Equivalence relation by the symmetric difference of setsWhy isn't reflexivity redundant in the definition of equivalence relation?Show that the restriction of an equivalence relation is an equivalence relation.Equivalence-relations question.Equivalence relation $gsim h :Longleftrightarrow h in g,g^-1$Equivalence relation question with functionsProving something is an equivalence relationProving that rational equivalence is an equivalence relation on any set.Elementary set theory - challenging problem from relations and equivalence classesProve that the union of relations is an equivalence relationEquivalence Relation Requiring Set of all Sets

Can I summon an otherworldly creature with the Gate spell without knowing its true name?

My players want to grind XP but we're using milestone advancement

Construct a word ladder

Why does the hash of infinity have the digits of π?

Where's this lookout in Nova Scotia?

Who is in charge of Wakanda?

Who decides how to classify a novel?

Popcorn is the only acceptable snack to consume while watching a movie

Why does this if-statement combining assignment and an equality check return true?

The art of clickbait captions

Do photons bend spacetime or not?

Remove CiviCRM and Drupal links / banner on profile form

How to cut a climbing rope?

Why were helmets and other body armour not commonplace in the 1800s?

Is the field of q-series 'dead'?

How to ignore kerning of underbrace in math mode

Why did Jon Snow do this immoral act if he is so honorable?

How to patch glass cuts in a bicycle tire?

How can I tell if I'm being too picky as a referee?

Why isn't 'chemically-strengthened glass' made with potassium carbonate to begin with?

Which European Languages are not Indo-European?

Do I need full recovery mode when I have multiple daily backup?

Where have Brexit voters gone?

Pirate democracy at its finest



Equivalence relation by the symmetric difference of sets


Why isn't reflexivity redundant in the definition of equivalence relation?Show that the restriction of an equivalence relation is an equivalence relation.Equivalence-relations question.Equivalence relation $gsim h :Longleftrightarrow h in g,g^-1$Equivalence relation question with functionsProving something is an equivalence relationProving that rational equivalence is an equivalence relation on any set.Elementary set theory - challenging problem from relations and equivalence classesProve that the union of relations is an equivalence relationEquivalence Relation Requiring Set of all Sets













1












$begingroup$


Let $A, B$ subsets of $X$ and $mathbb P(X)$ the power set,
we define the following equivalence relation on $mathbb P(X)$:



Let $ Ssubseteq X$ a fixed subset of $X$ and $A$~$B$ $iff A△B subseteq S$



Prove that is is an equivalence relation and find the class of $X$ and $S$



My work:



I have already shown that the relationship satisfies reflexivity and symmetry, all this is justified respectively by the fact that the empty set is a subset of any set and the symmetric difference is commutative.



My problem is with transitivity, I do not know how to do it, that is when I try to use it for the definition of symmetric difference I fall in many cases. There is some way to test transitivity using only operations between sets. And with respect to the equivalence class of $S$, I showed that they are all subsets of $X$ contained in $S$. But with respect to the equivalence class of $X4 I do not see what it is.



Any help would be useful. Thank you!










share|cite|improve this question











$endgroup$











  • $begingroup$
    @EthanBolker You're right, my mistake!
    $endgroup$
    – Hendrik Matamoros
    2 hours ago















1












$begingroup$


Let $A, B$ subsets of $X$ and $mathbb P(X)$ the power set,
we define the following equivalence relation on $mathbb P(X)$:



Let $ Ssubseteq X$ a fixed subset of $X$ and $A$~$B$ $iff A△B subseteq S$



Prove that is is an equivalence relation and find the class of $X$ and $S$



My work:



I have already shown that the relationship satisfies reflexivity and symmetry, all this is justified respectively by the fact that the empty set is a subset of any set and the symmetric difference is commutative.



My problem is with transitivity, I do not know how to do it, that is when I try to use it for the definition of symmetric difference I fall in many cases. There is some way to test transitivity using only operations between sets. And with respect to the equivalence class of $S$, I showed that they are all subsets of $X$ contained in $S$. But with respect to the equivalence class of $X4 I do not see what it is.



Any help would be useful. Thank you!










share|cite|improve this question











$endgroup$











  • $begingroup$
    @EthanBolker You're right, my mistake!
    $endgroup$
    – Hendrik Matamoros
    2 hours ago













1












1








1





$begingroup$


Let $A, B$ subsets of $X$ and $mathbb P(X)$ the power set,
we define the following equivalence relation on $mathbb P(X)$:



Let $ Ssubseteq X$ a fixed subset of $X$ and $A$~$B$ $iff A△B subseteq S$



Prove that is is an equivalence relation and find the class of $X$ and $S$



My work:



I have already shown that the relationship satisfies reflexivity and symmetry, all this is justified respectively by the fact that the empty set is a subset of any set and the symmetric difference is commutative.



