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Python program for a simple calculator


Finding the lowest terms for fractions in C#TDD: String Calculator KataN-Bonnaci sequence calculatorTiny calculator using dependency injection and inversion of controlA simple pocket calculatorPseudo Random Number GeneratorJavaScript OOP calculatorComputing the total property management fee for propertiesMultiplying/Dividing before Adding/SubtractingA Java Calculator that could perform basic Mathematical Operations






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2












$begingroup$


I have written a program for a simple calculator that can add, subtract, multiply and divide using functions.



Here is my code:



# This function adds two numbers 
def add(x, y):
return x + y

# This function subtracts two numbers
def subtract(x, y):
return x - y

# This function multiplies two numbers
def multiply(x, y):
return x * y

# This function divides two numbers
def divide(x, y):
return x / y

print ("Select operation.")
print ("1. Add")
print ("2. Subtract")
print ("3. Multiply")
print ("4. Divide")

choice = input("Enter choice (1/2/3/4): ")

num1 = int(input("Enter first number: "))
num2 = int(input("Enter second number: "))

if choice == '1':
print(num1, "+", num2, "=", add(num1,num2))

elif choice == '2':
print(num1, "-", num2, "=", subtract(num1,num2))

elif choice == '3':
print(num1, "*", num2, "=", multiply(num1,num2))

elif choice == '4':
print(num1, "/", num2, "=", divide(num1,num2))
else:
print("Invalid input")


So, I would like to know whether I could make this code shorter and more efficient.



Also, any alternatives are greatly welcome.



Any help would be highly appreciated.










share|improve this question











$endgroup$


















    2












    $begingroup$


    I have written a program for a simple calculator that can add, subtract, multiply and divide using functions.



    Here is my code:



    # This function adds two numbers 
    def add(x, y):
    return x + y

    # This function subtracts two numbers
    def subtract(x, y):
    return x - y

    # This function multiplies two numbers
    def multiply(x, y):
    return x * y

    # This function divides two numbers
    def divide(x, y):
    return x / y

    print ("Select operation.")
    print ("1. Add")
    print ("2. Subtract")
    print ("3. Multiply")
    print ("4. Divide")

    choice = input("Enter choice (1/2/3/4): ")

    num1 = int(input("Enter first number: "))
    num2 = int(input("Enter second number: "))

    if choice == '1':
    print(num1, "+", num2, "=", add(num1,num2))

    elif choice == '2':
    print(num1, "-", num2, "=", subtract(num1,num2))

    elif choice == '3':
    print(num1, "*", num2, "=", multiply(num1,num2))

    elif choice == '4':
    print(num1, "/", num2, "=", divide(num1,num2))
    else:
    print("Invalid input")


    So, I would like to know whether I could make this code shorter and more efficient.



    Also, any alternatives are greatly welcome.



    Any help would be highly appreciated.










    share|improve this question











    $endgroup$














      2












      2








      2


      1



      $begingroup$


      I have written a program for a simple calculator that can add, subtract, multiply and divide using functions.



      Here is my code:



      # This function adds two numbers 
      def add(x, y):
      return x + y

      # This function subtracts two numbers
      def subtract(x, y):
      return x - y

      # This function multiplies two numbers
      def multiply(x, y):
      return x * y

      # This function divides two numbers
      def divide(x, y):
      return x / y

      print ("Select operation.")
      print ("1. Add")
      print ("2. Subtract")
      print ("3. Multiply")
      print ("4. Divide")

      choice = input("Enter choice (1/2/3/4): ")

      num1 = int(input("Enter first number: "))
      num2 = int(input("Enter second number: "))

      if choice == '1':
      print(num1, "+", num2, "=", add(num1,num2))

      elif choice == '2':
      print(num1, "-", num2, "=", subtract(num1,num2))

      elif choice == '3':
      print(num1, "*", num2, "=", multiply(num1,num2))

      elif choice == '4':
      print(num1, "/", num2, "=", divide(num1,num2))
      else:
      print("Invalid input")


      So, I would like to know whether I could make this code shorter and more efficient.



      Also, any alternatives are greatly welcome.



      Any help would be highly appreciated.










      share|improve this question











      $endgroup$




      I have written a program for a simple calculator that can add, subtract, multiply and divide using functions.



