WAS IT A CAT I SAW? Do Some Detective Work & Catch The ImpostersWhat could have been the sentences I was thinking about?Can you work out the number which replaces the question mark?Can the Policeman catch the Thief?Can the policeman actually catch the thief, instead of shooting?Some day in the park with Fiqo

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WAS IT A CAT I SAW? Do Some Detective Work & Catch The Imposters


What could have been the sentences I was thinking about?Can you work out the number which replaces the question mark?Can the Policeman catch the Thief?Can the policeman actually catch the thief, instead of shooting?Some day in the park with Fiqo













1












$begingroup$


Carolina County Community Cat Conference is going on at a resort exclusively reserved for Prime Members.



Some look-alike impostors, aka cats, have sneaked in. They all wear fancy name tags that reveal their character.



Toss on a Sherlock Holmes hat and catch these cunning cats, that is the imposters, by examining their name tags closely. Initially assume all are Prime Members, unless you notice a specific character in the name tag that reveals that it they are not a Prime Member, and instead are actually a cat.



Only basic knowledge of primality test is needed to catch the culprit.



1) was it a rat I saw



2) Tacocat



3) Madam I m Adam



4) Malayalam



5) Dammit I m mad



6) Step on no Pets



7) Never odd or even



8) Do geese see god



9) Toppot



10) Redder



11) Race fast safe car



12) Madam in Eden I m Adam










share|improve this question











$endgroup$







  • 2




    $begingroup$
    Is the mathematics tag meant to be there?
    $endgroup$
    – gabbo1092
    8 hours ago










  • $begingroup$
    Yes..need to understand prime properties
    $endgroup$
    – Uvc
    8 hours ago















1












$begingroup$


Carolina County Community Cat Conference is going on at a resort exclusively reserved for Prime Members.



Some look-alike impostors, aka cats, have sneaked in. They all wear fancy name tags that reveal their character.



Toss on a Sherlock Holmes hat and catch these cunning cats, that is the imposters, by examining their name tags closely. Initially assume all are Prime Members, unless you notice a specific character in the name tag that reveals that it they are not a Prime Member, and instead are actually a cat.



Only basic knowledge of primality test is needed to catch the culprit.



1) was it a rat I saw



2) Tacocat



3) Madam I m Adam



4) Malayalam



5) Dammit I m mad



6) Step on no Pets



7) Never odd or even



8) Do geese see god



9) Toppot



10) Redder



11) Race fast safe car



12) Madam in Eden I m Adam










share|improve this question











$endgroup$







  • 2




    $begingroup$
    Is the mathematics tag meant to be there?
    $endgroup$
    – gabbo1092
    8 hours ago










  • $begingroup$
    Yes..need to understand prime properties
    $endgroup$
    – Uvc
    8 hours ago













1












1








1





$begingroup$


Carolina County Community Cat Conference is going on at a resort exclusively reserved for Prime Members.



Some look-alike impostors, aka cats, have sneaked in. They all wear fancy name tags that reveal their character.



Toss on a Sherlock Holmes hat and catch these cunning cats, that is the imposters, by examining their name tags closely. Initially assume all are Prime Members, unless you notice a specific character in the name tag that reveals that it they are not a Prime Member, and instead are actually a cat.



Only basic knowledge of primality test is needed to catch the culprit.



1) was it a rat I saw



2) Tacocat



3) Madam I m Adam



4) Malayalam



5) Dammit I m mad



6) Step on no Pets



7) Never odd or even



8) Do geese see god



9) Toppot



10) Redder



11) Race fast safe car



12) Madam in Eden I m Adam










share|improve this question











$endgroup$




Carolina County Community Cat Conference is going on at a resort exclusively reserved for Prime Members.



Some look-alike impostors, aka cats, have sneaked in. They all wear fancy name tags that reveal their character.



Toss on a Sherlock Holmes hat and catch these cunning cats, that is the imposters, by examining their name tags closely. Initially assume all are Prime Members, unless you notice a specific character in the name tag that reveals that it they are not a Prime Member, and instead are actually a cat.



Only basic knowledge of primality test is needed to catch the culprit.



