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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

1

1

I have directory say /var/tmp/abc which has 4 files as -

12345-ram-3e3r5-io9490-89adu9.csv

45434-dam-qwe35-to9490-43adu9.csv

11234-cam-yy3r5-ro9490-85adu9.csv

14423-sam-hh3r5-uo9490-869du9.csv

I want to rename all the csv files (find all the files & rename them) in shortest possible(probably one liner) way that,

XXXXX-ram-3e3r5-io9490-89adu9.csv

XXXXX-dam-qwe35-to9490-43adu9.csv

XXXXX-cam-yy3r5-ro9490-85adu9.csv

XXXXX-sam-hh3r5-uo9490-869du9.csv

bash shell ksh

share

edited 4 hours ago

Rocky86

asked 4 hours ago

Rocky86Rocky86

7919

add a comment | 

1

1

I have directory say /var/tmp/abc which has 4 files as -

12345-ram-3e3r5-io9490-89adu9.csv

45434-dam-qwe35-to9490-43adu9.csv

11234-cam-yy3r5-ro9490-85adu9.csv

14423-sam-hh3r5-uo9490-869du9.csv

I want to rename all the csv files (find all the files & rename them) in shortest possible(probably one liner) way that,

XXXXX-ram-3e3r5-io9490-89adu9.csv

XXXXX-dam-qwe35-to9490-43adu9.csv

XXXXX-cam-yy3r5-ro9490-85adu9.csv

XXXXX-sam-hh3r5-uo9490-869du9.csv

bash shell ksh

share

edited 4 hours ago

Rocky86

asked 4 hours ago

Rocky86Rocky86

7919

add a comment | 

I have directory say /var/tmp/abc which has 4 files as -

12345-ram-3e3r5-io9490-89adu9.csv

45434-dam-qwe35-to9490-43adu9.csv

11234-cam-yy3r5-ro9490-85adu9.csv

14423-sam-hh3r5-uo9490-869du9.csv

I want to rename all the csv files (find all the files & rename them) in shortest possible(probably one liner) way that,

XXXXX-ram-3e3r5-io9490-89adu9.csv

XXXXX-dam-qwe35-to9490-43adu9.csv

XXXXX-cam-yy3r5-ro9490-85adu9.csv

XXXXX-sam-hh3r5-uo9490-869du9.csv

bash shell ksh

share

edited 4 hours ago

Rocky86

asked 4 hours ago

Rocky86Rocky86

7919

share

edited 4 hours ago

Rocky86

asked 4 hours ago

Rocky86Rocky86

7919

share

edited 4 hours ago

Rocky86

asked 4 hours ago

Rocky86Rocky86

7919

asked 4 hours ago

Rocky86Rocky86

7919

asked 4 hours ago

Rocky86Rocky86

7919

3 Answers
3

active

oldest

votes

2

Try:

for f in *.csv; do mv -i -- "$f" "XXXXX-$f#*-"; done

How it works:

• 
  

  for f in *.csv; do

  
  
  

  This starts a loop over all *.csv files.

  
  


• 
  

  mv -i -- "$f" "XXXXX-$f#*-"

  
  
  

  This renames the files as you want, asking interactively before overwriting any file.

  
  


• 
  

  done

  
  
  

  This marks the end of the loop.

  
  

Example:

$ ls -1
11234-cam-yy3r5-ro9490-85adu9.csv
12345-ram-3e3r5-io9490-89adu9.csv
14423-sam-hh3r5-uo9490-869du9.csv
45434-dam-qwe35-to9490-43adu9.csv
$ for f in *.csv; do mv -i -- "$f" "XXXXX-$f#*-"; done
$ ls -1
XXXXX-cam-yy3r5-ro9490-85adu9.csv
XXXXX-dam-qwe35-to9490-43adu9.csv
XXXXX-ram-3e3r5-io9490-89adu9.csv
XXXXX-sam-hh3r5-uo9490-869du9.csv

share|improve this answer

answered 4 hours ago

John1024John1024

49.3k5114129

add a comment | 

2

rename -n 's/(w+)/XXXXX/' *.csv

remove the -n when happy.

share|improve this answer

answered 3 hours ago

SHawardenSHawarden

312

New contributor

SHawarden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

1

I liked the little challenge that you've posted, so here is my solution. I'm assuming that all your files starts with 5 numeric characters, so using the cut command to replace the initial numeric files by "XXXXX".

Below, the files before the command.

-rw-rw-r--. 1 daniel daniel 0 May 13 23:18 11111_bar_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 12345_baz_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 67890_foo_file.xml

Below, the one liner command.

for src in *.csv; do dst=XXXXX$(echo $src| cut -c6-); mv $src $dst; done;

Below, the files after the command.