      Here is my code:



      # This function adds two numbers 
      def add(x, y):
      return x + y

      # This function subtracts two numbers
      def subtract(x, y):
      return x - y

      # This function multiplies two numbers
      def multiply(x, y):
      return x * y

      # This function divides two numbers
      def divide(x, y):
      return x / y

      print ("Select operation.")
      print ("1. Add")
      print ("2. Subtract")
      print ("3. Multiply")
      print ("4. Divide")

      choice = input("Enter choice (1/2/3/4): ")

      num1 = int(input("Enter first number: "))
      num2 = int(input("Enter second number: "))

      if choice == '1':
      print(num1, "+", num2, "=", add(num1,num2))

      elif choice == '2':
      print(num1, "-", num2, "=", subtract(num1,num2))

      elif choice == '3':
      print(num1, "*", num2, "=", multiply(num1,num2))

      elif choice == '4':
      print(num1, "/", num2, "=", divide(num1,num2))
      else:
      print("Invalid input")


      So, I would like to know whether I could make this code shorter and more efficient.



      Also, any alternatives are greatly welcome.



      Any help would be highly appreciated.







      python performance python-3.x calculator






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 4 hours ago









      Mast

      7,74463788




      7,74463788










      asked 7 hours ago









      JustinJustin

      371116




      371116




















          2 Answers
          2






          active

          oldest

          votes


















          4












          $begingroup$

          1. You have several functions. What if you will have 100 functions? 1000? Will you copy-paste all your code dozens of times? Always keep in mind the DRY rule: "Don't repeat yourself". In your case you can store all functions and its info in some kind of structure, like dict.


          2. You run your program, it calculates something once and quits. Why not letting the user have many calculations? You can run the neverending loop with some break statement (old console programs, like in DOS, usually quitted on Q).


          Here is the improved code:



          # This function adds two numbers 
          def add(x, y):
          return x + y

          # This function subtracts two numbers
          def subtract(x, y):
          return x - y

          # This function multiplies two numbers
          def multiply(x, y):
          return x * y

          # This function divides two numbers
          def divide(x, y):
          return x / y

          print ("Select operation.")
          print ("1. Add")
          print ("2. Subtract")
          print ("3. Multiply")
          print ("4. Divide")

          functions_dict =
          '1': [add, '+'],
          '2': [subtract, '-'],
          '3': [multiply, '*'],
          '4': [divide, '/']


          while True:
          choice = input("Enter choice (1/2/3/4) or 'q' to quit: ")
          if choice == 'q':
          break
          elif choice in ['1', '2', '3', '4']:
          num1 = int(input("Enter first number: "))
          num2 = int(input("Enter second number: "))
          print(' = '.format(
          num1,
          functions_dict[choice][1],
          num2,
          functions_dict[choice][0](num1, num2)
          ))
          else:
          print('Invalid number')






          share|improve this answer








          New contributor



          vurmux is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.





          $endgroup$












          • $begingroup$
            I was about to post my answer and saw this. Upvote for bringing out a case for dictionaries. Might I add, it may be good to add a bit on input validation.
            $endgroup$
            – perennial_noob
            20 mins ago


















          3












          $begingroup$

          One issue I see is with casting the user's input to int:



          num1 = int(input("Enter first number: "))
          num2 = int(input("Enter second number: "))


          You can prompt the user the input only integers, but there is currently nothing stopping them from inputting a string. When an attempt to cast the string as an int is made, it will fail inelegantly.



          I suggest either surrounding the input with a try/except block to catch that possibility:



          try:
          num1 = int(input("Enter first number: "))
          except ValueError:
          print("RuhRoh")


          Or using str.isdigit():



          num1 = input("Enter first number: ")
          if not num1.isdigit():
          print("RuhRoh")





          share|improve this answer








          New contributor



          Clay Records is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.





          $endgroup$













            Your Answer






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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            4












            $begingroup$

            1. You have several functions. What if you will have 100 functions? 1000? Will you copy-paste all your code dozens of times? Always keep in mind the DRY rule: "Don't repeat yourself". In your case you can store all functions and its info in some kind of structure, like dict.


            2. You run your program, it calculates something once and quits. Why not letting the user have many calculations? You can run the neverending loop with some break statement (old console programs, like in DOS, usually quitted on Q).


            Here is the improved code:



            # This function adds two numbers 
            def add(x, y):
            return x + y

            # This function subtracts two numbers
            def subtract(x, y):
            return x - y

            # This function multiplies two numbers
            def multiply(x, y):
            return x * y

            # This function divides two numbers
            def divide(x, y):
            return x / y

            print ("Select operation.")
            print ("1. Add")
            print ("2. Subtract")
            print ("3. Multiply")
            print ("4. Divide")

            functions_dict =
            '1': [add, '+'],
            '2': [subtract, '-'],
            '3': [multiply, '*'],
            '4': [divide, '/']


            while True:
            choice = input("Enter choice (1/2/3/4) or 'q' to quit: ")
            if choice == 'q':
            break
            elif choice in ['1', '2', '3', '4']:
            num1 = int(input("Enter first number: "))
            num2 = int(input("Enter second number: "))
            print(' = '.format(
            num1,
            functions_dict[choice][1],
            num2,
            functions_dict[choice][0](num1, num2)
            ))
            else:
            print('Invalid number')






            share|improve this answer








            New contributor



            vurmux is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            $endgroup$












