What's the point in a preamp? The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Calculating the value of bypass capacitors for an amplifierAnother question concerning transistorsGetting bad clipping issues with this 3 stage amplifierIs there a difference in the meaning of power and current amplifier terms?What is the function of this transistor?NPN audio amplification, what is the difference between outputing from the collector or emitterWhy would I use an inverting amplifier?Headphone amplifier for guitar with stereo MP3 input - mixingDoes this audio amplifier do differential filtering?Amplifier and Low Pass filter not responding after few minutes of correct output?
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What's the point in a preamp?
The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Calculating the value of bypass capacitors for an amplifierAnother question concerning transistorsGetting bad clipping issues with this 3 stage amplifierIs there a difference in the meaning of power and current amplifier terms?What is the function of this transistor?NPN audio amplification, what is the difference between outputing from the collector or emitterWhy would I use an inverting amplifier?Headphone amplifier for guitar with stereo MP3 input - mixingDoes this audio amplifier do differential filtering?Amplifier and Low Pass filter not responding after few minutes of correct output?
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$begingroup$
I'm talking in the context of guitar amps, but I assume that this question is relevant for any type of audio amplifier.
Very often in amplifier schematics I see two stages of amplification -- first, the signal is amplified a smaller amount by a preamp circuit and then amplified again by a power amp circuit.
This seems redundant to me. What's the point in amplifying a signal in two small steps rather than just one greater-gain amplification?
My first thought was: does this multi-stage amplification help to reduce unwanted noise from the signal? But the more I think about that, the less it makes sense, since surely the second stage would be amplifying any noise as well.
amplifier
$endgroup$
add a comment |
$begingroup$
I'm talking in the context of guitar amps, but I assume that this question is relevant for any type of audio amplifier.
Very often in amplifier schematics I see two stages of amplification -- first, the signal is amplified a smaller amount by a preamp circuit and then amplified again by a power amp circuit.
This seems redundant to me. What's the point in amplifying a signal in two small steps rather than just one greater-gain amplification?
My first thought was: does this multi-stage amplification help to reduce unwanted noise from the signal? But the more I think about that, the less it makes sense, since surely the second stage would be amplifying any noise as well.
amplifier
$endgroup$
$begingroup$
There is also the problem of gain bandwidth product. For a given amplifier, more gain means less bandwidth. If you use too much gain in one stage, then you limit the bandwidth of that stage. This can lead to distortion - it takes gain and bandwidth for negative feedback to compensate for distortion.
$endgroup$
– JRE
1 hour ago
$begingroup$
@JRE I think in the context of the OP's he's not really talking about multiple "stages" of amplification as much as he's asking why there is both a pre-amp and an amp instead of just one amp. Inside either the pre-amp or the amp itself, it could contain as many actual stages of amplification as it wants.
$endgroup$
– Toor
1 hour ago
1
$begingroup$
You don't want the high currents (to the loudspeaker) anywhere near the input signal from the guitar pickup, or the vinyl-record signals.
$endgroup$
– analogsystemsrf
1 hour ago
add a comment |
$begingroup$
I'm talking in the context of guitar amps, but I assume that this question is relevant for any type of audio amplifier.
Very often in amplifier schematics I see two stages of amplification -- first, the signal is amplified a smaller amount by a preamp circuit and then amplified again by a power amp circuit.
This seems redundant to me. What's the point in amplifying a signal in two small steps rather than just one greater-gain amplification?
My first thought was: does this multi-stage amplification help to reduce unwanted noise from the signal? But the more I think about that, the less it makes sense, since surely the second stage would be amplifying any noise as well.
amplifier
$endgroup$
I'm talking in the context of guitar amps, but I assume that this question is relevant for any type of audio amplifier.
Very often in amplifier schematics I see two stages of amplification -- first, the signal is amplified a smaller amount by a preamp circuit and then amplified again by a power amp circuit.
This seems redundant to me. What's the point in amplifying a signal in two small steps rather than just one greater-gain amplification?
My first thought was: does this multi-stage amplification help to reduce unwanted noise from the signal? But the more I think about that, the less it makes sense, since surely the second stage would be amplifying any noise as well.
amplifier
amplifier
asked 1 hour ago
Jacob GarbyJacob Garby
27110
27110
$begingroup$
There is also the problem of gain bandwidth product. For a given amplifier, more gain means less bandwidth. If you use too much gain in one stage, then you limit the bandwidth of that stage. This can lead to distortion - it takes gain and bandwidth for negative feedback to compensate for distortion.