My problem is with transitivity, I do not know how to do it, that is when I try to use it for the definition of symmetric difference I fall in many cases. There is some way to test transitivity using only operations between sets. And with respect to the equivalence class of $S$, I showed that they are all subsets of $X$ contained in $S$. But with respect to the equivalence class of $X4 I do not see what it is.



Any help would be useful. Thank you!










share|cite|improve this question











$endgroup$




Let $A, B$ subsets of $X$ and $mathbb P(X)$ the power set,
we define the following equivalence relation on $mathbb P(X)$:



Let $ Ssubseteq X$ a fixed subset of $X$ and $A$~$B$ $iff A△B subseteq S$



Prove that is is an equivalence relation and find the class of $X$ and $S$



My work:



I have already shown that the relationship satisfies reflexivity and symmetry, all this is justified respectively by the fact that the empty set is a subset of any set and the symmetric difference is commutative.



My problem is with transitivity, I do not know how to do it, that is when I try to use it for the definition of symmetric difference I fall in many cases. There is some way to test transitivity using only operations between sets. And with respect to the equivalence class of $S$, I showed that they are all subsets of $X$ contained in $S$. But with respect to the equivalence class of $X4 I do not see what it is.



Any help would be useful. Thank you!







elementary-set-theory






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 2 hours ago







Hendrik Matamoros

















asked 2 hours ago









Hendrik MatamorosHendrik Matamoros

440310




440310











  • $begingroup$
    @EthanBolker You're right, my mistake!
    $endgroup$
    – Hendrik Matamoros
    2 hours ago
















  • $begingroup$
    @EthanBolker You're right, my mistake!
    $endgroup$
    – Hendrik Matamoros
    2 hours ago















$begingroup$
@EthanBolker You're right, my mistake!
$endgroup$
– Hendrik Matamoros
2 hours ago




$begingroup$
@EthanBolker You're right, my mistake!
$endgroup$
– Hendrik Matamoros
2 hours ago










4 Answers
4






active

oldest

votes


















1












$begingroup$

Two hints about ways to go.



  • Draw a Venn diagram for $A, B, C, X$ showing $A Delta B$ and so on.

  • Know or show that $Delta$ is associative. That and the fact that $B
    Delta B$
    is empty leads to an algebraic proof.





share|cite|improve this answer









$endgroup$












  • $begingroup$
    Oh, you're right! Thanks!
    $endgroup$
    – Hendrik Matamoros
    2 hours ago


















2












$begingroup$

We need to show theat $Asim B$ and $B sim C$ give $A sim C$. This can easily be seen by visualising $A, B, C$ in a Venn diagram (try it yourself!)
To put the Venn diagram proof formally, consider any element $x$ in $A$ but not in $C$. If $x$ is in $B$, it lies in the symmetric difference of $B$ and $C$ and so is in $S$. If $x$ is not in $B$, it lies in the symmetric difference of $A$ and $B$ and so is in $S$. By symmetry any element in $C$ but not $A$ is in $S$, completing the proof.






share|cite|improve this answer










New contributor



auscrypt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





$endgroup$




















    1












    $begingroup$

    If $A Delta B subseteq S$ and $B Delta C subseteq S$, then



    $A Delta C= (A Delta B) Delta (B Delta C) subseteq C$ as well.






    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      Must be, subset of $S$. Any help about the equivalence class of $X$?
      $endgroup$
      – Hendrik Matamoros
      2 hours ago


















    1












    $begingroup$

    Hint:



    By definition, $Asim B$ means $A-B$ and $B-Asubset S$. So you have to show that, if $A-B, B-A, B-C, C-Bsubset S$, then both $A-C$ and $C-A$ are subsets of $S$.



    Consider first an element $xin A-C$. Either it is in $B$, or it is not in $B$. What can you deduce from the hypotheses in each case?






    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      Thanks! My problem is now, what is the equivalence class of $X$?
      $endgroup$
      – Hendrik Matamoros
      2 hours ago










    • $begingroup$
      Well, it seems to be made up of the subsets of $X$ which contain $X-S$.
      $endgroup$
      – Bernard
      1 hour ago











    Your Answer








    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "69"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3237576%2fequivalence-relation-by-the-symmetric-difference-of-sets%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    4 Answers
    4






    active

    oldest

    votes








    4 Answers
    4






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1












    $begingroup$

    Two hints about ways to go.



