Which big number is bigger? Unicorn Meta Zoo #1: Why another podcast? Announcing the arrival of Valued Associate #679: Cesar Manara Sandbox for Proposed Challenges The PPCG Site design is on its way - help us make it awesome!Determine if an Array contains something other than 2Does the sum of 2 numbers in the list equal the desired sum?Is this number a factorial?Test if two numbers are equalDo two numbers contain unique powers of 2Do two numbers contain unique factorials?Impossible cube maybeAm I divisible by double the sum of my digits?Check if a string is entirely made of the same substringWhich really big number is bigger?
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Which big number is bigger?
Unicorn Meta Zoo #1: Why another podcast?
Announcing the arrival of Valued Associate #679: Cesar Manara
Sandbox for Proposed Challenges
The PPCG Site design is on its way - help us make it awesome!Determine if an Array contains something other than 2Does the sum of 2 numbers in the list equal the desired sum?Is this number a factorial?Test if two numbers are equalDo two numbers contain unique powers of 2Do two numbers contain unique factorials?Impossible cube maybeAm I divisible by double the sum of my digits?Check if a string is entirely made of the same substringWhich really big number is bigger?
5
$begingroup$
Input
Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.
Output
True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.
^ is exponentiation in this question.
Rules
This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.
You can output anything Truthy for True and anything Falsey for False.
Test cases
3^(4^5) > 5^(4^3)
1^(2^3) < 3^(2^1)
3^(6^5) < 5^(20^3)
20^(20^20) > 20^(20^19)
20^(20^20) is not bigger than 20^(20^20)
2^2^20 > 2^20^2
code-golf
asked 1 hour ago
AnushAnush
863627
$endgroup$
|
show 10 more comments
5
$begingroup$
Input
Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.
Output
True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.
^ is exponentiation in this question.
Rules
This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.
You can output anything Truthy for True and anything Falsey for False.
Test cases
3^(4^5) > 5^(4^3)
1^(2^3) < 3^(2^1)
3^(6^5) < 5^(20^3)
20^(20^20) > 20^(20^19)
20^(20^20) is not bigger than 20^(20^20)
2^2^20 > 2^20^2
code-golf
asked 1 hour ago
AnushAnush
863627
$endgroup$
1
$begingroup$
It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to1and0
$endgroup$
– Unrelated String
1 hour ago
2
$begingroup$
Can we take the inputs in any order?
$endgroup$
– Kevin Cruijssen
1 hour ago
2
$begingroup$
@Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
$endgroup$
– Luis Mendo
59 mins ago
1
$begingroup$
@Anush It means that I could for example choose to take inputs in the order a1,b1,a2,b2,c1,c2, always in that order. Or take the inputs as a 3x2 matrix. Or as an array of arrays
$endgroup$
– Luis Mendo
48 mins ago
1
$begingroup$
suggested test case (from H.PWiz):2^2^20>2^20^2
$endgroup$
– attinat
46 mins ago
|
show 10 more comments
5
5
5
1
$begingroup$
Input
Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.
Output
True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.
^ is exponentiation in this question.
Rules
This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.
You can output anything Truthy for True and anything Falsey for False.
Test cases
3^(4^5) > 5^(4^3)
1^(2^3) < 3^(2^1)
3^(6^5) < 5^(20^3)
20^(20^20) > 20^(20^19)
20^(20^20) is not bigger than 20^(20^20)
2^2^20 > 2^20^2
code-golf
asked 1 hour ago
AnushAnush
863627
$endgroup$
Input
Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.
Output
True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.
^ is exponentiation in this question.
Rules
This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.
You can output anything Truthy for True and anything Falsey for False.