$endgroup$
– JRE
1 hour ago
$begingroup$
@JRE I think in the context of the OP's he's not really talking about multiple "stages" of amplification as much as he's asking why there is both a pre-amp and an amp instead of just one amp. Inside either the pre-amp or the amp itself, it could contain as many actual stages of amplification as it wants.
$endgroup$
– Toor
1 hour ago
1
$begingroup$
You don't want the high currents (to the loudspeaker) anywhere near the input signal from the guitar pickup, or the vinyl-record signals.
$endgroup$
– analogsystemsrf
1 hour ago
add a comment |
$begingroup$
There is also the problem of gain bandwidth product. For a given amplifier, more gain means less bandwidth. If you use too much gain in one stage, then you limit the bandwidth of that stage. This can lead to distortion - it takes gain and bandwidth for negative feedback to compensate for distortion.
$endgroup$
– JRE
1 hour ago
$begingroup$
@JRE I think in the context of the OP's he's not really talking about multiple "stages" of amplification as much as he's asking why there is both a pre-amp and an amp instead of just one amp. Inside either the pre-amp or the amp itself, it could contain as many actual stages of amplification as it wants.
$endgroup$
– Toor
1 hour ago
1
$begingroup$
You don't want the high currents (to the loudspeaker) anywhere near the input signal from the guitar pickup, or the vinyl-record signals.
$endgroup$
– analogsystemsrf
1 hour ago
$begingroup$
There is also the problem of gain bandwidth product. For a given amplifier, more gain means less bandwidth. If you use too much gain in one stage, then you limit the bandwidth of that stage. This can lead to distortion - it takes gain and bandwidth for negative feedback to compensate for distortion.
$endgroup$
– JRE
1 hour ago
$begingroup$
There is also the problem of gain bandwidth product. For a given amplifier, more gain means less bandwidth. If you use too much gain in one stage, then you limit the bandwidth of that stage. This can lead to distortion - it takes gain and bandwidth for negative feedback to compensate for distortion.
$endgroup$
– JRE
1 hour ago
$begingroup$
@JRE I think in the context of the OP's he's not really talking about multiple "stages" of amplification as much as he's asking why there is both a pre-amp and an amp instead of just one amp. Inside either the pre-amp or the amp itself, it could contain as many actual stages of amplification as it wants.
$endgroup$
– Toor
1 hour ago
$begingroup$
@JRE I think in the context of the OP's he's not really talking about multiple "stages" of amplification as much as he's asking why there is both a pre-amp and an amp instead of just one amp. Inside either the pre-amp or the amp itself, it could contain as many actual stages of amplification as it wants.
$endgroup$
– Toor
1 hour ago
1
1
$begingroup$
You don't want the high currents (to the loudspeaker) anywhere near the input signal from the guitar pickup, or the vinyl-record signals.
$endgroup$
– analogsystemsrf
1 hour ago
$begingroup$
You don't want the high currents (to the loudspeaker) anywhere near the input signal from the guitar pickup, or the vinyl-record signals.
$endgroup$
– analogsystemsrf
1 hour ago
add a comment |
5 Answers
5
active
oldest
votes
$begingroup$
Quick and dirty answer:
Buffering is one reason. Interconnects between things can have a lot of capacitance and require a lot (comparatively) of current to drive.
Noise immunity is another. Think about this scenario: Send a signal through a wire where it picks up, say, 10mV noise, then amplify it by 100x: total noise, 1000mV. But if you instead amplify it by 10x, then send it through the wire where it gets 10mV noise, then amplify by another 10x, your total signal amplification is still 100x, but your total noise is only 100mV.
$endgroup$
add a comment |
$begingroup$
In audio gear, it is useful to do most of the signal manipulation at a standard level, known as "line level". This includes mixing, equalization, compression, etc.
Some signal sources (microphones, guitar pickups, etc.) do not inherently produce line level outputs, so a preamplifier is used to boost the signal to that level. Some signal sources (record players) require not only a boost, but also a special equalization to flatten the frequency response.
Then, after all of the signal processing is done, a second, "power" amplifier is used to drive the speaker(s).
This kind of modularity allows signal sources, processing stages, and different kinds of speakers to be mixed and matched freely.