    • Draw a Venn diagram for $A, B, C, X$ showing $A Delta B$ and so on.

    • Know or show that $Delta$ is associative. That and the fact that $B
      Delta B$
      is empty leads to an algebraic proof.





    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      Oh, you're right! Thanks!
      $endgroup$
      – Hendrik Matamoros
      2 hours ago















    1












    $begingroup$

    Two hints about ways to go.



    • Draw a Venn diagram for $A, B, C, X$ showing $A Delta B$ and so on.

    • Know or show that $Delta$ is associative. That and the fact that $B
      Delta B$
      is empty leads to an algebraic proof.





    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      Oh, you're right! Thanks!
      $endgroup$
      – Hendrik Matamoros
      2 hours ago













    1












    1








    1





    $begingroup$

    Two hints about ways to go.



    • Draw a Venn diagram for $A, B, C, X$ showing $A Delta B$ and so on.

    • Know or show that $Delta$ is associative. That and the fact that $B
      Delta B$
      is empty leads to an algebraic proof.





    share|cite|improve this answer









    $endgroup$



    Two hints about ways to go.



    • Draw a Venn diagram for $A, B, C, X$ showing $A Delta B$ and so on.

    • Know or show that $Delta$ is associative. That and the fact that $B
      Delta B$
      is empty leads to an algebraic proof.






    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered 2 hours ago









    Ethan BolkerEthan Bolker

    48.8k556125




    48.8k556125











    • $begingroup$
      Oh, you're right! Thanks!
      $endgroup$
      – Hendrik Matamoros
      2 hours ago
















    • $begingroup$
      Oh, you're right! Thanks!
      $endgroup$
      – Hendrik Matamoros
      2 hours ago















    $begingroup$
    Oh, you're right! Thanks!
    $endgroup$
    – Hendrik Matamoros
    2 hours ago




    $begingroup$
    Oh, you're right! Thanks!
    $endgroup$
    – Hendrik Matamoros
    2 hours ago











    2












    $begingroup$

    We need to show theat $Asim B$ and $B sim C$ give $A sim C$. This can easily be seen by visualising $A, B, C$ in a Venn diagram (try it yourself!)
    To put the Venn diagram proof formally, consider any element $x$ in $A$ but not in $C$. If $x$ is in $B$, it lies in the symmetric difference of $B$ and $C$ and so is in $S$. If $x$ is not in $B$, it lies in the symmetric difference of $A$ and $B$ and so is in $S$. By symmetry any element in $C$ but not $A$ is in $S$, completing the proof.






    share|cite|improve this answer










    New contributor



    auscrypt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





    $endgroup$

















      2












      $begingroup$

      We need to show theat $Asim B$ and $B sim C$ give $A sim C$. This can easily be seen by visualising $A, B, C$ in a Venn diagram (try it yourself!)
      To put the Venn diagram proof formally, consider any element $x$ in $A$ but not in $C$. If $x$ is in $B$, it lies in the symmetric difference of $B$ and $C$ and so is in $S$. If $x$ is not in $B$, it lies in the symmetric difference of $A$ and $B$ and so is in $S$. By symmetry any element in $C$ but not $A$ is in $S$, completing the proof.






      share|cite|improve this answer










      New contributor



      auscrypt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      $endgroup$















        2












        2








        2





        $begingroup$

        We need to show theat $Asim B$ and $B sim C$ give $A sim C$. This can easily be seen by visualising $A, B, C$ in a Venn diagram (try it yourself!)
        To put the Venn diagram proof formally, consider any element $x$ in $A$ but not in $C$. If $x$ is in $B$, it lies in the symmetric difference of $B$ and $C$ and so is in $S$. If $x$ is not in $B$, it lies in the symmetric difference of $A$ and $B$ and so is in $S$. By symmetry any element in $C$ but not $A$ is in $S$, completing the proof.






        share|cite|improve this answer










        New contributor



        auscrypt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





        $endgroup$



        We need to show theat $Asim B$ and $B sim C$ give $A sim C$. This can easily be seen by visualising $A, B, C$ in a Venn diagram (try it yourself!)
        To put the Venn diagram proof formally, consider any element $x$ in $A$ but not in $C$. If $x$ is in $B$, it lies in the symmetric difference of $B$ and $C$ and so is in $S$. If $x$ is not in $B$, it lies in the symmetric difference of $A$ and $B$ and so is in $S$. By symmetry any element in $C$ but not $A$ is in $S$, completing the proof.







        share|cite|improve this answer










        New contributor



        auscrypt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.








        share|cite|improve this answer



        share|cite|improve this answer








        edited 1 hour ago









        Bernard

        126k743120




        126k743120






        New contributor



        auscrypt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.








        answered 2 hours ago









        auscryptauscrypt

        1,3867




        1,3867




        New contributor



        auscrypt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.