            • $begingroup$
              I was about to post my answer and saw this. Upvote for bringing out a case for dictionaries. Might I add, it may be good to add a bit on input validation.
              $endgroup$
              – perennial_noob
              20 mins ago















            4












            $begingroup$

            1. You have several functions. What if you will have 100 functions? 1000? Will you copy-paste all your code dozens of times? Always keep in mind the DRY rule: "Don't repeat yourself". In your case you can store all functions and its info in some kind of structure, like dict.


            2. You run your program, it calculates something once and quits. Why not letting the user have many calculations? You can run the neverending loop with some break statement (old console programs, like in DOS, usually quitted on Q).


            Here is the improved code:



            # This function adds two numbers 
            def add(x, y):
            return x + y

            # This function subtracts two numbers
            def subtract(x, y):
            return x - y

            # This function multiplies two numbers
            def multiply(x, y):
            return x * y

            # This function divides two numbers
            def divide(x, y):
            return x / y

            print ("Select operation.")
            print ("1. Add")
            print ("2. Subtract")
            print ("3. Multiply")
            print ("4. Divide")

            functions_dict =
            '1': [add, '+'],
            '2': [subtract, '-'],
            '3': [multiply, '*'],
            '4': [divide, '/']


            while True:
            choice = input("Enter choice (1/2/3/4) or 'q' to quit: ")
            if choice == 'q':
            break
            elif choice in ['1', '2', '3', '4']:
            num1 = int(input("Enter first number: "))
            num2 = int(input("Enter second number: "))
            print(' = '.format(
            num1,
            functions_dict[choice][1],
            num2,
            functions_dict[choice][0](num1, num2)
            ))
            else:
            print('Invalid number')






            share|improve this answer








            New contributor



            vurmux is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            $endgroup$












            • $begingroup$
              I was about to post my answer and saw this. Upvote for bringing out a case for dictionaries. Might I add, it may be good to add a bit on input validation.
              $endgroup$
              – perennial_noob
              20 mins ago













            4












            4








            4





            $begingroup$

            1. You have several functions. What if you will have 100 functions? 1000? Will you copy-paste all your code dozens of times? Always keep in mind the DRY rule: "Don't repeat yourself". In your case you can store all functions and its info in some kind of structure, like dict.


            2. You run your program, it calculates something once and quits. Why not letting the user have many calculations? You can run the neverending loop with some break statement (old console programs, like in DOS, usually quitted on Q).


            Here is the improved code:



            # This function adds two numbers 
            def add(x, y):
            return x + y

            # This function subtracts two numbers
            def subtract(x, y):
            return x - y

            # This function multiplies two numbers
            def multiply(x, y):
            return x * y

            # This function divides two numbers
            def divide(x, y):
            return x / y

            print ("Select operation.")
            print ("1. Add")
            print ("2. Subtract")
            print ("3. Multiply")
            print ("4. Divide")

            functions_dict =
            '1': [add, '+'],
            '2': [subtract, '-'],
            '3': [multiply, '*'],
            '4': [divide, '/']


            while True:
            choice = input("Enter choice (1/2/3/4) or 'q' to quit: ")
            if choice == 'q':
            break
            elif choice in ['1', '2', '3', '4']:
            num1 = int(input("Enter first number: "))
            num2 = int(input("Enter second number: "))
            print(' = '.format(
            num1,
            functions_dict[choice][1],
            num2,
            functions_dict[choice][0](num1, num2)
            ))
            else:
            print('Invalid number')






            share|improve this answer








            New contributor



            vurmux is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            $endgroup$



            1. You have several functions. What if you will have 100 functions? 1000? Will you copy-paste all your code dozens of times? Always keep in mind the DRY rule: "Don't repeat yourself". In your case you can store all functions and its info in some kind of structure, like dict.


            2. You run your program, it calculates something once and quits. Why not letting the user have many calculations? You can run the neverending loop with some break statement (old console programs, like in DOS, usually quitted on Q).