$endgroup$
add a comment |
$begingroup$
Let me ask you this...how big would the amplifier hardware have to be to do its job properly? If it was this size, could it go right next to the pickup where the noise would the lowest and signal integrity is highest?
If it can't, then it has to be farther away. But if it's farther away, can the pickup natively produce a signal that can be reliably and accurately transmitted all the way to the single-stage amp?
If not, then you need another amplifier that is physically small enough to go right next to the signal source and reinforce the the signal just enough so that it can be accurately transmitted to where there is more physical space for the rest of the hardware. This reinforcement can come in the form of re-transmitting the pickup's high impedance output as a low impedance output, or boosting the signal levels just a bit so that the transmission noise won't drown out the signal.
$endgroup$
add a comment |
$begingroup$
A major reason for separate boxes for preamps and poweramps is the GROUND currents and also magnetic coupling. [there is numeric example, at 20KHz and 6 amps to the speakers, at end of this answer, with the Preamp only 10cm from the Power amplifier]
Suppose you built the preamp and the poweramp on the same PCB. Why not?
Some of the loudspeaker current will be flowing around on the GROUND, and end up combining with the input signal.
To minimize this "combining", make that PCB long and thin, so the PowerAmp Grounds are far away from the PreAmp Grounds.
How to improve on this? use long thing regions between the Preamp and the Poweramp.
In the extreme, a coax cable provides a long-thin-region, to ensure very small combining of input and output.
Give low millivolt signals from a vinyl record Moving Magnet cartridge, or even 0.5 millivolt from Moving Coil cartridges, that become near-100-volt audio outputs, the entire system needs 100,000:1 isolation.

simulate this circuit – Schematic created using CircuitLab
=============================================
How bad can crosstalk be? assume output current is 6 amps peak at 20,000Hz. The dI/dT is 6* d(sin(2*pi*20,000*time))/dT = 6 * 2*pi*20,000*cos(2pi20000T)
or dI/dT = 700,000 amps per second.
Assume the preamp input (remember that 1 millivolt signal from the cartridge, and you want at least 10,000:1 SNR or tonal feedback, thus 0.1 microvolt feedback is the desired floor) is 0.1 meter from the Speaker output.
V_magnetic_induce = (2.0e-7 * Area/Distance) * dI/dT
and we'll assume the input loop area (signal to ground) is 1cm by 4cm.
Now run the math; remember we need 0.1 microvolt feedback.
Vinduce = 2e-7Henry/meter * 1cm * 4cm /10cm * 700,000
Vinduce = 2e-7 * 0.0004meter/0.1meter * 700,000
Vinduce = 2e-7 * 0.004 * 7e+5
Vinduce = 2e-7 * 4e-3 * 7e+7 = 56 e-3 = 56 milliVolts.
The magnetic feedback, caused by having the Poweramplifer near the Preamplifier, is 56mV / 0.1 microvolt or 560,000X stronger than what "clean" music can tolerate.
$endgroup$
add a comment |
$begingroup$
To minimize the noise factor, which is the SNR of the output divided by the SNR of the input. An ideal amplifier should keep the SNR constant, since the input noise is amplified by the same amount as the input signal. A real amplifier, however, adds extra noise. The noise factor is given by
$$ F = 1 + fracN_mathrmadditionalN_mathrminputG.$$
If you cascade a series of amplifiers the total noise factor is given by Friis’ equation
$$F_mathrmtotal = F_1 + fracF_2 - 1G_1 + fracF_3 - 1G_1 G_2 + fracF_4 - 1G_1 G_2 G_3 + dots.$$
Where $F_n$ is the noise factor of the nth stage and $G_n$ is the gain of the nth stage. This is because the additional noise of the first stage is amplified by the second and subsequent stages but the additional noise of the second stage is amplified by only the third and subsequent stages etc.
As you can see, the the noise factor of a given stage is divided by the gain product of all previous stages. So the first stage is the most important when it comes to noise. That’s why you have a low noise pre-amp stage as your very first component in the signal chain. This configuration has the added benefit of not having to worry about the noise figure of the power amplifier.
$endgroup$
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Quick and dirty answer:
Buffering is one reason. Interconnects between things can have a lot of capacitance and require a lot (comparatively) of current to drive.
