where I am talking about the norm of the units in the Gaussian integers. Since there are only four units in the Gaussian integers, I'd like to have the calculations of their norms appear neatly in four columns that are centered. Basically so that you can easily look down each of the four columns and see the calculations for each unit. What I have right now sort of does that but its very sloppy and I'm sure there is a much cleaner way to do it. I'm still new to Latex so I realize this code is probably painfully inefficient but I would appreciate any suggestions of how to fix it and what packages I'd need to use to implement those changes.
begincenter
$N(1)=N(1+0i)$
hspace.025cm
$N(-1)=N(-1+0i)$
hspace.025cm
$N(i)=N(0+1i)$
hspace.025cm
$N(-i)=N(0-1i)$
endcenter
begincenter
$N(1)=1^2+0$
hspace.1cm
$N(-1)=(-1)^2+0^2$
hspace.1cm
$N(i)=0^2+1^2$
hspace.1cm
$N(-i)=0^2+(-1)^2$
endcenter
begincenter
$N(1)=1$
hspace.5cm
$N(-1)=1$
hspace.5cm
$N(i)=1$
hspace.5cm
$N(-i)=1$
endcenter
horizontal-alignment equations vertical-alignment
Maybe use anarrayenvironment?
– leandriis
2 hours ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
2 hours ago
add a comment |
I am writing a paper that deals with Gaussian integers and I have a section where I am talking about the norm of the units in the Gaussian integers. Since there are only four units in the Gaussian integers, I'd like to have the calculations of their norms appear neatly in four columns that are centered. Basically so that you can easily look down each of the four columns and see the calculations for each unit. What I have right now sort of does that but its very sloppy and I'm sure there is a much cleaner way to do it. I'm still new to Latex so I realize this code is probably painfully inefficient but I would appreciate any suggestions of how to fix it and what packages I'd need to use to implement those changes.
begincenter
$N(1)=N(1+0i)$
hspace.025cm
$N(-1)=N(-1+0i)$
hspace.025cm
$N(i)=N(0+1i)$
hspace.025cm
$N(-i)=N(0-1i)$
endcenter
begincenter
$N(1)=1^2+0$
hspace.1cm
$N(-1)=(-1)^2+0^2$
hspace.1cm
$N(i)=0^2+1^2$
hspace.1cm
$N(-i)=0^2+(-1)^2$
endcenter
begincenter
$N(1)=1$
hspace.5cm
$N(-1)=1$
hspace.5cm
$N(i)=1$
hspace.5cm
$N(-i)=1$
endcenter
horizontal-alignment equations vertical-alignment
I am writing a paper that deals with Gaussian integers and I have a section where I am talking about the norm of the units in the Gaussian integers. Since there are only four units in the Gaussian integers, I'd like to have the calculations of their norms appear neatly in four columns that are centered. Basically so that you can easily look down each of the four columns and see the calculations for each unit. What I have right now sort of does that but its very sloppy and I'm sure there is a much cleaner way to do it. I'm still new to Latex so I realize this code is probably painfully inefficient but I would appreciate any suggestions of how to fix it and what packages I'd need to use to implement those changes.
begincenter
$N(1)=N(1+0i)$
hspace.025cm
$N(-1)=N(-1+0i)$
hspace.025cm
$N(i)=N(0+1i)$
hspace.025cm
$N(-i)=N(0-1i)$
endcenter
begincenter
$N(1)=1^2+0$
hspace.1cm
$N(-1)=(-1)^2+0^2$
hspace.1cm
$N(i)=0^2+1^2$
hspace.1cm
$N(-i)=0^2+(-1)^2$
endcenter
begincenter
$N(1)=1$
hspace.5cm
$N(-1)=1$
hspace.5cm
$N(i)=1$
hspace.5cm
$N(-i)=1$
endcenter
horizontal-alignment equations vertical-alignment
horizontal-alignment equations vertical-alignment
edited 2 hours ago
Mico
289k32395783
289k32395783
asked 2 hours ago
Alex AdinolfiAlex Adinolfi
564
564
Maybe use anarrayenvironment?
– leandriis
2 hours ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
2 hours ago
add a comment |
Maybe use anarrayenvironment?
– leandriis
2 hours ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
2 hours ago
Maybe use an
array environment?– leandriis
2 hours ago
Maybe use an
array environment?– leandriis
2 hours ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
2 hours ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
2 hours ago
add a comment |
3 Answers
3
active
oldest
votes
Here are three different suggestions using either array or alignedat:

documentclassarticle
usepackagegeometry
usepackageamsmath
begindocument
[
beginarrayllll
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
endarray
]
[
beginarraycccc
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
endarray
]
beginalignat*4
N(1)&=N(1+0i) &quad N(-1)&=N(-1+0i) &quad N(i)&=N(0+1i) &quad N(-i)&=N(0-1i) \
N(1)&=1^2+0 & N(-1)&=(-1)^2+0^2 & N(i)&=0^2+1^2 & N(-i)&=0^2+(-1)^2 \
N(1)&=1 & N(-1)&=1 & N(i)&=1 & N(-i)&=1
endalignat*
enddocument
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
add a comment |
For example I would have used the tables in sequence (but it's just a personal taste) to give a touch of vitality.
In this case I have used the booktabs package to have toprule and bottomrule.

documentclass[a4paper,12pt]article
usepackagearray
usepackagebooktabs
begindocument
[
setlengtharraycolsep0pt
renewcommandarraystretch1.25
beginarrayr @= l
toprule
N(1) &N(1+0i) \
N(-1)&N(-1+0i) \
N(i) &N(0+1i) \
N(-i)&N(1+0i) \
bottomrule
endarray
quadRightarrowquad
beginarrayr @= l
toprule
N(1) &1^2+0 \
N(-1)&(-1)^2+0^2\
N(i) &0^2+1^2 \
N(-i)&0^2+(-1)^2\
bottomrule
endarray
quadRightarrowquad
beginarrayr @= l
toprule
N(1) &1 \
N(-1)&1 \
N(i) &1 \
N(-i)&1 \
bottomrule
endarray
]
enddocument
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
1 hour ago
add a comment |
I propose this layout:
documentclassarticle
usepackage[utf8]inputenc%
usepackagegeometry
usepackage[table, svgnames]xcolor
usepackagemathtools
colorletshadecolorGainsboro!50! Lavender
newcommand*shadebox[1]%
colorboxshadecolorhspace1em$displaystyle #1 $hspace1em
begindocument
beginequation
begingathered
beginaligned
N(1) & =N(1+0i)\
& =1^2+0^2
endaligned \[1.5ex]
shadeboxN(1) = 1
endgathered
qquad
begingathered
beginaligned
N(-1) & =N(-1+0i) \
& =(-1)^2+0^2
endaligned \[1ex]
shadeboxN(-1) = 1
endgathered
qquad
begingathered
beginaligned
N(i) & =N(0+1i) \
& =0^2+1^2
endaligned \[1ex]
shadebox N(i) = 1
endgathered
qquad
begingathered
beginaligned
N(-i) & =N(0-1i) \
& =0^2+(-1)^2
endaligned \[1ex]
shadeboxN(-i) = 1
endgathered
endequation
enddocument