Test cases
3^(4^5) > 5^(4^3)
1^(2^3) < 3^(2^1)
3^(6^5) < 5^(20^3)
20^(20^20) > 20^(20^19)
20^(20^20) is not bigger than 20^(20^20)
2^2^20 > 2^20^2
code-golf
code-golf
asked 1 hour ago
AnushAnush
863627
asked 1 hour ago
AnushAnush
863627
edited 45 mins ago
Anush
asked 1 hour ago
AnushAnush
863627
asked 1 hour ago
AnushAnush
863627
asked 1 hour ago
AnushAnush
863627
863627
1
$begingroup$
It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to1and0
$endgroup$
– Unrelated String
1 hour ago
2
$begingroup$
Can we take the inputs in any order?
$endgroup$
– Kevin Cruijssen
1 hour ago
2
$begingroup$
@Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
$endgroup$
– Luis Mendo
59 mins ago
1
$begingroup$
@Anush It means that I could for example choose to take inputs in the order a1,b1,a2,b2,c1,c2, always in that order. Or take the inputs as a 3x2 matrix. Or as an array of arrays
$endgroup$
– Luis Mendo
48 mins ago
1
$begingroup$
suggested test case (from H.PWiz):2^2^20>2^20^2
$endgroup$
– attinat
46 mins ago
|
show 10 more comments
1
$begingroup$
It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to1and0
$endgroup$
– Unrelated String
1 hour ago
2
$begingroup$
Can we take the inputs in any order?
$endgroup$
– Kevin Cruijssen
1 hour ago
2
$begingroup$
@Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
$endgroup$
– Luis Mendo
59 mins ago
1
$begingroup$
@Anush It means that I could for example choose to take inputs in the order a1,b1,a2,b2,c1,c2, always in that order. Or take the inputs as a 3x2 matrix. Or as an array of arrays
$endgroup$
– Luis Mendo
48 mins ago
1
$begingroup$
suggested test case (from H.PWiz):2^2^20>2^20^2
$endgroup$
– attinat
46 mins ago
1
1
$begingroup$
It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to
1 and 0$endgroup$
– Unrelated String
1 hour ago
$begingroup$
It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to
1 and 0$endgroup$
– Unrelated String
1 hour ago
2
2
$begingroup$
Can we take the inputs in any order?
$endgroup$
– Kevin Cruijssen
1 hour ago
$begingroup$
Can we take the inputs in any order?
$endgroup$
– Kevin Cruijssen
1 hour ago
2
2
$begingroup$
@Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
$endgroup$
– Luis Mendo
59 mins ago
$begingroup$
@Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
$endgroup$
– Luis Mendo
59 mins ago
1
1
$begingroup$
@Anush It means that I could for example choose to take inputs in the order a1,b1,a2,b2,c1,c2, always in that order. Or take the inputs as a 3x2 matrix. Or as an array of arrays
$endgroup$
– Luis Mendo
48 mins ago
$begingroup$
@Anush It means that I could for example choose to take inputs in the order a1,b1,a2,b2,c1,c2, always in that order. Or take the inputs as a 3x2 matrix. Or as an array of arrays
$endgroup$
– Luis Mendo
48 mins ago
1
1
$begingroup$
suggested test case (from H.PWiz):
2^2^20>2^20^2$endgroup$
– attinat
46 mins ago
$begingroup$
suggested test case (from H.PWiz):
2^2^20>2^20^2$endgroup$
– attinat
46 mins ago
|
show 10 more comments
5 Answers
5
active
oldest
votes
6
$begingroup$
JavaScript (ES7), 45 bytes
Fixed thanks to @H.PWiz
Returns $true$ if $a^b^c > d^e^f$, or $false$ otherwise.
(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)
Try it online!
answered 1 hour ago
ArnauldArnauld
82.2k798338
$endgroup$
1
$begingroup$
Eheh we had the same idea... and almost the same byte count :P
$endgroup$
– digEmAll
1 hour ago
4
$begingroup$
Shouldn't it be(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)? Yours givesfalseforf(2,2,20,2,20,2)
$endgroup$
– H.PWiz
50 mins ago
$begingroup$
@H.PWiz Indeed! Thanks. :)
$endgroup$
– Arnauld
43 mins ago
add a comment |
4
$begingroup$
R, 42 bytes
function(a,b,c,d,e,f)b^c*log(a)>e^f*log(d)
Try it online!