            Here is the improved code:



            # This function adds two numbers 
            def add(x, y):
            return x + y

            # This function subtracts two numbers
            def subtract(x, y):
            return x - y

            # This function multiplies two numbers
            def multiply(x, y):
            return x * y

            # This function divides two numbers
            def divide(x, y):
            return x / y

            print ("Select operation.")
            print ("1. Add")
            print ("2. Subtract")
            print ("3. Multiply")
            print ("4. Divide")

            functions_dict =
            '1': [add, '+'],
            '2': [subtract, '-'],
            '3': [multiply, '*'],
            '4': [divide, '/']


            while True:
            choice = input("Enter choice (1/2/3/4) or 'q' to quit: ")
            if choice == 'q':
            break
            elif choice in ['1', '2', '3', '4']:
            num1 = int(input("Enter first number: "))
            num2 = int(input("Enter second number: "))
            print(' = '.format(
            num1,
            functions_dict[choice][1],
            num2,
            functions_dict[choice][0](num1, num2)
            ))
            else:
            print('Invalid number')







            share|improve this answer








            New contributor



            vurmux is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.








            share|improve this answer



            share|improve this answer






            New contributor



            vurmux is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.








            answered 6 hours ago









            vurmuxvurmux

            2709




            2709




            New contributor



            vurmux is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.




            New contributor




            vurmux is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.













            • $begingroup$
              I was about to post my answer and saw this. Upvote for bringing out a case for dictionaries. Might I add, it may be good to add a bit on input validation.
              $endgroup$
              – perennial_noob
              20 mins ago
















            • $begingroup$
              I was about to post my answer and saw this. Upvote for bringing out a case for dictionaries. Might I add, it may be good to add a bit on input validation.
              $endgroup$
              – perennial_noob
              20 mins ago















            $begingroup$
            I was about to post my answer and saw this. Upvote for bringing out a case for dictionaries. Might I add, it may be good to add a bit on input validation.
            $endgroup$
            – perennial_noob
            20 mins ago




            $begingroup$
            I was about to post my answer and saw this. Upvote for bringing out a case for dictionaries. Might I add, it may be good to add a bit on input validation.
            $endgroup$
            – perennial_noob
            20 mins ago













            3












            $begingroup$

            One issue I see is with casting the user's input to int:



            num1 = int(input("Enter first number: "))
            num2 = int(input("Enter second number: "))


            You can prompt the user the input only integers, but there is currently nothing stopping them from inputting a string. When an attempt to cast the string as an int is made, it will fail inelegantly.



            I suggest either surrounding the input with a try/except block to catch that possibility:



            try:
            num1 = int(input("Enter first number: "))
            except ValueError:
            print("RuhRoh")


            Or using str.isdigit():



            num1 = input("Enter first number: ")
            if not num1.isdigit():
            print("RuhRoh")





            share|improve this answer








            New contributor



            Clay Records is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            $endgroup$

















              3












              $begingroup$

              One issue I see is with casting the user's input to int:



              num1 = int(input("Enter first number: "))
              num2 = int(input("Enter second number: "))


              You can prompt the user the input only integers, but there is currently nothing stopping them from inputting a string. When an attempt to cast the string as an int is made, it will fail inelegantly.



              I suggest either surrounding the input with a try/except block to catch that possibility:



              try:
              num1 = int(input("Enter first number: "))
              except ValueError:
              print("RuhRoh")


              Or using str.isdigit():



              num1 = input("Enter first number: ")
              if not num1.isdigit():
              print("RuhRoh")





              share|improve this answer








              New contributor



              Clay Records is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.





              $endgroup$















                3












                3








                3





                $begingroup$

                One issue I see is with casting the user's input to int:



                num1 = int(input("Enter first number: "))
                num2 = int(input("Enter second number: "))


                You can prompt the user the input only integers, but there is currently nothing stopping them from inputting a string. When an attempt to cast the string as an int is made, it will fail inelegantly.



                I suggest either surrounding the input with a try/except block to catch that possibility:



                try:
                num1 = int(input("Enter first number: "))
                except ValueError:
                print("RuhRoh")


                Or using str.isdigit():



                num1 = input("Enter first number: ")
                if not num1.isdigit():
                print("RuhRoh")





                share|improve this answer








                New contributor



                Clay Records is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





                $endgroup$



                One issue I see is with casting the user's input to int:



                num1 = int(input("Enter first number: "))
                num2 = int(input("Enter second number: "))


                You can prompt the user the input only integers, but there is currently nothing stopping them from inputting a string. When an attempt to cast the string as an int is made, it will fail inelegantly.



                I suggest either surrounding the input with a try/except block to catch that possibility:



                try:
                num1 = int(input("Enter first number: "))
                except ValueError:
                print("RuhRoh")


                Or using str.isdigit():



                num1 = input("Enter first number: ")
                if not num1.isdigit():
                print("RuhRoh")






                share|improve this answer








                New contributor



                Clay Records is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.








                share|improve this answer



                share|improve this answer






                New contributor



                Clay Records is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.








                answered 6 hours ago









                Clay RecordsClay Records

                1313




                1313




                New contributor



                Clay Records is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.




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