-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 67890_foo_file.xml
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 XXXXX_bar_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 23:18 XXXXX_baz_file.csv

Is that what you're looking for? :)

References:

Looping through command output in bash

Substrings in bash

share|improve this answer

edited 3 hours ago

answered 4 hours ago

danieldeveloper001danieldeveloper001

1215

New contributor

danieldeveloper001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

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2

Try:

for f in *.csv; do mv -i -- "$f" "XXXXX-$f#*-"; done

How it works:

• 
  

  for f in *.csv; do

  
  
  

  This starts a loop over all *.csv files.

  
  


• 
  

  mv -i -- "$f" "XXXXX-$f#*-"

  
  
  

  This renames the files as you want, asking interactively before overwriting any file.

  
  


• 
  

  done

  
  
  

  This marks the end of the loop.

  
  

Example:

$ ls -1
11234-cam-yy3r5-ro9490-85adu9.csv
12345-ram-3e3r5-io9490-89adu9.csv
14423-sam-hh3r5-uo9490-869du9.csv
45434-dam-qwe35-to9490-43adu9.csv
$ for f in *.csv; do mv -i -- "$f" "XXXXX-$f#*-"; done
$ ls -1
XXXXX-cam-yy3r5-ro9490-85adu9.csv
XXXXX-dam-qwe35-to9490-43adu9.csv
XXXXX-ram-3e3r5-io9490-89adu9.csv
XXXXX-sam-hh3r5-uo9490-869du9.csv

share|improve this answer

answered 4 hours ago

John1024John1024

49.3k5114129

add a comment | 

2

Try:

for f in *.csv; do mv -i -- "$f" "XXXXX-$f#*-"; done

How it works:

• 
  

  for f in *.csv; do

  
  
  

  This starts a loop over all *.csv files.

  
  


• 
  

  mv -i -- "$f" "XXXXX-$f#*-"

  
  
  

  This renames the files as you want, asking interactively before overwriting any file.

  
  


• 
  

  done

  
  
  

  This marks the end of the loop.

  
  

Example:

$ ls -1
11234-cam-yy3r5-ro9490-85adu9.csv
12345-ram-3e3r5-io9490-89adu9.csv
14423-sam-hh3r5-uo9490-869du9.csv
45434-dam-qwe35-to9490-43adu9.csv
$ for f in *.csv; do mv -i -- "$f" "XXXXX-$f#*-"; done
$ ls -1
XXXXX-cam-yy3r5-ro9490-85adu9.csv
XXXXX-dam-qwe35-to9490-43adu9.csv
XXXXX-ram-3e3r5-io9490-89adu9.csv
XXXXX-sam-hh3r5-uo9490-869du9.csv

share|improve this answer

answered 4 hours ago

John1024John1024

49.3k5114129

add a comment | 

Try:

for f in *.csv; do mv -i -- "$f" "XXXXX-$f#*-"; done

How it works:

• 
  

  for f in *.csv; do

  
  
  

  This starts a loop over all *.csv files.

  
  


• 
  

  mv -i -- "$f" "XXXXX-$f#*-"

  
  
  

  This renames the files as you want, asking interactively before overwriting any file.

  
  


• 
  

  done

  
  
  

  This marks the end of the loop.

  
  

Example:

$ ls -1
11234-cam-yy3r5-ro9490-85adu9.csv
12345-ram-3e3r5-io9490-89adu9.csv
14423-sam-hh3r5-uo9490-869du9.csv
45434-dam-qwe35-to9490-43adu9.csv
$ for f in *.csv; do mv -i -- "$f" "XXXXX-$f#*-"; done
$ ls -1
XXXXX-cam-yy3r5-ro9490-85adu9.csv
XXXXX-dam-qwe35-to9490-43adu9.csv
XXXXX-ram-3e3r5-io9490-89adu9.csv
XXXXX-sam-hh3r5-uo9490-869du9.csv

share|improve this answer

answered 4 hours ago

John1024John1024

49.3k5114129

for f in *.csv; do mv -i -- "$f" "XXXXX-$f#*-"; done

$ ls -1
11234-cam-yy3r5-ro9490-85adu9.csv
12345-ram-3e3r5-io9490-89adu9.csv
14423-sam-hh3r5-uo9490-869du9.csv
45434-dam-qwe35-to9490-43adu9.csv
$ for f in *.csv; do mv -i -- "$f" "XXXXX-$f#*-"; done
$ ls -1
XXXXX-cam-yy3r5-ro9490-85adu9.csv
XXXXX-dam-qwe35-to9490-43adu9.csv
XXXXX-ram-3e3r5-io9490-89adu9.csv
XXXXX-sam-hh3r5-uo9490-869du9.csv

share|improve this answer

answered 4 hours ago

John1024John1024

49.3k5114129

answered 4 hours ago

John1024John1024

49.3k5114129

answered 4 hours ago

John1024John1024

49.3k5114129

2

rename -n 's/(w+)/XXXXX/' *.csv

remove the -n when happy.