- Fixed the "symmetry problem" thanks to @H.PWiz suggestion
answered 1 hour ago
digEmAlldigEmAll
3,664515
$endgroup$
4
$begingroup$
This is wrong forf(2,2,20,2,20,2)
$endgroup$
– H.PWiz
49 mins ago
$begingroup$
Fixed, using your suggestion to @Arnauld answer ;)
$endgroup$
– digEmAll
23 mins ago
add a comment |
3
$begingroup$
05AB1E, 11 9 bytes
εć.²š}P`›
Port of @Arnauld's JavaScript and @digEmAll's R approaches (I saw them post around the same time)
-2 bytes thanks to @Emigna
Input as [[a1,a2,a3],[b1,b2,b3]].
Try it online or verify all test cases.
Explanation:
ε # Map the (implicit) input-lists to:
ć # Extract the head; pushing the remainder and head separated to the stack
.² # Get the logarithm with base 2 of this head
š # And prepend it back to the remainder
}P # After the map: take the product of both mapped inner lists
` # Push both integers separated to the stack
› # And check if A is larger than B
answered 1 hour ago
Kevin CruijssenKevin Cruijssen
43.5k573222
$endgroup$
1
$begingroup$
You second version can be εć.²š]P`›
$endgroup$
– Emigna
1 hour ago
$begingroup$
@Emigna Ah nice, I was looking at an approach withć, but completely forgot about usingš(not sure why now that I see it, haha). Thanks!
$endgroup$
– Kevin Cruijssen
1 hour ago
$begingroup$
This seems to be incorrect (because Arnauld's answer was incorrect until the recent fix).
$endgroup$
– Anush
42 mins ago
add a comment |
2
$begingroup$
Wolfram Language (Mathematica), 23 bytes
#2^#3Log@#>#5^#6Log@#4&
Try it online!
answered 1 hour ago
J42161217J42161217
14.4k21354
$endgroup$
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush fixed...
$endgroup$
– J42161217
1 hour ago
add a comment |
2
$begingroup$
05AB1E, 13 bytes
Uses the method from Arnauld's JS answer
2F.²IIm*ˆ}¯`›
Try it online!
answered 1 hour ago
EmignaEmigna
48.3k434147
$endgroup$
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
1
$begingroup$
@Anush: Seems to terminate in less than a second to me.
$endgroup$
– Emigna
1 hour ago
$begingroup$
you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush: Ah, you meantb1=b2=b3=20,yeah that doesn't terminate.
$endgroup$
– Emigna
1 hour ago
1
$begingroup$
@Anush: It is fixed now. Thanks for pointing out my mistake :)
$endgroup$
– Emigna
1 hour ago
|
show 4 more comments
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
6
$begingroup$
JavaScript (ES7), 45 bytes
Fixed thanks to @H.PWiz
Returns $true$ if $a^b^c > d^e^f$, or $false$ otherwise.
(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)
Try it online!
answered 1 hour ago
ArnauldArnauld
82.2k798338
$endgroup$
1
$begingroup$
Eheh we had the same idea... and almost the same byte count :P
$endgroup$
– digEmAll
1 hour ago
4
$begingroup$
Shouldn't it be(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)? Yours givesfalseforf(2,2,20,2,20,2)
$endgroup$
– H.PWiz
50 mins ago
$begingroup$
@H.PWiz Indeed! Thanks. :)
$endgroup$
– Arnauld
43 mins ago
add a comment |
6
$begingroup$
JavaScript (ES7), 45 bytes
Fixed thanks to @H.PWiz
Returns $true$ if $a^b^c > d^e^f$, or $false$ otherwise.