1) was it a rat I saw



2) Tacocat



3) Madam I m Adam



4) Malayalam



5) Dammit I m mad



6) Step on no Pets



7) Never odd or even



8) Do geese see god



9) Toppot



10) Redder



11) Race fast safe car



12) Madam in Eden I m Adam







mathematics






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 3 hours ago









Rewan Demontay

1,169121




1,169121










asked 8 hours ago









UvcUvc

91015




91015







  • 2




    $begingroup$
    Is the mathematics tag meant to be there?
    $endgroup$
    – gabbo1092
    8 hours ago










  • $begingroup$
    Yes..need to understand prime properties
    $endgroup$
    – Uvc
    8 hours ago












  • 2




    $begingroup$
    Is the mathematics tag meant to be there?
    $endgroup$
    – gabbo1092
    8 hours ago










  • $begingroup$
    Yes..need to understand prime properties
    $endgroup$
    – Uvc
    8 hours ago







2




2




$begingroup$
Is the mathematics tag meant to be there?
$endgroup$
– gabbo1092
8 hours ago




$begingroup$
Is the mathematics tag meant to be there?
$endgroup$
– gabbo1092
8 hours ago












$begingroup$
Yes..need to understand prime properties
$endgroup$
– Uvc
8 hours ago




$begingroup$
Yes..need to understand prime properties
$endgroup$
– Uvc
8 hours ago










3 Answers
3






active

oldest

votes


















3












$begingroup$

Partial answer



(I don't intend to make this less partial because that feels like a computer-based slog.)



I assume the idea is that each of these represents a prime number whose digits form the palindromic pattern given by the letters. Well,




any with an even number of digits must be an impostor, because any palindrome with an even number of digits is a multiple of 11. That means 6,7,9,10 are impostors.




My guess is




that the odd-length ones (including the Dammit... one if "I am" becomes "I'm") all do have corresponding primes. But actually checking that seems really tiresome. Also, it's kinda ambiguous whether we're supposed to assume that different letters correspond to different digits.







share|improve this answer









$endgroup$












  • $begingroup$
    Garetth...Great quick detective work
    $endgroup$
    – Uvc
    8 hours ago










  • $begingroup$
    Isn't this.. a bit far-fetched, given the current description? o.O
    $endgroup$
    – athin
    8 hours ago










  • $begingroup$
    It is surprising how the puzzles are dissected..if all the information is given explicitly, then no fun..club is primarily for prime numbers..stated..as a detective you have to examine the character and identify the distinguishing features from the majority. You identify the suspects and you can state your assumptions in doing so.
    $endgroup$
    – Uvc
    8 hours ago






  • 2




    $begingroup$
    No, what I mean is that given the statement of the problem, I'm kinda think it's (a bit) too board. No clue or statement to hint or give the impression that each character represent a number. The Prime Member is not enough. I also answer all composite numbers to be the impostors. I can also count the letters, or summing the A1Z26 and pick the non-prime one. My answer is also possible despite not taking the prime as a step. Additionally, as Gareth also stated, there are still many ambiguous steps like different letters should be different numbers so similar idea may lead to different answers.
    $endgroup$
    – athin
    7 hours ago











  • $begingroup$
    I originally toyed with that idea..then it will be too easy.. I will take suggestions and add edits to make it easy for future readers ..in real life, detectives life is not easy..
    $endgroup$
    – Uvc
    7 hours ago


















4












$begingroup$

It's




Number $5$ as it's the only one which is not palindrome.







share|improve this answer









$endgroup$












  • $begingroup$
    Ah, beat me to it!
    $endgroup$
    – PartyHatPanda
    8 hours ago






  • 2




    $begingroup$
    I suspect #5 is meant to say "I'm" rather than "I am".
    $endgroup$
    – Gareth McCaughan
    8 hours ago










  • $begingroup$
    @athin..all palindromes need not be primes..see Garett’s explanation
    $endgroup$
    – Uvc
    8 hours ago


















2












$begingroup$

The immediate one that stands out is




Number 5, as it isn't a palindrome







share|improve this answer









$endgroup$












  • $begingroup$
    Need to more detailed detective work
    $endgroup$
    – Uvc
    8 hours ago











Your Answer








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3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes









3












$begingroup$

Partial answer



(I don't intend to make this less partial because that feels like a computer-based slog.)



I assume the idea is that each of these represents a prime number whose digits form the palindromic pattern given by the letters. Well,




any with an even number of digits must be an impostor, because any palindrome with an even number of digits is a multiple of 11. That means 6,7,9,10 are impostors.