Noise immunity is another. Think about this scenario: Send a signal through a wire where it picks up, say, 10mV noise, then amplify it by 100x: total noise, 1000mV. But if you instead amplify it by 10x, then send it through the wire where it gets 10mV noise, then amplify by another 10x, your total signal amplification is still 100x, but your total noise is only 100mV.
$endgroup$
add a comment |
$begingroup$
Quick and dirty answer:
Buffering is one reason. Interconnects between things can have a lot of capacitance and require a lot (comparatively) of current to drive.
Noise immunity is another. Think about this scenario: Send a signal through a wire where it picks up, say, 10mV noise, then amplify it by 100x: total noise, 1000mV. But if you instead amplify it by 10x, then send it through the wire where it gets 10mV noise, then amplify by another 10x, your total signal amplification is still 100x, but your total noise is only 100mV.
$endgroup$
add a comment |
$begingroup$
Quick and dirty answer:
Buffering is one reason. Interconnects between things can have a lot of capacitance and require a lot (comparatively) of current to drive.
Noise immunity is another. Think about this scenario: Send a signal through a wire where it picks up, say, 10mV noise, then amplify it by 100x: total noise, 1000mV. But if you instead amplify it by 10x, then send it through the wire where it gets 10mV noise, then amplify by another 10x, your total signal amplification is still 100x, but your total noise is only 100mV.
$endgroup$
Quick and dirty answer:
Buffering is one reason. Interconnects between things can have a lot of capacitance and require a lot (comparatively) of current to drive.
Noise immunity is another. Think about this scenario: Send a signal through a wire where it picks up, say, 10mV noise, then amplify it by 100x: total noise, 1000mV. But if you instead amplify it by 10x, then send it through the wire where it gets 10mV noise, then amplify by another 10x, your total signal amplification is still 100x, but your total noise is only 100mV.
answered 1 hour ago
HearthHearth
5,10611339
5,10611339
add a comment |
add a comment |
$begingroup$
In audio gear, it is useful to do most of the signal manipulation at a standard level, known as "line level". This includes mixing, equalization, compression, etc.
Some signal sources (microphones, guitar pickups, etc.) do not inherently produce line level outputs, so a preamplifier is used to boost the signal to that level. Some signal sources (record players) require not only a boost, but also a special equalization to flatten the frequency response.
Then, after all of the signal processing is done, a second, "power" amplifier is used to drive the speaker(s).
This kind of modularity allows signal sources, processing stages, and different kinds of speakers to be mixed and matched freely.
$endgroup$
add a comment |
$begingroup$
In audio gear, it is useful to do most of the signal manipulation at a standard level, known as "line level". This includes mixing, equalization, compression, etc.
Some signal sources (microphones, guitar pickups, etc.) do not inherently produce line level outputs, so a preamplifier is used to boost the signal to that level. Some signal sources (record players) require not only a boost, but also a special equalization to flatten the frequency response.
Then, after all of the signal processing is done, a second, "power" amplifier is used to drive the speaker(s).
This kind of modularity allows signal sources, processing stages, and different kinds of speakers to be mixed and matched freely.
$endgroup$
add a comment |
$begingroup$
In audio gear, it is useful to do most of the signal manipulation at a standard level, known as "line level". This includes mixing, equalization, compression, etc.
Some signal sources (microphones, guitar pickups, etc.) do not inherently produce line level outputs, so a preamplifier is used to boost the signal to that level. Some signal sources (record players) require not only a boost, but also a special equalization to flatten the frequency response.
Then, after all of the signal processing is done, a second, "power" amplifier is used to drive the speaker(s).
This kind of modularity allows signal sources, processing stages, and different kinds of speakers to be mixed and matched freely.
$endgroup$
In audio gear, it is useful to do most of the signal manipulation at a standard level, known as "line level". This includes mixing, equalization, compression, etc.
Some signal sources (microphones, guitar pickups, etc.) do not inherently produce line level outputs, so a preamplifier is used to boost the signal to that level. Some signal sources (record players) require not only a boost, but also a special equalization to flatten the frequency response.
Then, after all of the signal processing is done, a second, "power" amplifier is used to drive the speaker(s).
This kind of modularity allows signal sources, processing stages, and different kinds of speakers to be mixed and matched freely.
answered 1 hour ago
Dave Tweed♦Dave Tweed
124k10153268
124k10153268
add a comment |
add a comment |
$begingroup$
Let me ask you this...how big would the amplifier hardware have to be to do its job properly? If it was this size, could it go right next to the pickup where the noise would the lowest and signal integrity is highest?