(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)
Try it online!
answered 1 hour ago
ArnauldArnauld
82.2k798338
$endgroup$
1
$begingroup$
Eheh we had the same idea... and almost the same byte count :P
$endgroup$
– digEmAll
1 hour ago
4
$begingroup$
Shouldn't it be(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)? Yours givesfalseforf(2,2,20,2,20,2)
$endgroup$
– H.PWiz
50 mins ago
$begingroup$
@H.PWiz Indeed! Thanks. :)
$endgroup$
– Arnauld
43 mins ago
add a comment |
6
6
6
$begingroup$
JavaScript (ES7), 45 bytes
Fixed thanks to @H.PWiz
Returns $true$ if $a^b^c > d^e^f$, or $false$ otherwise.
(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)
Try it online!
answered 1 hour ago
ArnauldArnauld
82.2k798338
$endgroup$
JavaScript (ES7), 45 bytes
Fixed thanks to @H.PWiz
Returns $true$ if $a^b^c > d^e^f$, or $false$ otherwise.
(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)
Try it online!
answered 1 hour ago
ArnauldArnauld
82.2k798338
edited 44 mins ago
answered 1 hour ago
ArnauldArnauld
82.2k798338
answered 1 hour ago
ArnauldArnauld
82.2k798338
answered 1 hour ago
ArnauldArnauld
82.2k798338
82.2k798338
1
$begingroup$
Eheh we had the same idea... and almost the same byte count :P
$endgroup$
– digEmAll
1 hour ago
4
$begingroup$
Shouldn't it be(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)? Yours givesfalseforf(2,2,20,2,20,2)
$endgroup$
– H.PWiz
50 mins ago
$begingroup$
@H.PWiz Indeed! Thanks. :)
$endgroup$
– Arnauld
43 mins ago
add a comment |
1
$begingroup$
Eheh we had the same idea... and almost the same byte count :P
$endgroup$
– digEmAll
1 hour ago
4
$begingroup$
Shouldn't it be(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)? Yours givesfalseforf(2,2,20,2,20,2)
$endgroup$
– H.PWiz
50 mins ago
$begingroup$
@H.PWiz Indeed! Thanks. :)
$endgroup$
– Arnauld
43 mins ago
1
1
$begingroup$
Eheh we had the same idea... and almost the same byte count :P
$endgroup$
– digEmAll
1 hour ago
$begingroup$
Eheh we had the same idea... and almost the same byte count :P
$endgroup$
– digEmAll
1 hour ago
4
4
$begingroup$
Shouldn't it be
(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)? Yours gives false for f(2,2,20,2,20,2)$endgroup$
– H.PWiz
50 mins ago
$begingroup$
Shouldn't it be
(a,b,c,d,e,f)=>b**c*(l=Math.log)(a)>e**f*l(d)? Yours gives false for f(2,2,20,2,20,2)$endgroup$
– H.PWiz
50 mins ago
$begingroup$
@H.PWiz Indeed! Thanks. :)
$endgroup$
– Arnauld
43 mins ago
$begingroup$
@H.PWiz Indeed! Thanks. :)
$endgroup$
– Arnauld
43 mins ago
add a comment |
4
$begingroup$
R, 42 bytes
function(a,b,c,d,e,f)b^c*log(a)>e^f*log(d)
Try it online!
- Fixed the "symmetry problem" thanks to @H.PWiz suggestion
answered 1 hour ago
digEmAlldigEmAll
3,664515
$endgroup$
4
$begingroup$
This is wrong forf(2,2,20,2,20,2)
$endgroup$
– H.PWiz
49 mins ago
$begingroup$
Fixed, using your suggestion to @Arnauld answer ;)
$endgroup$
– digEmAll
23 mins ago
add a comment |
4
$begingroup$
R, 42 bytes
function(a,b,c,d,e,f)b^c*log(a)>e^f*log(d)
Try it online!