My guess is




that the odd-length ones (including the Dammit... one if "I am" becomes "I'm") all do have corresponding primes. But actually checking that seems really tiresome. Also, it's kinda ambiguous whether we're supposed to assume that different letters correspond to different digits.







share|improve this answer









$endgroup$












  • $begingroup$
    Garetth...Great quick detective work
    $endgroup$
    – Uvc
    8 hours ago










  • $begingroup$
    Isn't this.. a bit far-fetched, given the current description? o.O
    $endgroup$
    – athin
    8 hours ago










  • $begingroup$
    It is surprising how the puzzles are dissected..if all the information is given explicitly, then no fun..club is primarily for prime numbers..stated..as a detective you have to examine the character and identify the distinguishing features from the majority. You identify the suspects and you can state your assumptions in doing so.
    $endgroup$
    – Uvc
    8 hours ago






  • 2




    $begingroup$
    No, what I mean is that given the statement of the problem, I'm kinda think it's (a bit) too board. No clue or statement to hint or give the impression that each character represent a number. The Prime Member is not enough. I also answer all composite numbers to be the impostors. I can also count the letters, or summing the A1Z26 and pick the non-prime one. My answer is also possible despite not taking the prime as a step. Additionally, as Gareth also stated, there are still many ambiguous steps like different letters should be different numbers so similar idea may lead to different answers.
    $endgroup$
    – athin
    7 hours ago











  • $begingroup$
    I originally toyed with that idea..then it will be too easy.. I will take suggestions and add edits to make it easy for future readers ..in real life, detectives life is not easy..
    $endgroup$
    – Uvc
    7 hours ago















3












$begingroup$

Partial answer



(I don't intend to make this less partial because that feels like a computer-based slog.)



I assume the idea is that each of these represents a prime number whose digits form the palindromic pattern given by the letters. Well,




any with an even number of digits must be an impostor, because any palindrome with an even number of digits is a multiple of 11. That means 6,7,9,10 are impostors.




My guess is




that the odd-length ones (including the Dammit... one if "I am" becomes "I'm") all do have corresponding primes. But actually checking that seems really tiresome. Also, it's kinda ambiguous whether we're supposed to assume that different letters correspond to different digits.







share|improve this answer









$endgroup$












  • $begingroup$
    Garetth...Great quick detective work
    $endgroup$
    – Uvc
    8 hours ago










  • $begingroup$
    Isn't this.. a bit far-fetched, given the current description? o.O
    $endgroup$
    – athin
    8 hours ago










  • $begingroup$
    It is surprising how the puzzles are dissected..if all the information is given explicitly, then no fun..club is primarily for prime numbers..stated..as a detective you have to examine the character and identify the distinguishing features from the majority. You identify the suspects and you can state your assumptions in doing so.
    $endgroup$
    – Uvc
    8 hours ago






  • 2




    $begingroup$
    No, what I mean is that given the statement of the problem, I'm kinda think it's (a bit) too board. No clue or statement to hint or give the impression that each character represent a number. The Prime Member is not enough. I also answer all composite numbers to be the impostors. I can also count the letters, or summing the A1Z26 and pick the non-prime one. My answer is also possible despite not taking the prime as a step. Additionally, as Gareth also stated, there are still many ambiguous steps like different letters should be different numbers so similar idea may lead to different answers.
    $endgroup$
    – athin
    7 hours ago











  • $begingroup$
    I originally toyed with that idea..then it will be too easy.. I will take suggestions and add edits to make it easy for future readers ..in real life, detectives life is not easy..
    $endgroup$
    – Uvc
    7 hours ago













3












3








3





$begingroup$

Partial answer



(I don't intend to make this less partial because that feels like a computer-based slog.)



I assume the idea is that each of these represents a prime number whose digits form the palindromic pattern given by the letters. Well,




any with an even number of digits must be an impostor, because any palindrome with an even number of digits is a multiple of 11. That means 6,7,9,10 are impostors.




My guess is




that the odd-length ones (including the Dammit... one if "I am" becomes "I'm") all do have corresponding primes. But actually checking that seems really tiresome. Also, it's kinda ambiguous whether we're supposed to assume that different letters correspond to different digits.







share|improve this answer









$endgroup$



Partial answer



(I don't intend to make this less partial because that feels like a computer-based slog.)



I assume the idea is that each of these represents a prime number whose digits form the palindromic pattern given by the letters. Well,




any with an even number of digits must be an impostor, because any palindrome with an even number of digits is a multiple of 11. That means 6,7,9,10 are impostors.




My guess is




that the odd-length ones (including the Dammit... one if "I am" becomes "I'm") all do have corresponding primes. But actually checking that seems really tiresome. Also, it's kinda ambiguous whether we're supposed to assume that different letters correspond to different digits.








share|improve this answer












share|improve this answer



share|improve this answer










answered 8 hours ago









Gareth McCaughanGareth McCaughan

72.8k3181280




72.8k3181280











  • $begingroup$
    Garetth...Great quick detective work
    $endgroup$
    – Uvc
    8 hours ago










  • $begingroup$
    Isn't this.. a bit far-fetched, given the current description? o.O
    $endgroup$
    – athin
    8 hours ago