1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
1 hour ago
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
59 mins ago
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here are three different suggestions using either array or alignedat:

documentclassarticle
usepackagegeometry
usepackageamsmath
begindocument
[
beginarrayllll
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
endarray
]
[
beginarraycccc
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
endarray
]
beginalignat*4
N(1)&=N(1+0i) &quad N(-1)&=N(-1+0i) &quad N(i)&=N(0+1i) &quad N(-i)&=N(0-1i) \
N(1)&=1^2+0 & N(-1)&=(-1)^2+0^2 & N(i)&=0^2+1^2 & N(-i)&=0^2+(-1)^2 \
N(1)&=1 & N(-1)&=1 & N(i)&=1 & N(-i)&=1
endalignat*
enddocument
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
add a comment |
Here are three different suggestions using either array or alignedat:

documentclassarticle
usepackagegeometry
usepackageamsmath
begindocument
[
beginarrayllll
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
endarray
]
[
beginarraycccc
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
endarray
]
beginalignat*4
N(1)&=N(1+0i) &quad N(-1)&=N(-1+0i) &quad N(i)&=N(0+1i) &quad N(-i)&=N(0-1i) \
N(1)&=1^2+0 & N(-1)&=(-1)^2+0^2 & N(i)&=0^2+1^2 & N(-i)&=0^2+(-1)^2 \
N(1)&=1 & N(-1)&=1 & N(i)&=1 & N(-i)&=1
endalignat*
enddocument
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
add a comment |
Here are three different suggestions using either array or alignedat:

documentclassarticle
usepackagegeometry
usepackageamsmath
begindocument
[
beginarrayllll
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
endarray
]
[
beginarraycccc
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
endarray
]
beginalignat*4
N(1)&=N(1+0i) &quad N(-1)&=N(-1+0i) &quad N(i)&=N(0+1i) &quad N(-i)&=N(0-1i) \
N(1)&=1^2+0 & N(-1)&=(-1)^2+0^2 & N(i)&=0^2+1^2 & N(-i)&=0^2+(-1)^2 \
N(1)&=1 & N(-1)&=1 & N(i)&=1 & N(-i)&=1
endalignat*
enddocument
Here are three different suggestions using either array or alignedat:

documentclassarticle
usepackagegeometry
usepackageamsmath
begindocument
[
beginarrayllll
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
endarray
]
[
beginarraycccc
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
endarray
]
beginalignat*4
N(1)&=N(1+0i) &quad N(-1)&=N(-1+0i) &quad N(i)&=N(0+1i) &quad N(-i)&=N(0-1i) \
N(1)&=1^2+0 & N(-1)&=(-1)^2+0^2 & N(i)&=0^2+1^2 & N(-i)&=0^2+(-1)^2 \
N(1)&=1 & N(-1)&=1 & N(i)&=1 & N(-i)&=1
endalignat*
enddocument
answered 1 hour ago
leandriisleandriis
12.3k1833
12.3k1833
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
add a comment |
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
add a comment |
For example I would have used the tables in sequence (but it's just a personal taste) to give a touch of vitality.
In this case I have used the booktabs package to have toprule and bottomrule.

documentclass[a4paper,12pt]article
usepackagearray
usepackagebooktabs
begindocument
[
setlengtharraycolsep0pt
renewcommandarraystretch1.25
beginarrayr @= l
toprule
N(1) &N(1+0i) \
N(-1)&N(-1+0i) \
N(i) &N(0+1i) \
N(-i)&N(1+0i) \
bottomrule
endarray
quadRightarrowquad
beginarrayr @= l
toprule
N(1) &1^2+0 \
N(-1)&(-1)^2+0^2\
N(i) &0^2+1^2 \
N(-i)&0^2+(-1)^2\
bottomrule
endarray
quadRightarrowquad
beginarrayr @= l
toprule
N(1) &1 \
N(-1)&1 \
N(i) &1 \
N(-i)&1 \
bottomrule
endarray
]
enddocument
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
1 hour ago
add a comment |
For example I would have used the tables in sequence (but it's just a personal taste) to give a touch of vitality.
In this case I have used the booktabs package to have toprule and bottomrule.