- Fixed the "symmetry problem" thanks to @H.PWiz suggestion
answered 1 hour ago
digEmAlldigEmAll
3,664515
$endgroup$
4
$begingroup$
This is wrong forf(2,2,20,2,20,2)
$endgroup$
– H.PWiz
49 mins ago
$begingroup$
Fixed, using your suggestion to @Arnauld answer ;)
$endgroup$
– digEmAll
23 mins ago
add a comment |
4
4
4
$begingroup$
R, 42 bytes
function(a,b,c,d,e,f)b^c*log(a)>e^f*log(d)
Try it online!
- Fixed the "symmetry problem" thanks to @H.PWiz suggestion
answered 1 hour ago
digEmAlldigEmAll
3,664515
$endgroup$
R, 42 bytes
function(a,b,c,d,e,f)b^c*log(a)>e^f*log(d)
Try it online!
- Fixed the "symmetry problem" thanks to @H.PWiz suggestion
answered 1 hour ago
digEmAlldigEmAll
3,664515
edited 18 mins ago
answered 1 hour ago
digEmAlldigEmAll
3,664515
answered 1 hour ago
digEmAlldigEmAll
3,664515
answered 1 hour ago
digEmAlldigEmAll
3,664515
3,664515
4
$begingroup$
This is wrong forf(2,2,20,2,20,2)
$endgroup$
– H.PWiz
49 mins ago
$begingroup$
Fixed, using your suggestion to @Arnauld answer ;)
$endgroup$
– digEmAll
23 mins ago
add a comment |
4
$begingroup$
This is wrong forf(2,2,20,2,20,2)
$endgroup$
– H.PWiz
49 mins ago
$begingroup$
Fixed, using your suggestion to @Arnauld answer ;)
$endgroup$
– digEmAll
23 mins ago
4
4
$begingroup$
This is wrong for
f(2,2,20,2,20,2)$endgroup$
– H.PWiz
49 mins ago
$begingroup$
This is wrong for
f(2,2,20,2,20,2)$endgroup$
– H.PWiz
49 mins ago
$begingroup$
Fixed, using your suggestion to @Arnauld answer ;)
$endgroup$
– digEmAll
23 mins ago
$begingroup$
Fixed, using your suggestion to @Arnauld answer ;)
$endgroup$
– digEmAll
23 mins ago
add a comment |
3
$begingroup$
05AB1E, 11 9 bytes
εć.²š}P`›
Port of @Arnauld's JavaScript and @digEmAll's R approaches (I saw them post around the same time)
-2 bytes thanks to @Emigna
Input as [[a1,a2,a3],[b1,b2,b3]].
Try it online or verify all test cases.
Explanation:
ε # Map the (implicit) input-lists to:
ć # Extract the head; pushing the remainder and head separated to the stack
.² # Get the logarithm with base 2 of this head
š # And prepend it back to the remainder
}P # After the map: take the product of both mapped inner lists
` # Push both integers separated to the stack
› # And check if A is larger than B
answered 1 hour ago
Kevin CruijssenKevin Cruijssen
43.5k573222
$endgroup$
1
$begingroup$
You second version can be εć.²š]P`›
$endgroup$
– Emigna
1 hour ago
$begingroup$
@Emigna Ah nice, I was looking at an approach withć, but completely forgot about usingš(not sure why now that I see it, haha). Thanks!
$endgroup$
– Kevin Cruijssen
1 hour ago
$begingroup$
This seems to be incorrect (because Arnauld's answer was incorrect until the recent fix).
$endgroup$
– Anush
42 mins ago
add a comment |
3
$begingroup$
05AB1E, 11 9 bytes
εć.²š}P`›
Port of @Arnauld's JavaScript and @digEmAll's R approaches (I saw them post around the same time)
-2 bytes thanks to @Emigna
Input as [[a1,a2,a3],[b1,b2,b3]].