If it can't, then it has to be farther away. But if it's farther away, can the pickup natively produce a signal that can be reliably and accurately transmitted all the way to the single-stage amp?
If not, then you need another amplifier that is physically small enough to go right next to the signal source and reinforce the the signal just enough so that it can be accurately transmitted to where there is more physical space for the rest of the hardware. This reinforcement can come in the form of re-transmitting the pickup's high impedance output as a low impedance output, or boosting the signal levels just a bit so that the transmission noise won't drown out the signal.
$endgroup$
add a comment |
$begingroup$
Let me ask you this...how big would the amplifier hardware have to be to do its job properly? If it was this size, could it go right next to the pickup where the noise would the lowest and signal integrity is highest?
If it can't, then it has to be farther away. But if it's farther away, can the pickup natively produce a signal that can be reliably and accurately transmitted all the way to the single-stage amp?
If not, then you need another amplifier that is physically small enough to go right next to the signal source and reinforce the the signal just enough so that it can be accurately transmitted to where there is more physical space for the rest of the hardware. This reinforcement can come in the form of re-transmitting the pickup's high impedance output as a low impedance output, or boosting the signal levels just a bit so that the transmission noise won't drown out the signal.
$endgroup$
add a comment |
$begingroup$
Let me ask you this...how big would the amplifier hardware have to be to do its job properly? If it was this size, could it go right next to the pickup where the noise would the lowest and signal integrity is highest?
If it can't, then it has to be farther away. But if it's farther away, can the pickup natively produce a signal that can be reliably and accurately transmitted all the way to the single-stage amp?
If not, then you need another amplifier that is physically small enough to go right next to the signal source and reinforce the the signal just enough so that it can be accurately transmitted to where there is more physical space for the rest of the hardware. This reinforcement can come in the form of re-transmitting the pickup's high impedance output as a low impedance output, or boosting the signal levels just a bit so that the transmission noise won't drown out the signal.
$endgroup$
Let me ask you this...how big would the amplifier hardware have to be to do its job properly? If it was this size, could it go right next to the pickup where the noise would the lowest and signal integrity is highest?
If it can't, then it has to be farther away. But if it's farther away, can the pickup natively produce a signal that can be reliably and accurately transmitted all the way to the single-stage amp?
If not, then you need another amplifier that is physically small enough to go right next to the signal source and reinforce the the signal just enough so that it can be accurately transmitted to where there is more physical space for the rest of the hardware. This reinforcement can come in the form of re-transmitting the pickup's high impedance output as a low impedance output, or boosting the signal levels just a bit so that the transmission noise won't drown out the signal.
edited 1 hour ago
answered 1 hour ago
ToorToor
1,669212
1,669212
add a comment |
add a comment |
$begingroup$
A major reason for separate boxes for preamps and poweramps is the GROUND currents and also magnetic coupling. [there is numeric example, at 20KHz and 6 amps to the speakers, at end of this answer, with the Preamp only 10cm from the Power amplifier]
Suppose you built the preamp and the poweramp on the same PCB. Why not?
Some of the loudspeaker current will be flowing around on the GROUND, and end up combining with the input signal.
To minimize this "combining", make that PCB long and thin, so the PowerAmp Grounds are far away from the PreAmp Grounds.
How to improve on this? use long thing regions between the Preamp and the Poweramp.
In the extreme, a coax cable provides a long-thin-region, to ensure very small combining of input and output.
Give low millivolt signals from a vinyl record Moving Magnet cartridge, or even 0.5 millivolt from Moving Coil cartridges, that become near-100-volt audio outputs, the entire system needs 100,000:1 isolation.

simulate this circuit – Schematic created using CircuitLab
=============================================
How bad can crosstalk be? assume output current is 6 amps peak at 20,000Hz. The dI/dT is 6* d(sin(2*pi*20,000*time))/dT = 6 * 2*pi*20,000*cos(2pi20000T)
or dI/dT = 700,000 amps per second.
Assume the preamp input (remember that 1 millivolt signal from the cartridge, and you want at least 10,000:1 SNR or tonal feedback, thus 0.1 microvolt feedback is the desired floor) is 0.1 meter from the Speaker output.