documentclass[a4paper,12pt]article
usepackagearray
usepackagebooktabs
begindocument
[
setlengtharraycolsep0pt
renewcommandarraystretch1.25
beginarrayr @= l
toprule
N(1) &N(1+0i) \
N(-1)&N(-1+0i) \
N(i) &N(0+1i) \
N(-i)&N(1+0i) \
bottomrule
endarray
quadRightarrowquad
beginarrayr @= l
toprule
N(1) &1^2+0 \
N(-1)&(-1)^2+0^2\
N(i) &0^2+1^2 \
N(-i)&0^2+(-1)^2\
bottomrule
endarray
quadRightarrowquad
beginarrayr @= l
toprule
N(1) &1 \
N(-1)&1 \
N(i) &1 \
N(-i)&1 \
bottomrule
endarray
]
enddocument
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
1 hour ago
add a comment |
For example I would have used the tables in sequence (but it's just a personal taste) to give a touch of vitality.
In this case I have used the booktabs package to have toprule and bottomrule.

documentclass[a4paper,12pt]article
usepackagearray
usepackagebooktabs
begindocument
[
setlengtharraycolsep0pt
renewcommandarraystretch1.25
beginarrayr @= l
toprule
N(1) &N(1+0i) \
N(-1)&N(-1+0i) \
N(i) &N(0+1i) \
N(-i)&N(1+0i) \
bottomrule
endarray
quadRightarrowquad
beginarrayr @= l
toprule
N(1) &1^2+0 \
N(-1)&(-1)^2+0^2\
N(i) &0^2+1^2 \
N(-i)&0^2+(-1)^2\
bottomrule
endarray
quadRightarrowquad
beginarrayr @= l
toprule
N(1) &1 \
N(-1)&1 \
N(i) &1 \
N(-i)&1 \
bottomrule
endarray
]
enddocument
For example I would have used the tables in sequence (but it's just a personal taste) to give a touch of vitality.
In this case I have used the booktabs package to have toprule and bottomrule.

documentclass[a4paper,12pt]article
usepackagearray
usepackagebooktabs
begindocument
[
setlengtharraycolsep0pt
renewcommandarraystretch1.25
beginarrayr @= l
toprule
N(1) &N(1+0i) \
N(-1)&N(-1+0i) \
N(i) &N(0+1i) \
N(-i)&N(1+0i) \
bottomrule
endarray
quadRightarrowquad
beginarrayr @= l
toprule
N(1) &1^2+0 \
N(-1)&(-1)^2+0^2\
N(i) &0^2+1^2 \
N(-i)&0^2+(-1)^2\
bottomrule
endarray
quadRightarrowquad
beginarrayr @= l
toprule
N(1) &1 \
N(-1)&1 \
N(i) &1 \
N(-i)&1 \
bottomrule
endarray
]
enddocument
edited 1 hour ago
Mico
289k32395783
289k32395783
answered 1 hour ago
SebastianoSebastiano
11.8k42467
11.8k42467
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
1 hour ago
add a comment |
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
1 hour ago
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
1 hour ago
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
1 hour ago
add a comment |
I propose this layout:
documentclassarticle
usepackage[utf8]inputenc%
usepackagegeometry
usepackage[table, svgnames]xcolor
usepackagemathtools
colorletshadecolorGainsboro!50! Lavender
newcommand*shadebox[1]%
colorboxshadecolorhspace1em$displaystyle #1 $hspace1em
begindocument
beginequation
begingathered
beginaligned
N(1) & =N(1+0i)\
& =1^2+0^2
endaligned \[1.5ex]
shadeboxN(1) = 1
endgathered
qquad
begingathered
beginaligned
N(-1) & =N(-1+0i) \
& =(-1)^2+0^2
endaligned \[1ex]
shadeboxN(-1) = 1
endgathered
qquad
begingathered
beginaligned
N(i) & =N(0+1i) \
& =0^2+1^2
endaligned \[1ex]
shadebox N(i) = 1
endgathered
qquad
begingathered
beginaligned
N(-i) & =N(0-1i) \
& =0^2+(-1)^2
endaligned \[1ex]
shadeboxN(-i) = 1
endgathered
endequation
enddocument