Try it online or verify all test cases.
Explanation:
ε # Map the (implicit) input-lists to:
ć # Extract the head; pushing the remainder and head separated to the stack
.² # Get the logarithm with base 2 of this head
š # And prepend it back to the remainder
}P # After the map: take the product of both mapped inner lists
` # Push both integers separated to the stack
› # And check if A is larger than B
answered 1 hour ago
Kevin CruijssenKevin Cruijssen
43.5k573222
$endgroup$
1
$begingroup$
You second version can be εć.²š]P`›
$endgroup$
– Emigna
1 hour ago
$begingroup$
@Emigna Ah nice, I was looking at an approach withć, but completely forgot about usingš(not sure why now that I see it, haha). Thanks!
$endgroup$
– Kevin Cruijssen
1 hour ago
$begingroup$
This seems to be incorrect (because Arnauld's answer was incorrect until the recent fix).
$endgroup$
– Anush
42 mins ago
add a comment |
3
3
3
$begingroup$
05AB1E, 11 9 bytes
εć.²š}P`›
Port of @Arnauld's JavaScript and @digEmAll's R approaches (I saw them post around the same time)
-2 bytes thanks to @Emigna
Input as [[a1,a2,a3],[b1,b2,b3]].
Try it online or verify all test cases.
Explanation:
ε # Map the (implicit) input-lists to:
ć # Extract the head; pushing the remainder and head separated to the stack
.² # Get the logarithm with base 2 of this head
š # And prepend it back to the remainder
}P # After the map: take the product of both mapped inner lists
` # Push both integers separated to the stack
› # And check if A is larger than B
answered 1 hour ago
Kevin CruijssenKevin Cruijssen
43.5k573222
$endgroup$
05AB1E, 11 9 bytes
εć.²š}P`›
Port of @Arnauld's JavaScript and @digEmAll's R approaches (I saw them post around the same time)
-2 bytes thanks to @Emigna
Input as [[a1,a2,a3],[b1,b2,b3]].
Try it online or verify all test cases.
Explanation:
ε # Map the (implicit) input-lists to:
ć # Extract the head; pushing the remainder and head separated to the stack
.² # Get the logarithm with base 2 of this head
š # And prepend it back to the remainder
}P # After the map: take the product of both mapped inner lists
` # Push both integers separated to the stack
› # And check if A is larger than B
answered 1 hour ago
Kevin CruijssenKevin Cruijssen
43.5k573222
edited 1 hour ago
answered 1 hour ago
Kevin CruijssenKevin Cruijssen
43.5k573222
answered 1 hour ago
Kevin CruijssenKevin Cruijssen
43.5k573222
answered 1 hour ago
Kevin CruijssenKevin Cruijssen
43.5k573222
43.5k573222
1
$begingroup$
You second version can be εć.²š]P`›
$endgroup$
– Emigna
1 hour ago
$begingroup$
@Emigna Ah nice, I was looking at an approach withć, but completely forgot about usingš(not sure why now that I see it, haha). Thanks!
$endgroup$
– Kevin Cruijssen
1 hour ago
$begingroup$
This seems to be incorrect (because Arnauld's answer was incorrect until the recent fix).
$endgroup$
– Anush
42 mins ago
add a comment |
1
$begingroup$
You second version can be εć.²š]P`›
$endgroup$
– Emigna
1 hour ago
$begingroup$
@Emigna Ah nice, I was looking at an approach withć, but completely forgot about usingš(not sure why now that I see it, haha). Thanks!
$endgroup$
– Kevin Cruijssen
1 hour ago
$begingroup$
This seems to be incorrect (because Arnauld's answer was incorrect until the recent fix).