        New contributor




        auscrypt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.























            1












            $begingroup$

            If $A Delta B subseteq S$ and $B Delta C subseteq S$, then



            $A Delta C= (A Delta B) Delta (B Delta C) subseteq C$ as well.






            share|cite|improve this answer









            $endgroup$












            • $begingroup$
              Must be, subset of $S$. Any help about the equivalence class of $X$?
              $endgroup$
              – Hendrik Matamoros
              2 hours ago















            1












            $begingroup$

            If $A Delta B subseteq S$ and $B Delta C subseteq S$, then



            $A Delta C= (A Delta B) Delta (B Delta C) subseteq C$ as well.






            share|cite|improve this answer









            $endgroup$












            • $begingroup$
              Must be, subset of $S$. Any help about the equivalence class of $X$?
              $endgroup$
              – Hendrik Matamoros
              2 hours ago













            1












            1








            1





            $begingroup$

            If $A Delta B subseteq S$ and $B Delta C subseteq S$, then



            $A Delta C= (A Delta B) Delta (B Delta C) subseteq C$ as well.






            share|cite|improve this answer









            $endgroup$



            If $A Delta B subseteq S$ and $B Delta C subseteq S$, then



            $A Delta C= (A Delta B) Delta (B Delta C) subseteq C$ as well.







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered 2 hours ago









            Henno BrandsmaHenno Brandsma

            120k351132




            120k351132











            • $begingroup$
              Must be, subset of $S$. Any help about the equivalence class of $X$?
              $endgroup$
              – Hendrik Matamoros
              2 hours ago
















            • $begingroup$
              Must be, subset of $S$. Any help about the equivalence class of $X$?
              $endgroup$
              – Hendrik Matamoros
              2 hours ago















            $begingroup$
            Must be, subset of $S$. Any help about the equivalence class of $X$?
            $endgroup$
            – Hendrik Matamoros
            2 hours ago




            $begingroup$
            Must be, subset of $S$. Any help about the equivalence class of $X$?
            $endgroup$
            – Hendrik Matamoros
            2 hours ago











            1












            $begingroup$

            Hint:



            By definition, $Asim B$ means $A-B$ and $B-Asubset S$. So you have to show that, if $A-B, B-A, B-C, C-Bsubset S$, then both $A-C$ and $C-A$ are subsets of $S$.



            Consider first an element $xin A-C$. Either it is in $B$, or it is not in $B$. What can you deduce from the hypotheses in each case?






            share|cite|improve this answer









            $endgroup$












            • $begingroup$
              Thanks! My problem is now, what is the equivalence class of $X$?
              $endgroup$
              – Hendrik Matamoros
              2 hours ago










            • $begingroup$
              Well, it seems to be made up of the subsets of $X$ which contain $X-S$.
              $endgroup$
              – Bernard
              1 hour ago















            1












            $begingroup$

            Hint:



            By definition, $Asim B$ means $A-B$ and $B-Asubset S$. So you have to show that, if $A-B, B-A, B-C, C-Bsubset S$, then both $A-C$ and $C-A$ are subsets of $S$.



            Consider first an element $xin A-C$. Either it is in $B$, or it is not in $B$. What can you deduce from the hypotheses in each case?






            share|cite|improve this answer









            $endgroup$












            • $begingroup$
              Thanks! My problem is now, what is the equivalence class of $X$?
              $endgroup$
              – Hendrik Matamoros
              2 hours ago










            • $begingroup$
              Well, it seems to be made up of the subsets of $X$ which contain $X-S$.
              $endgroup$
              – Bernard
              1 hour ago













            1












            1








            1





            $begingroup$

            Hint:



            By definition, $Asim B$ means $A-B$ and $B-Asubset S$. So you have to show that, if $A-B, B-A, B-C, C-Bsubset S$, then both $A-C$ and $C-A$ are subsets of $S$.