  • $begingroup$
    It is surprising how the puzzles are dissected..if all the information is given explicitly, then no fun..club is primarily for prime numbers..stated..as a detective you have to examine the character and identify the distinguishing features from the majority. You identify the suspects and you can state your assumptions in doing so.
    $endgroup$
    – Uvc
    8 hours ago






  • 2




    $begingroup$
    No, what I mean is that given the statement of the problem, I'm kinda think it's (a bit) too board. No clue or statement to hint or give the impression that each character represent a number. The Prime Member is not enough. I also answer all composite numbers to be the impostors. I can also count the letters, or summing the A1Z26 and pick the non-prime one. My answer is also possible despite not taking the prime as a step. Additionally, as Gareth also stated, there are still many ambiguous steps like different letters should be different numbers so similar idea may lead to different answers.
    $endgroup$
    – athin
    7 hours ago











  • $begingroup$
    I originally toyed with that idea..then it will be too easy.. I will take suggestions and add edits to make it easy for future readers ..in real life, detectives life is not easy..
    $endgroup$
    – Uvc
    7 hours ago
















  • $begingroup$
    Garetth...Great quick detective work
    $endgroup$
    – Uvc
    8 hours ago










  • $begingroup$
    Isn't this.. a bit far-fetched, given the current description? o.O
    $endgroup$
    – athin
    8 hours ago










  • $begingroup$
    It is surprising how the puzzles are dissected..if all the information is given explicitly, then no fun..club is primarily for prime numbers..stated..as a detective you have to examine the character and identify the distinguishing features from the majority. You identify the suspects and you can state your assumptions in doing so.
    $endgroup$
    – Uvc
    8 hours ago






  • 2




    $begingroup$
    No, what I mean is that given the statement of the problem, I'm kinda think it's (a bit) too board. No clue or statement to hint or give the impression that each character represent a number. The Prime Member is not enough. I also answer all composite numbers to be the impostors. I can also count the letters, or summing the A1Z26 and pick the non-prime one. My answer is also possible despite not taking the prime as a step. Additionally, as Gareth also stated, there are still many ambiguous steps like different letters should be different numbers so similar idea may lead to different answers.
    $endgroup$
    – athin
    7 hours ago











  • $begingroup$
    I originally toyed with that idea..then it will be too easy.. I will take suggestions and add edits to make it easy for future readers ..in real life, detectives life is not easy..
    $endgroup$
    – Uvc
    7 hours ago















$begingroup$
Garetth...Great quick detective work
$endgroup$
– Uvc
8 hours ago




$begingroup$
Garetth...Great quick detective work
$endgroup$
– Uvc
8 hours ago












$begingroup$
Isn't this.. a bit far-fetched, given the current description? o.O
$endgroup$
– athin
8 hours ago




$begingroup$
Isn't this.. a bit far-fetched, given the current description? o.O
$endgroup$
– athin
8 hours ago












$begingroup$
It is surprising how the puzzles are dissected..if all the information is given explicitly, then no fun..club is primarily for prime numbers..stated..as a detective you have to examine the character and identify the distinguishing features from the majority. You identify the suspects and you can state your assumptions in doing so.
$endgroup$
– Uvc
8 hours ago




$begingroup$
It is surprising how the puzzles are dissected..if all the information is given explicitly, then no fun..club is primarily for prime numbers..stated..as a detective you have to examine the character and identify the distinguishing features from the majority. You identify the suspects and you can state your assumptions in doing so.
$endgroup$
– Uvc
8 hours ago




2




2




$begingroup$
No, what I mean is that given the statement of the problem, I'm kinda think it's (a bit) too board. No clue or statement to hint or give the impression that each character represent a number. The Prime Member is not enough. I also answer all composite numbers to be the impostors. I can also count the letters, or summing the A1Z26 and pick the non-prime one. My answer is also possible despite not taking the prime as a step. Additionally, as Gareth also stated, there are still many ambiguous steps like different letters should be different numbers so similar idea may lead to different answers.
$endgroup$
– athin
7 hours ago





$begingroup$
No, what I mean is that given the statement of the problem, I'm kinda think it's (a bit) too board. No clue or statement to hint or give the impression that each character represent a number. The Prime Member is not enough. I also answer all composite numbers to be the impostors. I can also count the letters, or summing the A1Z26 and pick the non-prime one. My answer is also possible despite not taking the prime as a step. Additionally, as Gareth also stated, there are still many ambiguous steps like different letters should be different numbers so similar idea may lead to different answers.
$endgroup$
– athin
7 hours ago













$begingroup$
I originally toyed with that idea..then it will be too easy.. I will take suggestions and add edits to make it easy for future readers ..in real life, detectives life is not easy..
$endgroup$
– Uvc
7 hours ago