1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
1 hour ago
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
59 mins ago
add a comment |
I propose this layout:
documentclassarticle
usepackage[utf8]inputenc%
usepackagegeometry
usepackage[table, svgnames]xcolor
usepackagemathtools
colorletshadecolorGainsboro!50! Lavender
newcommand*shadebox[1]%
colorboxshadecolorhspace1em$displaystyle #1 $hspace1em
begindocument
beginequation
begingathered
beginaligned
N(1) & =N(1+0i)\
& =1^2+0^2
endaligned \[1.5ex]
shadeboxN(1) = 1
endgathered
qquad
begingathered
beginaligned
N(-1) & =N(-1+0i) \
& =(-1)^2+0^2
endaligned \[1ex]
shadeboxN(-1) = 1
endgathered
qquad
begingathered
beginaligned
N(i) & =N(0+1i) \
& =0^2+1^2
endaligned \[1ex]
shadebox N(i) = 1
endgathered
qquad
begingathered
beginaligned
N(-i) & =N(0-1i) \
& =0^2+(-1)^2
endaligned \[1ex]
shadeboxN(-i) = 1
endgathered
endequation
enddocument

1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
1 hour ago
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
59 mins ago
add a comment |
I propose this layout:
documentclassarticle
usepackage[utf8]inputenc%
usepackagegeometry
usepackage[table, svgnames]xcolor
usepackagemathtools
colorletshadecolorGainsboro!50! Lavender
newcommand*shadebox[1]%
colorboxshadecolorhspace1em$displaystyle #1 $hspace1em
begindocument
beginequation
begingathered
beginaligned
N(1) & =N(1+0i)\
& =1^2+0^2
endaligned \[1.5ex]
shadeboxN(1) = 1
endgathered
qquad
begingathered
beginaligned
N(-1) & =N(-1+0i) \
& =(-1)^2+0^2
endaligned \[1ex]
shadeboxN(-1) = 1
endgathered
qquad
begingathered
beginaligned
N(i) & =N(0+1i) \
& =0^2+1^2
endaligned \[1ex]
shadebox N(i) = 1
endgathered
qquad
begingathered
beginaligned
N(-i) & =N(0-1i) \
& =0^2+(-1)^2
endaligned \[1ex]
shadeboxN(-i) = 1
endgathered
endequation
enddocument

I propose this layout:
documentclassarticle
usepackage[utf8]inputenc%
usepackagegeometry
usepackage[table, svgnames]xcolor
usepackagemathtools
colorletshadecolorGainsboro!50! Lavender
newcommand*shadebox[1]%
colorboxshadecolorhspace1em$displaystyle #1 $hspace1em
begindocument
beginequation
begingathered
beginaligned
N(1) & =N(1+0i)\
& =1^2+0^2
endaligned \[1.5ex]
shadeboxN(1) = 1
endgathered
qquad
begingathered
beginaligned
N(-1) & =N(-1+0i) \
& =(-1)^2+0^2
endaligned \[1ex]
shadeboxN(-1) = 1
endgathered
qquad
begingathered
beginaligned
N(i) & =N(0+1i) \
& =0^2+1^2
endaligned \[1ex]
shadebox N(i) = 1
endgathered
qquad
begingathered
beginaligned
N(-i) & =N(0-1i) \
& =0^2+(-1)^2
endaligned \[1ex]
shadeboxN(-i) = 1
endgathered
endequation
enddocument

answered 1 hour ago
BernardBernard
178k779211
178k779211
1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
1 hour ago
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
59 mins ago
add a comment |
1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
1 hour ago
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
59 mins ago
1
1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
1 hour ago
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
1 hour ago
1
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
59 mins ago
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
59 mins ago
add a comment |
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Maybe use an
arrayenvironment?– leandriis
2 hours ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
2 hours ago