share|improve this answer

answered 3 hours ago

SHawardenSHawarden

312

New contributor

SHawarden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

2

rename -n 's/(w+)/XXXXX/' *.csv

remove the -n when happy.

share|improve this answer

answered 3 hours ago

SHawardenSHawarden

312

New contributor

SHawarden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

rename -n 's/(w+)/XXXXX/' *.csv

remove the -n when happy.

share|improve this answer

answered 3 hours ago

SHawardenSHawarden

312

New contributor

SHawarden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this answer

answered 3 hours ago

SHawardenSHawarden

312

New contributor

SHawarden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered 3 hours ago

SHawardenSHawarden

312

New contributor

SHawarden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered 3 hours ago

SHawardenSHawarden

312

1

I liked the little challenge that you've posted, so here is my solution. I'm assuming that all your files starts with 5 numeric characters, so using the cut command to replace the initial numeric files by "XXXXX".

Below, the files before the command.

-rw-rw-r--. 1 daniel daniel 0 May 13 23:18 11111_bar_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 12345_baz_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 67890_foo_file.xml

Below, the one liner command.

for src in *.csv; do dst=XXXXX$(echo $src| cut -c6-); mv $src $dst; done;

Below, the files after the command.

-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 67890_foo_file.xml
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 XXXXX_bar_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 23:18 XXXXX_baz_file.csv

Is that what you're looking for? :)

References:

Looping through command output in bash

Substrings in bash

share|improve this answer

edited 3 hours ago

answered 4 hours ago

danieldeveloper001danieldeveloper001

1215

New contributor

danieldeveloper001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

1

I liked the little challenge that you've posted, so here is my solution. I'm assuming that all your files starts with 5 numeric characters, so using the cut command to replace the initial numeric files by "XXXXX".

Below, the files before the command.

-rw-rw-r--. 1 daniel daniel 0 May 13 23:18 11111_bar_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 12345_baz_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 67890_foo_file.xml

Below, the one liner command.

for src in *.csv; do dst=XXXXX$(echo $src| cut -c6-); mv $src $dst; done;

Below, the files after the command.

-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 67890_foo_file.xml
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 XXXXX_bar_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 23:18 XXXXX_baz_file.csv

Is that what you're looking for? :)

References:

Looping through command output in bash

Substrings in bash

share|improve this answer

edited 3 hours ago

answered 4 hours ago

danieldeveloper001danieldeveloper001

1215

New contributor

danieldeveloper001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

I liked the little challenge that you've posted, so here is my solution. I'm assuming that all your files starts with 5 numeric characters, so using the cut command to replace the initial numeric files by "XXXXX".

Below, the files before the command.

-rw-rw-r--. 1 daniel daniel 0 May 13 23:18 11111_bar_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 12345_baz_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 67890_foo_file.xml

Below, the one liner command.

for src in *.csv; do dst=XXXXX$(echo $src| cut -c6-); mv $src $dst; done;

Below, the files after the command.

-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 67890_foo_file.xml
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 XXXXX_bar_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 23:18 XXXXX_baz_file.csv

Is that what you're looking for? :)

References:

Looping through command output in bash

Substrings in bash

share|improve this answer

edited 3 hours ago

answered 4 hours ago

danieldeveloper001danieldeveloper001

1215

New contributor

danieldeveloper001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

-rw-rw-r--. 1 daniel daniel 0 May 13 23:18 11111_bar_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 12345_baz_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 67890_foo_file.xml

for src in *.csv; do dst=XXXXX$(echo $src| cut -c6-); mv $src $dst; done;

-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 67890_foo_file.xml
-rw-rw-r--. 1 daniel daniel 0 May 13 22:54 XXXXX_bar_file.csv
-rw-rw-r--. 1 daniel daniel 0 May 13 23:18 XXXXX_baz_file.csv

share|improve this answer

edited 3 hours ago

answered 4 hours ago

danieldeveloper001danieldeveloper001

1215

New contributor

danieldeveloper001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered 4 hours ago

danieldeveloper001danieldeveloper001

1215

New contributor

danieldeveloper001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered 4 hours ago

danieldeveloper001danieldeveloper001

1215