V_magnetic_induce = (2.0e-7 * Area/Distance) * dI/dT
and we'll assume the input loop area (signal to ground) is 1cm by 4cm.
Now run the math; remember we need 0.1 microvolt feedback.
Vinduce = 2e-7Henry/meter * 1cm * 4cm /10cm * 700,000
Vinduce = 2e-7 * 0.0004meter/0.1meter * 700,000
Vinduce = 2e-7 * 0.004 * 7e+5
Vinduce = 2e-7 * 4e-3 * 7e+7 = 56 e-3 = 56 milliVolts.
The magnetic feedback, caused by having the Poweramplifer near the Preamplifier, is 56mV / 0.1 microvolt or 560,000X stronger than what "clean" music can tolerate.
$endgroup$
add a comment |
$begingroup$
A major reason for separate boxes for preamps and poweramps is the GROUND currents and also magnetic coupling. [there is numeric example, at 20KHz and 6 amps to the speakers, at end of this answer, with the Preamp only 10cm from the Power amplifier]
Suppose you built the preamp and the poweramp on the same PCB. Why not?
Some of the loudspeaker current will be flowing around on the GROUND, and end up combining with the input signal.
To minimize this "combining", make that PCB long and thin, so the PowerAmp Grounds are far away from the PreAmp Grounds.
How to improve on this? use long thing regions between the Preamp and the Poweramp.
In the extreme, a coax cable provides a long-thin-region, to ensure very small combining of input and output.
Give low millivolt signals from a vinyl record Moving Magnet cartridge, or even 0.5 millivolt from Moving Coil cartridges, that become near-100-volt audio outputs, the entire system needs 100,000:1 isolation.

simulate this circuit – Schematic created using CircuitLab
=============================================
How bad can crosstalk be? assume output current is 6 amps peak at 20,000Hz. The dI/dT is 6* d(sin(2*pi*20,000*time))/dT = 6 * 2*pi*20,000*cos(2pi20000T)
or dI/dT = 700,000 amps per second.
Assume the preamp input (remember that 1 millivolt signal from the cartridge, and you want at least 10,000:1 SNR or tonal feedback, thus 0.1 microvolt feedback is the desired floor) is 0.1 meter from the Speaker output.
V_magnetic_induce = (2.0e-7 * Area/Distance) * dI/dT
and we'll assume the input loop area (signal to ground) is 1cm by 4cm.
Now run the math; remember we need 0.1 microvolt feedback.
Vinduce = 2e-7Henry/meter * 1cm * 4cm /10cm * 700,000
Vinduce = 2e-7 * 0.0004meter/0.1meter * 700,000
Vinduce = 2e-7 * 0.004 * 7e+5
Vinduce = 2e-7 * 4e-3 * 7e+7 = 56 e-3 = 56 milliVolts.
The magnetic feedback, caused by having the Poweramplifer near the Preamplifier, is 56mV / 0.1 microvolt or 560,000X stronger than what "clean" music can tolerate.
$endgroup$
add a comment |
$begingroup$
A major reason for separate boxes for preamps and poweramps is the GROUND currents and also magnetic coupling. [there is numeric example, at 20KHz and 6 amps to the speakers, at end of this answer, with the Preamp only 10cm from the Power amplifier]
Suppose you built the preamp and the poweramp on the same PCB. Why not?
Some of the loudspeaker current will be flowing around on the GROUND, and end up combining with the input signal.
To minimize this "combining", make that PCB long and thin, so the PowerAmp Grounds are far away from the PreAmp Grounds.
How to improve on this? use long thing regions between the Preamp and the Poweramp.
In the extreme, a coax cable provides a long-thin-region, to ensure very small combining of input and output.
Give low millivolt signals from a vinyl record Moving Magnet cartridge, or even 0.5 millivolt from Moving Coil cartridges, that become near-100-volt audio outputs, the entire system needs 100,000:1 isolation.

simulate this circuit – Schematic created using CircuitLab
=============================================
How bad can crosstalk be? assume output current is 6 amps peak at 20,000Hz. The dI/dT is 6* d(sin(2*pi*20,000*time))/dT = 6 * 2*pi*20,000*cos(2pi20000T)
or dI/dT = 700,000 amps per second.