$endgroup$
– Anush
42 mins ago
1
1
$begingroup$
You second version can be εć.²š]P`›
$endgroup$
– Emigna
1 hour ago
$begingroup$
You second version can be εć.²š]P`›
$endgroup$
– Emigna
1 hour ago
$begingroup$
@Emigna Ah nice, I was looking at an approach with
ć, but completely forgot about using š (not sure why now that I see it, haha). Thanks!$endgroup$
– Kevin Cruijssen
1 hour ago
$begingroup$
@Emigna Ah nice, I was looking at an approach with
ć, but completely forgot about using š (not sure why now that I see it, haha). Thanks!$endgroup$
– Kevin Cruijssen
1 hour ago
$begingroup$
This seems to be incorrect (because Arnauld's answer was incorrect until the recent fix).
$endgroup$
– Anush
42 mins ago
$begingroup$
This seems to be incorrect (because Arnauld's answer was incorrect until the recent fix).
$endgroup$
– Anush
42 mins ago
add a comment |
2
$begingroup$
Wolfram Language (Mathematica), 23 bytes
#2^#3Log@#>#5^#6Log@#4&
Try it online!
answered 1 hour ago
J42161217J42161217
14.4k21354
$endgroup$
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush fixed...
$endgroup$
– J42161217
1 hour ago
add a comment |
2
$begingroup$
Wolfram Language (Mathematica), 23 bytes
#2^#3Log@#>#5^#6Log@#4&
Try it online!
answered 1 hour ago
J42161217J42161217
14.4k21354
$endgroup$
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush fixed...
$endgroup$
– J42161217
1 hour ago
add a comment |
2
2
2
$begingroup$
Wolfram Language (Mathematica), 23 bytes
#2^#3Log@#>#5^#6Log@#4&
Try it online!
answered 1 hour ago
J42161217J42161217
14.4k21354
$endgroup$
Wolfram Language (Mathematica), 23 bytes
#2^#3Log@#>#5^#6Log@#4&
Try it online!
answered 1 hour ago
J42161217J42161217
14.4k21354
edited 1 hour ago
answered 1 hour ago
J42161217J42161217
14.4k21354
answered 1 hour ago
J42161217J42161217
14.4k21354
answered 1 hour ago
J42161217J42161217
14.4k21354
14.4k21354
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush fixed...
$endgroup$
– J42161217
1 hour ago
add a comment |
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush fixed...
$endgroup$
– J42161217
1 hour ago
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush fixed...
$endgroup$
– J42161217
1 hour ago
$begingroup$
@Anush fixed...
$endgroup$
– J42161217
1 hour ago
add a comment |
2
$begingroup$
05AB1E, 13 bytes
Uses the method from Arnauld's JS answer
2F.²IIm*ˆ}¯`›
Try it online!
answered 1 hour ago
EmignaEmigna
48.3k434147
$endgroup$
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
1
$begingroup$
@Anush: Seems to terminate in less than a second to me.
$endgroup$
– Emigna
1 hour ago
$begingroup$
you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush: Ah, you meantb1=b2=b3=20,yeah that doesn't terminate.
$endgroup$
– Emigna
1 hour ago
1
$begingroup$
@Anush: It is fixed now. Thanks for pointing out my mistake :)
$endgroup$
– Emigna
1 hour ago
|
show 4 more comments
2
$begingroup$
05AB1E, 13 bytes
Uses the method from Arnauld's JS answer
2F.²IIm*ˆ}¯`›
Try it online!
answered 1 hour ago
EmignaEmigna
48.3k434147
$endgroup$
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
1
$begingroup$
@Anush: Seems to terminate in less than a second to me.
$endgroup$
– Emigna
1 hour ago
$begingroup$
you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush: Ah, you meantb1=b2=b3=20,yeah that doesn't terminate.