            Consider first an element $xin A-C$. Either it is in $B$, or it is not in $B$. What can you deduce from the hypotheses in each case?






            share|cite|improve this answer









            $endgroup$



            Hint:



            By definition, $Asim B$ means $A-B$ and $B-Asubset S$. So you have to show that, if $A-B, B-A, B-C, C-Bsubset S$, then both $A-C$ and $C-A$ are subsets of $S$.



            Consider first an element $xin A-C$. Either it is in $B$, or it is not in $B$. What can you deduce from the hypotheses in each case?







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered 2 hours ago









            BernardBernard

            126k743120




            126k743120











            • $begingroup$
              Thanks! My problem is now, what is the equivalence class of $X$?
              $endgroup$
              – Hendrik Matamoros
              2 hours ago










            • $begingroup$
              Well, it seems to be made up of the subsets of $X$ which contain $X-S$.
              $endgroup$
              – Bernard
              1 hour ago
















            • $begingroup$
              Thanks! My problem is now, what is the equivalence class of $X$?
              $endgroup$
              – Hendrik Matamoros
              2 hours ago










            • $begingroup$
              Well, it seems to be made up of the subsets of $X$ which contain $X-S$.
              $endgroup$
              – Bernard
              1 hour ago















            $begingroup$
            Thanks! My problem is now, what is the equivalence class of $X$?
            $endgroup$
            – Hendrik Matamoros
            2 hours ago




            $begingroup$
            Thanks! My problem is now, what is the equivalence class of $X$?
            $endgroup$
            – Hendrik Matamoros
            2 hours ago












            $begingroup$
            Well, it seems to be made up of the subsets of $X$ which contain $X-S$.
            $endgroup$
            – Bernard
            1 hour ago




            $begingroup$
            Well, it seems to be made up of the subsets of $X$ which contain $X-S$.
            $endgroup$
            – Bernard
            1 hour ago

















            draft saved

            draft discarded
















































            Thanks for contributing an answer to Mathematics Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3237576%2fequivalence-relation-by-the-symmetric-difference-of-sets%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Log på Navigationsmenu

            Creating second map without labels using QGIS?How to lock map labels for inset map in Print Composer?How to Force the Showing of Labels of a Vector File in QGISQGIS Valmiera, Labels only show for part of polygonsRemoving duplicate point labels in QGISLabeling every feature using QGIS?Show labels for point features outside map canvasAbbreviate Road Labels in QGIS only when requiredExporting map from composer in QGIS - text labels have moved in output?How to make sure labels in qgis turn up in layout map?Writing label expression with ArcMap and If then Statement?

            Nuuk Indholdsfortegnelse Etyomologi | Historie | Geografi | Transport og infrastruktur | Politik og administration | Uddannelsesinstitutioner | Kultur | Venskabsbyer | Noter | Eksterne henvisninger | Se også | Navigationsmenuwww.sermersooq.gl64°10′N 51°45′V / 64.167°N 51.750°V / 64.167; -51.75064°10′N 51°45′V / 64.167°N 51.750°V / 64.167; -51.750DMI - KlimanormalerSalmonsen, s. 850Grønlands Naturinstitut undersøger rensdyr i Akia og Maniitsoq foråret 2008Grønlands NaturinstitutNy vej til Qinngorput indviet i dagAntallet af biler i Nuuk må begrænsesNy taxacentral mødt med demonstrationKøreplan. Rute 1, 2 og 3SnescootersporNuukNord er for storSkoler i Kommuneqarfik SermersooqAtuarfik Samuel KleinschmidtKangillinguit AtuarfiatNuussuup AtuarfiaNuuk Internationale FriskoleIlinniarfissuaq, Grønlands SeminariumLedelseÅrsberetning for 2008Kunst og arkitekturÅrsberetning for 2008Julie om naturenNuuk KunstmuseumSilamiutGrønlands Nationalmuseum og ArkivStatistisk ÅrbogGrønlands LandsbibliotekStore koncerter på stribeVandhund nummer 1.000.000Kommuneqarfik Sermersooq – MalikForsidenVenskabsbyerLyngby-Taarbæk i GrønlandArctic Business NetworkWinter Cities 2008 i NuukDagligt opdaterede satellitbilleder fra NuukområdetKommuneqarfik Sermersooqs hjemmesideTurist i NuukGrønlands Statistiks databankGrønlands Hjemmestyres valgresultaterrrWorldCat124325457671310-5