Assume the preamp input (remember that 1 millivolt signal from the cartridge, and you want at least 10,000:1 SNR or tonal feedback, thus 0.1 microvolt feedback is the desired floor) is 0.1 meter from the Speaker output.
V_magnetic_induce = (2.0e-7 * Area/Distance) * dI/dT
and we'll assume the input loop area (signal to ground) is 1cm by 4cm.
Now run the math; remember we need 0.1 microvolt feedback.
Vinduce = 2e-7Henry/meter * 1cm * 4cm /10cm * 700,000
Vinduce = 2e-7 * 0.0004meter/0.1meter * 700,000
Vinduce = 2e-7 * 0.004 * 7e+5
Vinduce = 2e-7 * 4e-3 * 7e+7 = 56 e-3 = 56 milliVolts.
The magnetic feedback, caused by having the Poweramplifer near the Preamplifier, is 56mV / 0.1 microvolt or 560,000X stronger than what "clean" music can tolerate.
$endgroup$
A major reason for separate boxes for preamps and poweramps is the GROUND currents and also magnetic coupling. [there is numeric example, at 20KHz and 6 amps to the speakers, at end of this answer, with the Preamp only 10cm from the Power amplifier]
Suppose you built the preamp and the poweramp on the same PCB. Why not?
Some of the loudspeaker current will be flowing around on the GROUND, and end up combining with the input signal.
To minimize this "combining", make that PCB long and thin, so the PowerAmp Grounds are far away from the PreAmp Grounds.
How to improve on this? use long thing regions between the Preamp and the Poweramp.
In the extreme, a coax cable provides a long-thin-region, to ensure very small combining of input and output.
Give low millivolt signals from a vinyl record Moving Magnet cartridge, or even 0.5 millivolt from Moving Coil cartridges, that become near-100-volt audio outputs, the entire system needs 100,000:1 isolation.

simulate this circuit – Schematic created using CircuitLab
=============================================
How bad can crosstalk be? assume output current is 6 amps peak at 20,000Hz. The dI/dT is 6* d(sin(2*pi*20,000*time))/dT = 6 * 2*pi*20,000*cos(2pi20000T)
or dI/dT = 700,000 amps per second.
Assume the preamp input (remember that 1 millivolt signal from the cartridge, and you want at least 10,000:1 SNR or tonal feedback, thus 0.1 microvolt feedback is the desired floor) is 0.1 meter from the Speaker output.
V_magnetic_induce = (2.0e-7 * Area/Distance) * dI/dT
and we'll assume the input loop area (signal to ground) is 1cm by 4cm.
Now run the math; remember we need 0.1 microvolt feedback.
Vinduce = 2e-7Henry/meter * 1cm * 4cm /10cm * 700,000
Vinduce = 2e-7 * 0.0004meter/0.1meter * 700,000
Vinduce = 2e-7 * 0.004 * 7e+5
Vinduce = 2e-7 * 4e-3 * 7e+7 = 56 e-3 = 56 milliVolts.
The magnetic feedback, caused by having the Poweramplifer near the Preamplifier, is 56mV / 0.1 microvolt or 560,000X stronger than what "clean" music can tolerate.
edited 7 mins ago
answered 1 hour ago
analogsystemsrfanalogsystemsrf
16.1k2822
16.1k2822
add a comment |
add a comment |
$begingroup$
To minimize the noise factor, which is the SNR of the output divided by the SNR of the input. An ideal amplifier should keep the SNR constant, since the input noise is amplified by the same amount as the input signal. A real amplifier, however, adds extra noise. The noise factor is given by
$$ F = 1 + fracN_mathrmadditionalN_mathrminputG.$$
If you cascade a series of amplifiers the total noise factor is given by Friis’ equation
$$F_mathrmtotal = F_1 + fracF_2 - 1G_1 + fracF_3 - 1G_1 G_2 + fracF_4 - 1G_1 G_2 G_3 + dots.$$
Where $F_n$ is the noise factor of the nth stage and $G_n$ is the gain of the nth stage. This is because the additional noise of the first stage is amplified by the second and subsequent stages but the additional noise of the second stage is amplified by only the third and subsequent stages etc.
As you can see, the the noise factor of a given stage is divided by the gain product of all previous stages. So the first stage is the most important when it comes to noise. That’s why you have a low noise pre-amp stage as your very first component in the signal chain. This configuration has the added benefit of not having to worry about the noise figure of the power amplifier.