$endgroup$
– Emigna
1 hour ago
1
$begingroup$
@Anush: It is fixed now. Thanks for pointing out my mistake :)
$endgroup$
– Emigna
1 hour ago
|
show 4 more comments
2
2
2
$begingroup$
05AB1E, 13 bytes
Uses the method from Arnauld's JS answer
2F.²IIm*ˆ}¯`›
Try it online!
answered 1 hour ago
EmignaEmigna
48.3k434147
$endgroup$
05AB1E, 13 bytes
Uses the method from Arnauld's JS answer
2F.²IIm*ˆ}¯`›
Try it online!
answered 1 hour ago
EmignaEmigna
48.3k434147
edited 15 mins ago
answered 1 hour ago
EmignaEmigna
48.3k434147
answered 1 hour ago
EmignaEmigna
48.3k434147
answered 1 hour ago
EmignaEmigna
48.3k434147
48.3k434147
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
1
$begingroup$
@Anush: Seems to terminate in less than a second to me.
$endgroup$
– Emigna
1 hour ago
$begingroup$
you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush: Ah, you meantb1=b2=b3=20,yeah that doesn't terminate.
$endgroup$
– Emigna
1 hour ago
1
$begingroup$
@Anush: It is fixed now. Thanks for pointing out my mistake :)
$endgroup$
– Emigna
1 hour ago
|
show 4 more comments
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
1
$begingroup$
@Anush: Seems to terminate in less than a second to me.
$endgroup$
– Emigna
1 hour ago
$begingroup$
you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush: Ah, you meantb1=b2=b3=20,yeah that doesn't terminate.
$endgroup$
– Emigna
1 hour ago
1
$begingroup$
@Anush: It is fixed now. Thanks for pointing out my mistake :)
$endgroup$
– Emigna
1 hour ago
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
$begingroup$
This doesn't terminate for a1=20, a2=20, a3=20.
$endgroup$
– Anush
1 hour ago
1
1
$begingroup$
@Anush: Seems to terminate in less than a second to me.
$endgroup$
– Emigna
1 hour ago
$begingroup$
@Anush: Seems to terminate in less than a second to me.
$endgroup$
– Emigna
1 hour ago
$begingroup$
you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
$endgroup$
– Anush
1 hour ago
$begingroup$
you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
$endgroup$
– Anush
1 hour ago
$begingroup$
@Anush: Ah, you meant
b1=b2=b3=20 ,yeah that doesn't terminate.$endgroup$
– Emigna
1 hour ago
$begingroup$
@Anush: Ah, you meant
b1=b2=b3=20 ,yeah that doesn't terminate.$endgroup$
– Emigna
1 hour ago
1
1
$begingroup$
@Anush: It is fixed now. Thanks for pointing out my mistake :)
$endgroup$
– Emigna
1 hour ago
$begingroup$
@Anush: It is fixed now. Thanks for pointing out my mistake :)
$endgroup$
– Emigna
1 hour ago
|
show 4 more comments
draft saved
draft discarded
If this is an answer to a challenge…
…Be sure to follow the challenge specification. However, please refrain from exploiting obvious loopholes. Answers abusing any of the standard loopholes are considered invalid. If you think a specification is unclear or underspecified, comment on the question instead.
…Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one.
Explanations of your answer make it more interesting to read and are very much encouraged.…Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.
More generally…
…Please make sure to answer the question and provide sufficient detail.
…Avoid asking for help, clarification or responding to other answers (use comments instead).
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1
$begingroup$
It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to
1and0$endgroup$
– Unrelated String
1 hour ago
2
$begingroup$
Can we take the inputs in any order?
$endgroup$
– Kevin Cruijssen
1 hour ago
2
$begingroup$
@Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
$endgroup$
– Luis Mendo
59 mins ago
1
$begingroup$
@Anush It means that I could for example choose to take inputs in the order a1,b1,a2,b2,c1,c2, always in that order. Or take the inputs as a 3x2 matrix. Or as an array of arrays
$endgroup$
– Luis Mendo
48 mins ago
1
$begingroup$
suggested test case (from H.PWiz):
2^2^20>2^20^2$endgroup$
– attinat
46 mins ago