$begingroup$
I originally toyed with that idea..then it will be too easy.. I will take suggestions and add edits to make it easy for future readers ..in real life, detectives life is not easy..
$endgroup$
– Uvc
7 hours ago











4












$begingroup$

It's




Number $5$ as it's the only one which is not palindrome.







share|improve this answer









$endgroup$












  • $begingroup$
    Ah, beat me to it!
    $endgroup$
    – PartyHatPanda
    8 hours ago






  • 2




    $begingroup$
    I suspect #5 is meant to say "I'm" rather than "I am".
    $endgroup$
    – Gareth McCaughan
    8 hours ago










  • $begingroup$
    @athin..all palindromes need not be primes..see Garett’s explanation
    $endgroup$
    – Uvc
    8 hours ago















4












$begingroup$

It's




Number $5$ as it's the only one which is not palindrome.







share|improve this answer









$endgroup$












  • $begingroup$
    Ah, beat me to it!
    $endgroup$
    – PartyHatPanda
    8 hours ago






  • 2




    $begingroup$
    I suspect #5 is meant to say "I'm" rather than "I am".
    $endgroup$
    – Gareth McCaughan
    8 hours ago










  • $begingroup$
    @athin..all palindromes need not be primes..see Garett’s explanation
    $endgroup$
    – Uvc
    8 hours ago













4












4








4





$begingroup$

It's




Number $5$ as it's the only one which is not palindrome.







share|improve this answer









$endgroup$



It's




Number $5$ as it's the only one which is not palindrome.








share|improve this answer












share|improve this answer



share|improve this answer










answered 8 hours ago









athinathin

10.3k23589




10.3k23589











  • $begingroup$
    Ah, beat me to it!
    $endgroup$
    – PartyHatPanda
    8 hours ago






  • 2




    $begingroup$
    I suspect #5 is meant to say "I'm" rather than "I am".
    $endgroup$
    – Gareth McCaughan
    8 hours ago










  • $begingroup$
    @athin..all palindromes need not be primes..see Garett’s explanation
    $endgroup$
    – Uvc
    8 hours ago
















  • $begingroup$
    Ah, beat me to it!
    $endgroup$
    – PartyHatPanda
    8 hours ago






  • 2




    $begingroup$
    I suspect #5 is meant to say "I'm" rather than "I am".
    $endgroup$
    – Gareth McCaughan
    8 hours ago










  • $begingroup$
    @athin..all palindromes need not be primes..see Garett’s explanation
    $endgroup$
    – Uvc
    8 hours ago















$begingroup$
Ah, beat me to it!
$endgroup$
– PartyHatPanda
8 hours ago




$begingroup$
Ah, beat me to it!
$endgroup$
– PartyHatPanda
8 hours ago




2




2




$begingroup$
I suspect #5 is meant to say "I'm" rather than "I am".
$endgroup$
– Gareth McCaughan
8 hours ago




$begingroup$
I suspect #5 is meant to say "I'm" rather than "I am".
$endgroup$
– Gareth McCaughan
8 hours ago












$begingroup$
@athin..all palindromes need not be primes..see Garett’s explanation
$endgroup$
– Uvc
8 hours ago




$begingroup$
@athin..all palindromes need not be primes..see Garett’s explanation
$endgroup$
– Uvc
8 hours ago











2












$begingroup$

The immediate one that stands out is




Number 5, as it isn't a palindrome







share|improve this answer









$endgroup$












  • $begingroup$
    Need to more detailed detective work
    $endgroup$
    – Uvc
    8 hours ago















2












$begingroup$

The immediate one that stands out is




Number 5, as it isn't a palindrome







share|improve this answer









$endgroup$












  • $begingroup$
    Need to more detailed detective work
    $endgroup$
    – Uvc
    8 hours ago













2












2








2





$begingroup$

The immediate one that stands out is




Number 5, as it isn't a palindrome







share|improve this answer









$endgroup$



The immediate one that stands out is




Number 5, as it isn't a palindrome








share|improve this answer












share|improve this answer



share|improve this answer










answered 8 hours ago









PartyHatPandaPartyHatPanda

1,521620




1,521620











  • $begingroup$
    Need to more detailed detective work
    $endgroup$
    – Uvc
    8 hours ago
















  • $begingroup$
    Need to more detailed detective work
    $endgroup$
    – Uvc
    8 hours ago















$begingroup$
Need to more detailed detective work
$endgroup$
– Uvc
8 hours ago




$begingroup$
Need to more detailed detective work
$endgroup$
– Uvc
8 hours ago

















draft saved

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