$endgroup$
add a comment |
$begingroup$
To minimize the noise factor, which is the SNR of the output divided by the SNR of the input. An ideal amplifier should keep the SNR constant, since the input noise is amplified by the same amount as the input signal. A real amplifier, however, adds extra noise. The noise factor is given by
$$ F = 1 + fracN_mathrmadditionalN_mathrminputG.$$
If you cascade a series of amplifiers the total noise factor is given by Friis’ equation
$$F_mathrmtotal = F_1 + fracF_2 - 1G_1 + fracF_3 - 1G_1 G_2 + fracF_4 - 1G_1 G_2 G_3 + dots.$$
Where $F_n$ is the noise factor of the nth stage and $G_n$ is the gain of the nth stage. This is because the additional noise of the first stage is amplified by the second and subsequent stages but the additional noise of the second stage is amplified by only the third and subsequent stages etc.
As you can see, the the noise factor of a given stage is divided by the gain product of all previous stages. So the first stage is the most important when it comes to noise. That’s why you have a low noise pre-amp stage as your very first component in the signal chain. This configuration has the added benefit of not having to worry about the noise figure of the power amplifier.
$endgroup$
add a comment |
$begingroup$
To minimize the noise factor, which is the SNR of the output divided by the SNR of the input. An ideal amplifier should keep the SNR constant, since the input noise is amplified by the same amount as the input signal. A real amplifier, however, adds extra noise. The noise factor is given by
$$ F = 1 + fracN_mathrmadditionalN_mathrminputG.$$
If you cascade a series of amplifiers the total noise factor is given by Friis’ equation
$$F_mathrmtotal = F_1 + fracF_2 - 1G_1 + fracF_3 - 1G_1 G_2 + fracF_4 - 1G_1 G_2 G_3 + dots.$$
Where $F_n$ is the noise factor of the nth stage and $G_n$ is the gain of the nth stage. This is because the additional noise of the first stage is amplified by the second and subsequent stages but the additional noise of the second stage is amplified by only the third and subsequent stages etc.
As you can see, the the noise factor of a given stage is divided by the gain product of all previous stages. So the first stage is the most important when it comes to noise. That’s why you have a low noise pre-amp stage as your very first component in the signal chain. This configuration has the added benefit of not having to worry about the noise figure of the power amplifier.
$endgroup$
To minimize the noise factor, which is the SNR of the output divided by the SNR of the input. An ideal amplifier should keep the SNR constant, since the input noise is amplified by the same amount as the input signal. A real amplifier, however, adds extra noise. The noise factor is given by
$$ F = 1 + fracN_mathrmadditionalN_mathrminputG.$$
If you cascade a series of amplifiers the total noise factor is given by Friis’ equation
$$F_mathrmtotal = F_1 + fracF_2 - 1G_1 + fracF_3 - 1G_1 G_2 + fracF_4 - 1G_1 G_2 G_3 + dots.$$
Where $F_n$ is the noise factor of the nth stage and $G_n$ is the gain of the nth stage. This is because the additional noise of the first stage is amplified by the second and subsequent stages but the additional noise of the second stage is amplified by only the third and subsequent stages etc.
As you can see, the the noise factor of a given stage is divided by the gain product of all previous stages. So the first stage is the most important when it comes to noise. That’s why you have a low noise pre-amp stage as your very first component in the signal chain. This configuration has the added benefit of not having to worry about the noise figure of the power amplifier.
answered 39 mins ago
user110971user110971
3,4041717
3,4041717
add a comment |
add a comment |
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$begingroup$
There is also the problem of gain bandwidth product. For a given amplifier, more gain means less bandwidth. If you use too much gain in one stage, then you limit the bandwidth of that stage. This can lead to distortion - it takes gain and bandwidth for negative feedback to compensate for distortion.
$endgroup$
– JRE
1 hour ago
$begingroup$
@JRE I think in the context of the OP's he's not really talking about multiple "stages" of amplification as much as he's asking why there is both a pre-amp and an amp instead of just one amp. Inside either the pre-amp or the amp itself, it could contain as many actual stages of amplification as it wants.
$endgroup$
– Toor
1 hour ago
1
$begingroup$
You don't want the high currents (to the loudspeaker) anywhere near the input signal from the guitar pickup, or the vinyl-record signals.
$endgroup$
– analogsystemsrf
1 hour ago